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GMATPREP- population

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VP
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GMATPREP- population  [#permalink]

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New post 28 Mar 2009, 02:56
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

50% (02:30) correct 50% (00:52) wrong based on 14 sessions

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Pls explain ur answer

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Re: GMATPREP- population  [#permalink]

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New post 01 Apr 2009, 21:48
Ok I got screwed :

The mean is 12,000 and there are 11 towns. The town with the least population will have 10% less than the town with the next highest population and so on.

So if there are a,b,c,d,e,f,g,h.i,j,k in the increasing order : b = 11/10a, c = 11/10 (b) = 11^2/10^2 (a) .. so k =11^10/10^10 * (a)

I guess f would be the mean = 12,000 and f = 11^4/10^4 a. Now substitute the answer choices.

Using approximation : 10,700 kinda fits the bill. I spent about 4 minutes and got the wrong answer I guess.

Any other better approaches please.

-pradeep

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Re: GMATPREP- population  [#permalink]

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New post 02 Apr 2009, 15:16
1
Lets assume minimum be x, so next maximum be 1.1x


x+1.1x*10=132K
12x=132k
x=11k
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Re: GMATPREP- population  [#permalink]

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New post 15 Apr 2009, 00:54
i got b... what's the correct answer?
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Re: GMATPREP- population  [#permalink]

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New post 15 Apr 2009, 06:44
I think C (10,900) is the correct answer.

Using backward substitution, if we take the minimum possible population to be 10,900. (As "C" is considered a better answer choice to start the backward substitution with.)
Then, the remaining population 121100 is left to be divided among 10 districts.
Dividing equally, we get 12110.
Checking our answer: 12110-1211 = 10,900 (approximately) (10,899 to be exact).

Thus C is the answer.


This took about 3 minutes to solve. But much of the time was used to figure out the approach. The calculation involved isn't a lot, although it seems to be.
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Re: GMATPREP- population  [#permalink]

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New post 15 Apr 2009, 12:01
The answer is D.

10900 would mean the max for the others is 11990. Multiply by 10 and add 10900 and you have with 130800 people, so not everyone has been divided into a district.

10*11k*1.1 = 121000
+ 11k = 132k
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Re: GMATPREP- population  [#permalink]

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New post 19 Sep 2009, 06:35
D. Backsolving is the best and fastest way to do it. Choose answer C as the median number here (answer choices are sorted in ascending order). When solve it, we see that it is insufficient, because the result is lower than 132000, thus take next ,bigger, choice. Here's how I did it.
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Re: GMATPREP- population  [#permalink]

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New post 24 Oct 2009, 01:10
Let's X be the least population city
For x to be the minimum, each of other city should reach the maximum and all are equal in number

10(1.1X) + X = 132000

X = 11000

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Re: GMATPREP- population  [#permalink]

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Re: GMATPREP- population   [#permalink] 16 Jul 2017, 12:19
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