We are asked to calculate the Train A's average speed for the whole journey.
Let's Sa and Sb are the Train A's average speed for the whole journey and Train B's average speed for the whole journey.
Then, we can infer the below
Speed (in km/h) distance (in km) time (in h)
Train A Sa 300 t
Train B Sb 220 t
We get that
\(\frac{300}{Sa }=\frac{220}{Sb}\)
\(\frac{Sb}{Sa} = \frac{11}{15}\)
If we calcualte the average speed of train B, then we can calculate the Average speed of Train A for the whole journey.
From statement 1,
let's say, in the first hour, train A covered 150 km then train B covered 110 km, and the distance that train A covered by end of 2 hours is 300km.
1 hr 2hr
A 150km 300km
B 110km 220km
Sa = 300/2 = 150 km/hr
Let's say, in the first hour, train A covered 50 km then train B covered 10 km.
1 hr 2hr 3hr 4hr 5hr 6hr
A 50km 100km 150km 200km 250km 300km
B 10km 52km ...............................................220km
Sa = 300/6 = 50 km/hr
We get different values of Train A average speed. Therefore, Statement A alone is not sufficient.
From statement 2,
Similar to Statement 1, we will get different values of Train A average speed because we are given only Train B's average speed for the first 110 kilometers was 110 kilometers per hour. For the rest of the distance, the speeds can vary and therefore the Train A average speed can vary.
Same example applies when combined both the statements.
The right ans is E