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26 Jul 2019, 00:32
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
54% (01:17) correct
46%
(01:26)
wrong
based on 157
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How many unequal 5-digit numbers can be formed using each digit of the number 11235 only once?
(A) \(5!\)
(B) \(5P_3\)
(C) \(\frac{5C_5}{2!}\)
(D) \(\frac{5P_5}{2!*3!}\)
(E) \(\frac{5C_5}{2!*3!}\)
(A) \(5!\)
(B) \(5P_3\)
(C) \(\frac{5C_5}{2!}\)
(D) \(\frac{5P_5}{2!*3!}\)
(E) \(\frac{5C_5}{2!*3!}\)
Updated on: 27 Jul 2019, 06:39
Originally posted by Archit3110 on 26 Jul 2019, 07:23.
Last edited by Archit3110 on 27 Jul 2019, 06:39, edited 1 time in total.
Last edited by Archit3110 on 27 Jul 2019, 06:39, edited 1 time in total.
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Bunuel
How many unequal 5-digit numbers can be formed using each digit of the number 11235 only once?
(A) \(5!\)
(B) \(5P_3\)
(C) \(\frac{5C_5}{2!}\)
(D) \(\frac{5P_5}{2!*3!}\)
(E) \(\frac{5C_5}{2!*3!}\)
(A) \(5!\)
(B) \(5P_3\)
(C) \(\frac{5C_5}{2!}\)
(D) \(\frac{5P_5}{2!*3!}\)
(E) \(\frac{5C_5}{2!*3!}\)
total ways to arrange 11235 ; 5!/2! =60 i.e \(5P_3\)
IMO B
26 Jul 2019, 10:35
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Archit3110
Bunuel
How many unequal 5-digit numbers can be formed using each digit of the number 11235 only once?
(A) \(5!\)
(B) \(5P_3\)
(C) \(\frac{5C_5}{2!}\)
(D) \(\frac{5P_5}{2!*3!}\)
(E) \(\frac{5C_5}{2!*3!}\)
(A) \(5!\)
(B) \(5P_3\)
(C) \(\frac{5C_5}{2!}\)
(D) \(\frac{5P_5}{2!*3!}\)
(E) \(\frac{5C_5}{2!*3!}\)
total ways to arrange 11235 ; 5!/2! or say \(\frac{5C_5}{2!}\)
IMO C
