GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 24 May 2019, 14:05

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# GMATPREP- population

Author Message
VP
Joined: 18 May 2008
Posts: 1062

### Show Tags

28 Mar 2009, 02:56
00:00

Difficulty:

(N/A)

Question Stats:

50% (02:30) correct 50% (00:52) wrong based on 14 sessions

### HideShow timer Statistics

--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

Attachments

population.JPG [ 59.88 KiB | Viewed 3520 times ]

Senior Manager
Joined: 01 Mar 2009
Posts: 338
Location: PDX

### Show Tags

01 Apr 2009, 21:48
Ok I got screwed :

The mean is 12,000 and there are 11 towns. The town with the least population will have 10% less than the town with the next highest population and so on.

So if there are a,b,c,d,e,f,g,h.i,j,k in the increasing order : b = 11/10a, c = 11/10 (b) = 11^2/10^2 (a) .. so k =11^10/10^10 * (a)

I guess f would be the mean = 12,000 and f = 11^4/10^4 a. Now substitute the answer choices.

Using approximation : 10,700 kinda fits the bill. I spent about 4 minutes and got the wrong answer I guess.

--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

_________________
In the land of the night, the chariot of the sun is drawn by the grateful dead
Current Student
Joined: 13 Jan 2009
Posts: 311
Location: India

### Show Tags

02 Apr 2009, 15:16
1
Lets assume minimum be x, so next maximum be 1.1x

x+1.1x*10=132K
12x=132k
x=11k
Intern
Joined: 29 Dec 2006
Posts: 30

### Show Tags

15 Apr 2009, 00:54
i got b... what's the correct answer?
Manager
Joined: 08 Feb 2009
Posts: 136
Schools: Anderson

### Show Tags

15 Apr 2009, 06:44
I think C (10,900) is the correct answer.

Using backward substitution, if we take the minimum possible population to be 10,900. (As "C" is considered a better answer choice to start the backward substitution with.)
Then, the remaining population 121100 is left to be divided among 10 districts.
Dividing equally, we get 12110.
Checking our answer: 12110-1211 = 10,900 (approximately) (10,899 to be exact).

This took about 3 minutes to solve. But much of the time was used to figure out the approach. The calculation involved isn't a lot, although it seems to be.
Intern
Joined: 09 Apr 2009
Posts: 7

### Show Tags

15 Apr 2009, 12:01

10900 would mean the max for the others is 11990. Multiply by 10 and add 10900 and you have with 130800 people, so not everyone has been divided into a district.

10*11k*1.1 = 121000
+ 11k = 132k
Manager
Joined: 10 Jul 2009
Posts: 102
Location: Ukraine, Kyiv

### Show Tags

19 Sep 2009, 06:35
D. Backsolving is the best and fastest way to do it. Choose answer C as the median number here (answer choices are sorted in ascending order). When solve it, we see that it is insufficient, because the result is lower than 132000, thus take next ,bigger, choice. Here's how I did it.
Attachments

population.xls [7 KiB]

_________________
Never, never, never give up
Manager
Joined: 11 Sep 2009
Posts: 70

### Show Tags

24 Oct 2009, 01:10
Let's X be the least population city
For x to be the minimum, each of other city should reach the maximum and all are equal in number

10(1.1X) + X = 132000

X = 11000

Cheers
Non-Human User
Joined: 09 Sep 2013
Posts: 11013

### Show Tags

16 Jul 2017, 12:19
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.

--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

_________________
Re: GMATPREP- population   [#permalink] 16 Jul 2017, 12:19
Display posts from previous: Sort by