silvertaurus
How many times is 6 % of 0.00005 greater than 2 % of 0.000025?
i have tried the following method but its time consuming any alternative method available?
a/b = [(6/100) * 5 * 10^(- 5)] / [(2/100) * 25 * 10^(- 6)]
a/b = [3 * 2 * 5 * 10^(- 5)] / [2 * 5 * 5 * 10^(- 6)] → you can simplify by 5
a/b = [3 * 2 * 10^(- 5)] / [2 * 5 * 10^(- 6)] → you can simplify by 2
a/b = [3 * 10^(- 5)] / [5 * 10^(- 6)]
a/b = (3/5) * 10^(- 5) / 10^(- 6)
a/b = (3/5) * 10^(- 5) * 10^(6)
a/b = (3/5) * 10^(- 5 + 6)
a/b = (3/5) * 10^(1)
a/b = (3/5) * 10
a/b = 30/5
a/b = 6 times
6% of 0.00005 = \(\frac{6}{100}*0.00005\)
2% of 0.000025 = \(\frac{2}{100}*0.000025\)
\(\frac{\frac{6}{100}*0.000050}{\frac{2}{100}*0.000025}\)
=\(\frac{6}{2}*\frac{50}{25}\) = 6
This is how I would solve the question by simplifying the equation as mentioned above.
Consider Kudos if this helps.