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If 12x + 2y is 80% of 5y, what is the value of
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13 May 2018, 05:56
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If 12x + 2y is 80% of 5y, what is the value of x/y ? A) 1/6 B) 1/4 C) 2/5 D) 1/2 E) 5/8 *kudos for all correct solutions
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If 12x + 2y is 80% of 5y, what is the value of
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Updated on: 13 May 2018, 21:46
12x + 2y = 80/100 * 5y
so, 12x = 2y
that gives x/y =1/6
Ans: A
Originally posted by RB15 on 13 May 2018, 06:00.
Last edited by RB15 on 13 May 2018, 21:46, edited 1 time in total.



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If 12x + 2y is 80% of 5y, what is the value of
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13 May 2018, 07:08
GMATPrepNow wrote: If 12x + 2y is 80% of 5y, what is the value of x/y ?
A) 1/6 B) 1/4 C) 2/5 D) 1/2 E) 5/8
*kudos for all correct solutions \(12x + 2y = 0.8*5y\) > \(12x + 2y = 4y\) > \(12x = 2y\) Therefore, \(\frac{x}{y} = \frac{2}{12} = \frac{1}{6}\) (Option A) Alternate approach: Assume x = 1 \(12 + 2y = \frac{4}{5}*5y\) > \(2y = 12\) > \(y = 6\) Therefore, \(\frac{x}{y} = \frac{1}{6}\) (Option A)
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Re: If 12x + 2y is 80% of 5y, what is the value of
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13 May 2018, 07:11
RB15 wrote: 12x + 2y = 80y/100
so, 12x = 2y
that gives x/y =1/6
Ans: A How did you get 12x + 2y = 80y/100? Cheers, Brent
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Re: If 12x + 2y is 80% of 5y, what is the value of
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13 May 2018, 18:22
Since, 12x + 2y is 80% of 5y
Hence, 12x + 2y = 4y
x/y = 1/6



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If 12x + 2y is 80% of 5y, what is the value of
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13 May 2018, 18:37
RB15 wrote: 12x + 2y = 80y/100
This should be \(12x + 2y = \frac{80}{100} * 5y\) You've got the correct answer, I think its just a typo
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Re: If 12x + 2y is 80% of 5y, what is the value of
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13 May 2018, 21:47
GMATPrepNow wrote: RB15 wrote: 12x + 2y = 80y/100
so, 12x = 2y
that gives x/y =1/6
Ans: A How did you get 12x + 2y = 80y/100? Cheers, Brent It was a typo. Edited now. Thanks for pointing it out.



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Re: If 12x + 2y is 80% of 5y, what is the value of
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14 May 2018, 07:37
GMATPrepNow wrote: If 12x + 2y is 80% of 5y, what is the value of x/y ?
A) 1/6 B) 1/4 C) 2/5 D) 1/2 E) 5/8
*kudos for all correct solutions pushpitkc's approach is exactly the same as the approach I'd use. However, here's another approach (for kicks!) Let's try to find some values for x and y that satisfy the given information: 12x + 2y is 80% of 5yLet's first let y = 20, and then figure out what value of x is needed. We get: 12x + 2( 20) is 80% of 5( 20) Simplify: 12x + 40 is 80% of 100 Evaluate: 12x + 40 = 80 So: 12x = 40 Solve: x = 40/12 = 10/3So, x = 10/3 and y = 20 satisfies the given information. What is the value of x/y ?x/ y = (10/3)/ 20 = (10/3)(1/20) = 10/60 = 1/6 Answer: A
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Re: If 12x + 2y is 80% of 5y, what is the value of
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14 May 2018, 07:42
GMATPrepNow wrote: If 12x + 2y is 80% of 5y, what is the value of x/y ?
A) 1/6 B) 1/4 C) 2/5 D) 1/2 E) 5/8
*kudos for all correct solutions 12x + 2y = 80% of 5y So, 12x + 2y = 4y Or, 12x = 2y Or, y = 6x So, x/y = 1/6, Answer must be (A)
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Re: If 12x + 2y is 80% of 5y, what is the value of
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27 Aug 2018, 23:07
GMATPrepNow wrote: If 12x + 2y is 80% of 5y, what is the value of x/y ?
A) 1/6 B) 1/4 C) 2/5 D) 1/2 E) 5/8
*kudos for all correct solutions This is how i solved If 12x + 2y is 80% of 5y, what is the value of x/y ? 12x+2y = (80*5y/100) 12x+2y = 400y/100 Cross multiply to get 1200x +200y = 400 y 1200 x = 200y x/y= 200/1200 = 1/6 = A



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Re: If 12x + 2y is 80% of 5y, what is the value of
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Re: If 12x + 2y is 80% of 5y, what is the value of
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