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Praveena_10
02 Jul 2025, 20:32
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H:S:A=5:6:11
Statement-1:
This tells all the Hiking i.e 5x students are in in archery but it doesn’t tell us how many Archery students are in Swimming, so we cannot find the fraction of Archery students who are in Swimming.
Statement-2:
It tells all the archery Students are enrolled in any one other course. But it also doesn't tell us how many Students are there in Swimming.
Both statements combined:
In 11k Students from archery 5x students enrolled to hiking so the rest will be enrolled in swimming i.e, 11x-5x=6x
Ratio= 6x/11x=6/11
Statement-1:
This tells all the Hiking i.e 5x students are in in archery but it doesn’t tell us how many Archery students are in Swimming, so we cannot find the fraction of Archery students who are in Swimming.
Statement-2:
It tells all the archery Students are enrolled in any one other course. But it also doesn't tell us how many Students are there in Swimming.
Both statements combined:
In 11k Students from archery 5x students enrolled to hiking so the rest will be enrolled in swimming i.e, 11x-5x=6x
Ratio= 6x/11x=6/11
02 Jul 2025, 21:18
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Based on the statement we got the percentage of student enrolled in three groups. Now coming to the question, among those enrolled in archery, what fraction are also enrolled in swimming, we will look at both statements.
From statement 1, if 5 students from hiking are enrolled in archery also there are two possiblities- one is the 6 from swimming are enrolled in archery which makes the total 11 or they are not enrolled which makes only archery 6.
If we look at second statement every student enrolled in archery is enrolled in atleast one other so there is only one possiblity that from 11 students, 6 are in swimming and 5 are on hiking. There is no other possiblity as overlap will occur and all conditions will not be satisfied. So it can be answered by 2nd but not 1st.
From statement 1, if 5 students from hiking are enrolled in archery also there are two possiblities- one is the 6 from swimming are enrolled in archery which makes the total 11 or they are not enrolled which makes only archery 6.
If we look at second statement every student enrolled in archery is enrolled in atleast one other so there is only one possiblity that from 11 students, 6 are in swimming and 5 are on hiking. There is no other possiblity as overlap will occur and all conditions will not be satisfied. So it can be answered by 2nd but not 1st.
Bunuel
02 Jul 2025, 21:19
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For every 5 students in Hiking, there are 6 in Swimming and 11 in Archery
We have to find for students in Archery How many are enrolled in Swimming so that ration can be obtained
So lets say 5x students are enrolled in Hiking
Then 6x students are in swimming & 11x students in Archery are enrolled
Statement 1
All students enrolled in Hiking are also enrolled in Archery.
Hiking = 5x students
so 11x students also have 5x students. So remaining students are 6x but we don't know whether they are enrolled in swimming or not.
So statement is insufficient.
Statement 2
Every student enrolled in Archery is also enrolled in at least one other group.
Students enrolled in Archery = 11x
all 11x are enrolled in either swimming or hiking. But we don't know how many are in hiking & how many in swimming.
So statement is again insufficient.
Lets combine both statements
From paragraph & statement 1 we know 11x students are in Archery & 5x ae in Hiking
So 6X are remaining
from statement 2 we know that complete 11x is enrolled in Hiking & swimming
Hiking has 5x students so automatically remaining students i.e 6x are enrolled in swimming.
So ration is 6x/11x of students enrolled in swimming of total students in Archery.
Answer is C. Both statements combined are sufficient.
We have to find for students in Archery How many are enrolled in Swimming so that ration can be obtained
So lets say 5x students are enrolled in Hiking
Then 6x students are in swimming & 11x students in Archery are enrolled
Statement 1
All students enrolled in Hiking are also enrolled in Archery.
Hiking = 5x students
so 11x students also have 5x students. So remaining students are 6x but we don't know whether they are enrolled in swimming or not.
So statement is insufficient.
Statement 2
Every student enrolled in Archery is also enrolled in at least one other group.
Students enrolled in Archery = 11x
all 11x are enrolled in either swimming or hiking. But we don't know how many are in hiking & how many in swimming.
So statement is again insufficient.
Lets combine both statements
From paragraph & statement 1 we know 11x students are in Archery & 5x ae in Hiking
So 6X are remaining
from statement 2 we know that complete 11x is enrolled in Hiking & swimming
Hiking has 5x students so automatically remaining students i.e 6x are enrolled in swimming.
So ration is 6x/11x of students enrolled in swimming of total students in Archery.
Answer is C. Both statements combined are sufficient.
