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28 Mar 2009, 02:56
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
50% (02:30) correct
50%
(00:52)
wrong
based on 14
sessions
History
Date
Time
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Not Attempted Yet
Pls explain ur answer
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01 Apr 2009, 21:48
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Ok I got screwed :
The mean is 12,000 and there are 11 towns. The town with the least population will have 10% less than the town with the next highest population and so on.
So if there are a,b,c,d,e,f,g,h.i,j,k in the increasing order : b = 11/10a, c = 11/10 (b) = 11^2/10^2 (a) .. so k =11^10/10^10 * (a)
I guess f would be the mean = 12,000 and f = 11^4/10^4 a. Now substitute the answer choices.
Using approximation : 10,700 kinda fits the bill. I spent about 4 minutes and got the wrong answer I guess.
Any other better approaches please.
-pradeep
The mean is 12,000 and there are 11 towns. The town with the least population will have 10% less than the town with the next highest population and so on.
So if there are a,b,c,d,e,f,g,h.i,j,k in the increasing order : b = 11/10a, c = 11/10 (b) = 11^2/10^2 (a) .. so k =11^10/10^10 * (a)
I guess f would be the mean = 12,000 and f = 11^4/10^4 a. Now substitute the answer choices.
Using approximation : 10,700 kinda fits the bill. I spent about 4 minutes and got the wrong answer I guess.
Any other better approaches please.
-pradeep
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THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.
If you would like to discuss this question please re-post it in the respective forum. Thank you!
To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
