Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 26 May 2017, 16:58

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# How many divisors of 1728 are also mutiples of 6

Author Message
Senior Manager
Joined: 22 Aug 2003
Posts: 257
Location: Bangalore
Followers: 1

Kudos [?]: 13 [0], given: 0

How many divisors of 1728 are also mutiples of 6 [#permalink]

### Show Tags

27 Sep 2003, 08:24
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

How many divisors of 1728 are also mutiples of 6.
SVP
Joined: 03 Feb 2003
Posts: 1604
Followers: 9

Kudos [?]: 268 [0], given: 0

### Show Tags

27 Sep 2003, 08:49
1728=[2^6][3^3]

(I) they should have at least one 2 and at least one 3.
therefore, 6*3=18, since the question does not say whether divisors are positive, we have to allow for negative divisors. 18*2=36

(II) or another way

(1) [3^1][2, or 2^2, or 2^3 ... 2^6] 6 numbers
(2) [3^2][2, or 2^2, or 2^3 ... 2^6] 6 numbers
(3) [3^3][2, or 2^2, or 2^3 ... 2^6] 6 numbers

total 18 numbers. With negatives:36

(III) or yet another way
1728=[2^6][3^3], there are 7*4=28 positive divisors overall. The divisors that are not multiples of 6 are: 1, 2, 4, 8, 16, 32, 64, 3, 9, and 27. 28-10=18. 18*2=36
27 Sep 2003, 08:49
Display posts from previous: Sort by