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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
42% (02:25) correct
58%
(02:22)
wrong
based on 412
sessions
History
Date
Time
Result
Not Attempted Yet
How many prime numbers n exist such that 90 < n < 106 and n is a factor of 99999919?
A. Zero
B. One
C. Two
D. Three
E. More than three
A. Zero
B. One
C. Two
D. Three
E. More than three
11 Jun 2013, 05:45
Kudos
Bookmarks
emmak
How many prime numbers n exist such that 90 < n < 106 and n is a factor of 99999919?
A. Zero
B. One
C. Two
D. Three
E. More than three
A. Zero
B. One
C. Two
D. Three
E. More than three
There are 3 primes in the range: 97, 101 and 103.
\(99,999,919=10^8-81=(10^4+9)(10^4-9)=(10^4+9)(10^2+3)(10^2-3)=10,009*103*97\).
97 and 103 are factors of 99,999,919 but 101 is not a factor of 10,009. Thus 2 primes from the range are factors of 99,999,919.
Answer: C.
General Discussion
22 Nov 2016, 02:27
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Bookmarks
Great Question.
I got this Wrong the First Time.
So its in my Error Log.
Here is wat i will do the next time =>
N=10^8-81
N=1009*(103)*97
And primes between 90 and 105 are => 97,101 and 103
Hence C
I got this Wrong the First Time.
So its in my Error Log.
Here is wat i will do the next time =>
N=10^8-81
N=1009*(103)*97
And primes between 90 and 105 are => 97,101 and 103
Hence C
