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Reference Question 1


If x, y, and z are positive integers, where x is an odd number and \(z = x^2 + y^2 + 4\). Is \(y^2\) divisible by 4?
    I. z = 8k - 3 where k is a positive integer
    II. (z - x + 1) = 2q + 1, where q is a positive integer

Solution


Steps 1 & 2: Understand Question and Draw Inferences
We are given that
    • x, y and z are positive integers.
    • Also, x is odd
    • And, \(z= x^2 + y^2 + 4\)

By rearranging the terms, we get:
    \(y^2 = z – x^2 – 4\) …………. (1)

The question asks us whether \(y^2\) is divisible by 4 or not. If y is divisible by 2, then \(y^2\) will be divisible by 4; else it will not be.
And if y is divisible by 2, this means that y is even.
    • Thus, the question is indirectly asking us: is y even?
y will be even if the right-hand side of Equation 1 is even. So, let’s analyze the condition in which this will be so.

Now, we are given that x is an odd number. This means that \(x^2\) is also odd (Odd * Odd = Odd)
So, in the part \((x^2 – 4)\), we are subtracting an even number from an odd number. Think of what happens when we subtract 4 from 9. We get 5, which is an odd number. So, here too, the result of subtracting 4 from \(x^2\) will be an Odd number (Please note that the result may be positive or negative. We are not concerned with that. All that we want to know is whether the result will be even or odd)

So, from Equation 1 we get:
    • \(y^2\) = z – Odd number . . . (2)

Now,
    • Even +/- Odd = Odd (Think: 4 + 1 = 5)
    • And, Odd +/- Odd = Even (Think: 3 + 1 = 4)

Thus, from equation (2),
It is clear that \(y^2\) will be even only if z is an odd number
    • y will be even only if z is an odd number
Our task is to determine if z is odd or not.

Step 3: Analyze Statement 1
Statement (1) says: z = 8 * k – 3

Now, irrespective of whether k is even or odd,
    • 8 * k = even number
    • 8k – 3 = Even number - odd number = Odd Number (Think: 8 – 3 = 5)

So, the analysis of statement (1) tells us that z is an odd number.
Since we have been able to determine that z is an odd number, this means that y is an even number.
Thus, Statement (1) alone is sufficient to answer the question: is y even?

Step 4: Analyze Statement 2
Statement (2) says: (z - x + 1) = 2q + 1, where q is a positive integer
    • 2q+1 = odd
    Hence, z – x + 1 = odd
    z – x = Odd – 1 = Odd – Odd = Even
    So, z = x + Even number
    z = Odd + Even = Odd
Thus, z is an odd number

Hence, y is an even number
Thus, Statement 2 alone is sufficient to answer the question: is y even?

Step 5: Analyze Both Statements Together (if needed)
Since we got unique answers in step 3 and 4, so this step is not required

Answer: D
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Reference Question 2


The number x is a positive odd integer. If the unit digit of \(x^3\) is subtracted from the unit digit of \(x^2\), it results in 0. What is the unit digit of the number x + 7?
    I. The unit digit of the product of 105 and x is 5.
    II. When x is divided by 5, it leaves no remainder.

Solution


Steps 1 & 2: Understand Question and Draw Inferences
We are given that
    • x is a positive odd number.
    • Also, (The unit digit of \(x^2\)) – (the unit digit of \(x^3\)) = 0
      o This implies, the unit digits of \(x^2\) and \(x^3\) are same.

So, we know two things about the number x:
    • It’s an odd number.
    • The cyclicity of the unit digit of x is 1 since the unit digits of \(x^2\) and \(x^3\) are same.

Now, in odd numbers, we know that the cyclicity of only 1 and 5 is 1. So, the unit digit of x is either 1 or 5.
    • So, we have to find whether the unit digit of x is 1 or 5.
      o Because once we get to know the unit digit of x, we can add 7 to it and find the unit digit of x + 7.

Step 3: Analyze Statement 1
Statement 1 says: The unit digit of the product of 105 and x is 5.

Now, we know that the unit digit of the product of 105 and x will be the product of the unit digit of 105 and the unit digit of x.
The unit digit of 105 is 5, and the unit digit of x is either 1 or 5. So, let’s consider both the cases:

Case 1: The unit digit of x is 1.
    • So, the unit digit of 105x = 5*1 = 5
Thus, if the unit digit of x is 1, the unit digit of 105x will be 5.

Case 2: The unit digit of x is 5.
    • So, the unit digit of 105x = 5 * 5 = The unit digit of 25 = 5
Thus, if the unit digit of x is 5, the unit digit of 105x will be 5.

So, we can’t determine the unit digit of x from this statement.
Hence, statement (1) is not sufficient to answer the question: What is the unit digit of x + 7?

Step 4: Analyze Statement 2
Statement 2 says: When x is divided by 5, it leaves no remainder.

Now, we know that the multiple of 5 can only have 0 or 5 at the units place. Also, x is an odd number.
    • So, \(\frac{x}{5}\) will not leave any remainder only if the unit digit of x is 5.
So, we know that the unit digit of x is 5.

Now, since we know the unit digit of x we can find the unit digit of x + 7.
So, statement (2) alone is sufficient to answer the question: What is the unit digit of x + 7?

Step 5: Analyze Both Statements Together (if needed)
Since statement (2) alone is sufficient to answer the question, we don’t need to perform this step.

Answer: B
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Hi, Can you share part 2 articles?
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Hey calculusbro,

We have not posted the second article yet.
We will surely notify you once we post the next article.

Till then, you read more of our articles by checking this link: https://gmatclub.com/forum/e-gmat-quant ... l#p1525390

Regards,
Ashutosh
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Hey calculusbro,

We have not posted the second article yet.
We will surely notify you once we post the next article.

Till then, you can read more of our articles by checking this link: https://gmatclub.com/forum/e-gmat-quant ... l#p1525390

Regards,
Ashutosh
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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