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19 Jul 2024, 02:39
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Train A and Train B each departed simultaneously from Liverpool heading to London, which is 300 kilometers away. When Train A reached the destination, Train B still had 80 kilometers left to cover. What was Train A's average speed during this journey?
(1) During the first hour, Train B covered 40 kilometers less than Train A.
(2) Train B's average speed for the first 110 kilometers was 110 kilometers per hour.
C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked. => CORRECT
(1) Not Sufficient Alone
(2) Not Sufficient Alone
TOGETHER:
(2) Average Speed of Train B for the first 110 km = 110 km/h
(1) During the first hour, Train B covered 40 kilometers less than Train A => Average Speed of Train A during the first hour = 150 km/h
(1) During the first hour, Train B covered 40 kilometers less than Train A.
(2) Train B's average speed for the first 110 kilometers was 110 kilometers per hour.
C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked. => CORRECT
(1) Not Sufficient Alone
(2) Not Sufficient Alone
TOGETHER:
(2) Average Speed of Train B for the first 110 km = 110 km/h
(1) During the first hour, Train B covered 40 kilometers less than Train A => Average Speed of Train A during the first hour = 150 km/h
19 Jul 2024, 02:55
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From first statement, we can only deduce that Train A speed is 40km per hour more than train B speed. We cant calculate the average speed of train A during journey from this information
From second statement we are given train B average speed during first hour. This is not at all helpful for calculating the average speed of train A during journey
When we combined both statement , we can conclude that Train A journey during first hour is 150 km per hour but still we can tell anything about the speeds for the rest of journey for train A and B
Thus Both statements are not sufficient to provide the answer and E is our answer
From second statement we are given train B average speed during first hour. This is not at all helpful for calculating the average speed of train A during journey
When we combined both statement , we can conclude that Train A journey during first hour is 150 km per hour but still we can tell anything about the speeds for the rest of journey for train A and B
Thus Both statements are not sufficient to provide the answer and E is our answer
19 Jul 2024, 02:58
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Time taken for A to cover 300 km = t
Time taken for B to cover 220 km = t
Avg Speed of A = \(a_s\)
Avg Speed of B = \(b_s\)
\(300/a_s = 220/b_s\)
a_s = ?
Statement-1
Distance covered by Train A in first hour \(= d_a \)
Distance covered by Train B in first hour \(= d_b\)
\(d_a = d_b + 40\)
Do not know avg speed taken to cover \(d_a\) or \(d_b\).
Statement-1 not suff.
Statement-2
average speed for B in first 110 km = 110 km/hr
No mention of average speed for next 110 km
Statement-2 not suff
Combining state-1 and state-2
d_b = 110 as 110 km/hr speed for first 110
d_a = 150
a_s = 150 km/hr
State-1 and 2 suff together
C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.
Time taken for B to cover 220 km = t
Avg Speed of A = \(a_s\)
Avg Speed of B = \(b_s\)
\(300/a_s = 220/b_s\)
a_s = ?
Statement-1
Distance covered by Train A in first hour \(= d_a \)
Distance covered by Train B in first hour \(= d_b\)
\(d_a = d_b + 40\)
Do not know avg speed taken to cover \(d_a\) or \(d_b\).
Statement-1 not suff.
Statement-2
average speed for B in first 110 km = 110 km/hr
No mention of average speed for next 110 km
Statement-2 not suff
Combining state-1 and state-2
d_b = 110 as 110 km/hr speed for first 110
d_a = 150
a_s = 150 km/hr
State-1 and 2 suff together
C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.
19 Jul 2024, 03:21
Kudos
Bookmarks
We are asked to calculate the Train A's average speed for the whole journey.
Let's Sa and Sb are the Train A's average speed for the whole journey and Train B's average speed for the whole journey.
Then, we can infer the below
Speed (in km/h) distance (in km) time (in h)
Train A Sa 300 t
Train B Sb 220 t
We get that
\(\frac{300}{Sa }=\frac{220}{Sb}\)
\(\frac{Sb}{Sa} = \frac{11}{15}\)
If we calcualte the average speed of train B, then we can calculate the Average speed of Train A for the whole journey.
From statement 1,
let's say, in the first hour, train A covered 150 km then train B covered 110 km, and the distance that train A covered by end of 2 hours is 300km.
1 hr 2hr
A 150km 300km
B 110km 220km
Sa = 300/2 = 150 km/hr
Let's say, in the first hour, train A covered 50 km then train B covered 10 km.
1 hr 2hr 3hr 4hr 5hr 6hr
A 50km 100km 150km 200km 250km 300km
B 10km 52km ...............................................220km
Sa = 300/6 = 50 km/hr
We get different values of Train A average speed. Therefore, Statement A alone is not sufficient.
From statement 2,
Similar to Statement 1, we will get different values of Train A average speed because we are given only Train B's average speed for the first 110 kilometers was 110 kilometers per hour. For the rest of the distance, the speeds can vary and therefore the Train A average speed can vary.
Same example applies when combined both the statements.
The right ans is E
Let's Sa and Sb are the Train A's average speed for the whole journey and Train B's average speed for the whole journey.
Then, we can infer the below
Speed (in km/h) distance (in km) time (in h)
Train A Sa 300 t
Train B Sb 220 t
We get that
\(\frac{300}{Sa }=\frac{220}{Sb}\)
\(\frac{Sb}{Sa} = \frac{11}{15}\)
If we calcualte the average speed of train B, then we can calculate the Average speed of Train A for the whole journey.
From statement 1,
let's say, in the first hour, train A covered 150 km then train B covered 110 km, and the distance that train A covered by end of 2 hours is 300km.
1 hr 2hr
A 150km 300km
B 110km 220km
Sa = 300/2 = 150 km/hr
Let's say, in the first hour, train A covered 50 km then train B covered 10 km.
1 hr 2hr 3hr 4hr 5hr 6hr
A 50km 100km 150km 200km 250km 300km
B 10km 52km ...............................................220km
Sa = 300/6 = 50 km/hr
We get different values of Train A average speed. Therefore, Statement A alone is not sufficient.
From statement 2,
Similar to Statement 1, we will get different values of Train A average speed because we are given only Train B's average speed for the first 110 kilometers was 110 kilometers per hour. For the rest of the distance, the speeds can vary and therefore the Train A average speed can vary.
Same example applies when combined both the statements.
The right ans is E
