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If 12x + 2y is 80% of 5y, what is the value of

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If 12x + 2y is 80% of 5y, what is the value of  [#permalink]

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New post 13 May 2018, 06:56
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If 12x + 2y is 80% of 5y, what is the value of x/y ?

A) 1/6
B) 1/4
C) 2/5
D) 1/2
E) 5/8

*kudos for all correct solutions

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If 12x + 2y is 80% of 5y, what is the value of  [#permalink]

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New post Updated on: 13 May 2018, 22:46
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12x + 2y = 80/100 * 5y

so, 12x = 2y

that gives x/y =1/6

Ans: A

Originally posted by RB15 on 13 May 2018, 07:00.
Last edited by RB15 on 13 May 2018, 22:46, edited 1 time in total.
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If 12x + 2y is 80% of 5y, what is the value of  [#permalink]

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New post 13 May 2018, 08:08
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GMATPrepNow wrote:
If 12x + 2y is 80% of 5y, what is the value of x/y ?

A) 1/6
B) 1/4
C) 2/5
D) 1/2
E) 5/8

*kudos for all correct solutions



\(12x + 2y = 0.8*5y\) -> \(12x + 2y = 4y\) -> \(12x = 2y\) Therefore, \(\frac{x}{y} = \frac{2}{12} = \frac{1}{6}\)(Option A)


Alternate approach: Assume x = 1

\(12 + 2y = \frac{4}{5}*5y\) -> \(2y = 12\) -> \(y = 6\) Therefore, \(\frac{x}{y} = \frac{1}{6}\)(Option A)
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Re: If 12x + 2y is 80% of 5y, what is the value of  [#permalink]

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New post 13 May 2018, 08:11
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RB15 wrote:
12x + 2y = 80y/100

so, 12x = 2y

that gives x/y =1/6

Ans: A


How did you get 12x + 2y = 80y/100?

Cheers,
Brent
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Re: If 12x + 2y is 80% of 5y, what is the value of  [#permalink]

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New post 13 May 2018, 19:22
Since, 12x + 2y is 80% of 5y

Hence, 12x + 2y = 4y

x/y = 1/6
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If 12x + 2y is 80% of 5y, what is the value of  [#permalink]

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New post 13 May 2018, 19:37
RB15 wrote:
12x + 2y = 80y/100


This should be \(12x + 2y = \frac{80}{100} * 5y\)

You've got the correct answer, I think its just a typo
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Re: If 12x + 2y is 80% of 5y, what is the value of  [#permalink]

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New post 13 May 2018, 22:47
GMATPrepNow wrote:
RB15 wrote:
12x + 2y = 80y/100

so, 12x = 2y

that gives x/y =1/6

Ans: A


How did you get 12x + 2y = 80y/100?

Cheers,
Brent


It was a typo. Edited now. Thanks for pointing it out.
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Re: If 12x + 2y is 80% of 5y, what is the value of  [#permalink]

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New post 14 May 2018, 08:37
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GMATPrepNow wrote:
If 12x + 2y is 80% of 5y, what is the value of x/y ?

A) 1/6
B) 1/4
C) 2/5
D) 1/2
E) 5/8

*kudos for all correct solutions


pushpitkc's approach is exactly the same as the approach I'd use.
However, here's another approach (for kicks!)

Let's try to find some values for x and y that satisfy the given information: 12x + 2y is 80% of 5y
Let's first let y = 20, and then figure out what value of x is needed.
We get: 12x + 2(20) is 80% of 5(20)
Simplify: 12x + 40 is 80% of 100
Evaluate: 12x + 40 = 80
So: 12x = 40
Solve: x = 40/12 = 10/3

So, x = 10/3 and y = 20 satisfies the given information.

What is the value of x/y ?
x/y = (10/3)/20
= (10/3)(1/20)
= 10/60
= 1/6

Answer: A
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Re: If 12x + 2y is 80% of 5y, what is the value of  [#permalink]

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New post 14 May 2018, 08:42
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GMATPrepNow wrote:
If 12x + 2y is 80% of 5y, what is the value of x/y ?

A) 1/6
B) 1/4
C) 2/5
D) 1/2
E) 5/8

*kudos for all correct solutions

12x + 2y = 80% of 5y

So, 12x + 2y = 4y

Or, 12x = 2y

Or, y = 6x

So, x/y = 1/6, Answer must be (A)
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Re: If 12x + 2y is 80% of 5y, what is the value of  [#permalink]

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New post 28 Aug 2018, 00:07
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GMATPrepNow wrote:
If 12x + 2y is 80% of 5y, what is the value of x/y ?

A) 1/6
B) 1/4
C) 2/5
D) 1/2
E) 5/8

*kudos for all correct solutions


This is how i solved

If 12x + 2y is 80% of 5y, what is the value of x/y ?

12x+2y = (80*5y/100)
12x+2y = 400y/100

Cross multiply to get 1200x +200y = 400 y
1200 x = 200y
x/y= 200/1200 = 1/6 = A
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Re: If 12x + 2y is 80% of 5y, what is the value of   [#permalink] 28 Aug 2018, 00:07
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