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Let's say the number is in the format (a^x) (b^y) (c^z) (d^t)...
The min number of prime factors is 1. This means the number is in the format of a^23

The max number of prime factors is 4. This means the number is in the format of (a^2)(b^1)(c^1)(d^1)

The range = 4-1 = 3

Answer: C
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The number of distinct factors are found by adding 1 to the exponent of each unique prime factor and multiplying the results. Of course, there is no need to test whether the maximum is 1 as all composite numbers are products of prime factors. I'll also test using the easiest PFs to make my life easier.

2 UPFs: 2 x 3 -> if either exponent is 5 and the other 3, then we get (5+1)x(3+1)=24
3 UPFs: 2 x 3 x 5 -> if either exponent is 1, 2, and 3, then we get (1+1)x(2+1)x(3+4)=24
4 UPFs: 2 x 3 x 5 x 7 -> if either exponent is 1,1,1 and 2, then we get (1+1)x...=24

Now I notice how to distribute the product of 24 across 4 factors, I can't have more 'terms' than 2 x 2 x 2 x 3 , the prime factorisation of 24.

Answer: D) 4
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Bunuel
If a positive integer n has 24 positive factors, what is the maximum possible range in the number of distinct prime factors that n can have?

A. 1
B. 2
C. 3
D. 4
E. 5


 


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N = p1^n1 * p2^n2 * p3^n3 ...

n = (n1+1)*(n2+1)*(n3+1) ..

and p1, p2, p3 are prime

For this question

N = p1^23

Least number of prime = 1

N = p1^1 * p2^1 * p3^1 * p4^2

Max number of prime = 4

Range = 4 - 1 = 3

Option C
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Any positive integer n can be written as:

n=p1^e1.p2^e2.... so on, where p1 and p2 are prime numbers and e1,e2 are their exponents.

Number of factors are given by:
(e1+1)(e2+1)...(ek+1)=24

  • Minimum number of primes k: If k=1, then e1+1=24, so e1=23 (which is prime).
  • Maximum k: To maximize k, write 24 as a product of as many factors ≥ 2 as possible:
    24=2×2×2×3. That means k=4 primes with exponents (1,1,1,2)
So k can be from 1 to 4. Hence, Range will be 4-1 =3

C) 3
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Seems straightforward, should be C

The minimum is 1 prime number and the maximum is 4 prime numbers(a^2*b*c*d) which would give 24 factors - 3*2*2*2=24

Thus range is 4-3=1
Bunuel
If a positive integer n has 24 positive factors, what is the maximum possible range in the number of distinct prime factors that n can have?

A. 1
B. 2
C. 3
D. 4
E. 5


 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 

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Positive factors by prime numbers
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n = a^p * b^m *... where a, b and so on are prime factors and p, m etc are exponents
The number of factors of n is calculated as (p+1) *(m+1) and so on....

Looking at factors of 24, we have different scenarios
1,24 => (23+1) => p = 23; n could be a^23 there could be just 1 prime number
2,12 => (1+1)*(11+1) => p = 1 and m=10 ; n could be a * b^11
...
2*2*2*3 = > (1+1)*(1+1)*(1+1)*(2+1) there could be 4 prime numbers

Range = 4-1 = 3
Bunuel
If a positive integer n has 24 positive factors, what is the maximum possible range in the number of distinct prime factors that n can have?

A. 1
B. 2
C. 3
D. 4
E. 5


 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 

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Number of factors= (P^x)+(P2^y)+(P3^z)+.......
Number of factors=24
24=(x+1)*(y+1)*(z+1).......
We need maximum number of primes in this
24=(1*24),(1*2*12),(1*2*3*4),(1*2*2*2*3),(1*2*2*6),(1*3*8),(1*4*6)
Highest we have (2*2*2*3) means 3 prime number with power 1 and 1 prime number with power 2. We have maximum 4 distinct primes and atleast 1 prime,
maximum possible range in the number of distinct prime factors that n can have= 4-1=3

C
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We are given that an integer 'n' has 24 positive factors

Note that we are provided the total number of 'factors' and not 'prime factors'.

So for the integer 'n' to have total positive factors as 24,

In the prime factorized form of 'n' expressed as:
\( P1^a P2^b P3^c P4^d .... \)
Where P1 , P2, P3 are prime numbers and a,b,c... are positive integers

The total number of positive factors:
24 = (a+1) * (b+1) * (c +1) ... and so on

We need to determine the maximum possible range in the number of distinct prime factors that n can have.

The least number of distinct prime factors can be determined by expressing 24 as:
24 = (23 +1)

where 23 is the exponent of any single prime factor that 'n' is composed of

so n could be \( 2^23, or 5^23 or 13^23 \)

All these terms, having only one distinct prime factor would give a total number of positive factors as 23 + 1 = 24.

Similarly, the maximum number of distinct prime factors can be determined by expressing 24 as:
24 = 2 * 2 * 2 * 3
24 = (1+1) * (1+1) * (1+1) * (2+1)

Here, we have 24 expressed as a product of four different terms, which means that the maximum number of distinct prime factors that n could have is 4.


Thus, the maximum possible range of prime factors is 4 - 1 = 3.

Note:
24 can be expressed as
(7 +1 ) * (2 +1), giving us only two distinct prime factors for example \( n = 19^7 * 23^2 \)
or
(1+1) * (3 + 1 ) * (2 +1), giving us only three distinct prime factors. but the question asks us to maximize the range, so we need to express n as product of maximum number of terms.
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To calculate number of factors for a number we can prime factorize the number, add 1 to the powers of the exponent portion of the prime factors and multiply it to get the number of factors.
E.g. 48 => 2^4 * 3^1
No. of factors = (4+1) * (1+1) = 10

To get the most number of distinct prime factors, if we are to use the above logic, they will have a power of 1, and we will add 1 to the power and multiply it. Therefore we will get the number of factors to lie in between 2^m and 2^(m+1). Where m is the number of distinct prime factors.

Therefore, 24 lies in between 16 (2^4) and 32 (2^5). We can conclude that the maximum number of distinct prime factors for a number which has 24 factors is 4.

Hence, Answer D

Note: For a number which has 5 distinct prime factors, that number will have a minimum of 32 factors.
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Factors of 24: 2^3 and 3
Distinct prime factors are 2 and 3
Range: 3-2 = 1
Bunuel
If a positive integer n has 24 positive factors, what is the maximum possible range in the number of distinct prime factors that n can have?

A. 1
B. 2
C. 3
D. 4
E. 5


 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

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Given positive integer n has 24 factors.
Minimum no of prime numbers = 1 ( let p be a prime number: \( n = p^2^3 \) Total number of factors = (23 + 1) )
Maximum no of prime numbers = 4 ( \(p^1* q^1* r^1* s^2\), no of factors = \((1+1)*(1+1)*(1+1)*(2+1) = (2)*(2)*(2)*(3) = 24\))
Hence maximum possible range of distinct prime factors= 4-1= 3
Option C.
Bunuel
If a positive integer n has 24 positive factors, what is the maximum possible range in the number of distinct prime factors that n can have?

A. 1
B. 2
C. 3
D. 4
E. 5


 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

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Suppose: N = (p^a) (q^b) (r^c) (s^d) and N has 24 positive factors, then:

(a+1)(b+1)(c+1)(d+1) = 24

What is asked? "what is the maximum possible range in the number of distinct prime factors that n can have"
It is #max. - #min (number of distintic prime factors)

#max depends in how long can I express 24 in their factors, 24 = 2x2x2x3, (p^1)(q^1)(r^1)(s^2), so 4 different prime factors as max.
# min will be 1, represented by p^23
So the range will be 4-1 = 3
Answer is C
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n has 24 factors,s so we can write n in factorization form
n = a^x b^y....
no. of factor = (x+1)(y+1).....
For the minimum no. of factors, if a has a power of 23, then (23+1) = 24
Minimum value = 1

(x+1)(y+1).. in this we can only have positive powers and minimum is 1, then for maximum we can break 24 into = 2*2*2*3 = (x+1)(y+1)(z+1)(w+1)
Then the Maximum no. of primes is 4

Range = 4 - 1 = 3
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no of factors = (prime factor power +1) .......... Number of prime factors. So now for minimum it's (23 +1) (that is 1 prime factor ) and max = 4 (2*2*2*3)
Bunuel
If a positive integer n has 24 positive factors, what is the maximum possible range in the number of distinct prime factors that n can have?

A. 1
B. 2
C. 3
D. 4
E. 5


 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

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Bunuel
If a positive integer n has 24 positive factors, what is the maximum possible range in the number of distinct prime factors that n can have?

A. 1
B. 2
C. 3
D. 4
E. 5


 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 

Maximum possible range = Maximum distinct prime factors - Minimum distinct prime factors.
The minimum distinct prime factor is always 1. (as long as n has more than 1 positive factors)
The maximum distinct prime factors of n is as much as many small prime factors of 24: 24 = 2*2*2*3 => Total 4 distinct prime factors

=> Maximum range = 4 - 1 = 3

Answer: (C) 3
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Option C is the correct answer.

First of all we need to understand the meaning of the question to properly answer it. So here the question is basically asking us the maximum possible range of the number of distinct prime factors of n which would mean that range of number of distinct prime factors which the number n can have.

Lets understand this with an example of similar kind so that we can proper understand what exactly the question is asking of us.

Example:
Question: Let say their is a positive integer x which has 4 positive factors, then what is the maximum possible range in the number of distinct prime factors that x can have?
Answer: Since we know the formula to calculate the total factors of a number is to just add (+1) to the maximum power of each distinct prime number that is the factor of that number and multiply all of them. example: the number 6 has two prime factors 2&3 and both have a maximum power of 1-1 each so to calculate total number of factors we will do (1+1)*(1+1) which will be equal to 4 factors. Now lets get back to the example question which we were solving.
So, as we know that x has 4 positive factors so we can get 4 by the two ways: (0+1)*(3+1) = 4, (1+1)*(1+1) = 4. And from here we get to know that x can have either only one prime number or two prime numbers atmost.
Now to answer the think which question asked we just need to do: 2-1 = 1 which will be the maximum possible range in the number of distinct prime factors that x can have.


Similarly we need to answer this question as well. It tells us that n is a positive number which have 24 factors.

First Case: Only one prime number - (0+1)*(23+1) = 24
Second Case: Two prime numbers - (1+1)*(11+1) = 24, (2+1)*(7+1) = 24 or (3+1)*(5+1) = 24
Third Case: Three prime numbers: (1+1)*(1+1)*(5+1) = 24 or (1+1)*(2+1)*(3+1) = 24
Fourth Case: Four prime numbers: (2+1)*(1+1)*(1+1)*(1+1) = 24

Now we cannot have more than these four cases so the maximum possible range of the number of distinct prime factors of n will be: 4-1 = 3



Bunuel
If a positive integer n has 24 positive factors, what is the maximum possible range in the number of distinct prime factors that n can have?

A. 1
B. 2
C. 3
D. 4
E. 5


 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 

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