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If 4 < x < 7 and 6 < y < 3, which of the following specifies all the
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13 Jan 2011, 18:08
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If 4 < x < 7 and 6 < y < 3, which of the following specifies all the possible values of xy? A. 42 < xy < 21 B. 42 < xy < 24 C. 28 < xy < 18 D. 24 < xy < 21 E. 24 < xy < 24
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Re: If 4 < x < 7 and 6 < y < 3, which of the following specifies all the
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13 Jan 2011, 18:38
dc123 wrote: If 4<x<7 and 6<y<3, which of the following specifies all the possible values to xy?
42<xy<21 42<xy<24 28<xy<18 24<xy<21 24<xy<24
Answer says its B....I dont get it....Help plz Minimum value of xy will be negative with highest absolute value. If x is very close to 7 and y is very close to 6, xy will be very close to 42. This is the maximum absolute value of xy with a negative sign. So it is the minimum value of xy. Maximum value of xy will be positive with highest absolute value. When you multiply two positive numbers, you get a positive and when you multiply two negative numbers you get a positive number. The maximum absolute value will be obtained when x is very close to 4 and y is very close to 6. So xy will be very close to 24. Answer B. Else, take a straight forward approach. Just try all four extremity combinations: 4<x<7 6<y<3 If x is very close to 7 and y is very close to 3, xy will be very close to 21. If x is very close to 7 and y is very close to 6, xy will be very close to 42. If x is very close to 4 and y is very close to 6, xy will be very close to 24. If x is very close to 4 and y is very close to 3, xy will be very close to 12. Smallest value is 42 and greatest value is 24.
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25 Oct 2012, 17:48
librian383 wrote: if 4<x<7 and 6 < y< 3, which of the following specifies the all possible values of xy? 1.42<xy<21 2.42<xy<28 3.28<xy<18 4.24<xy<21 5.24<xy<24 I think the answer should be 42<xy<24, which is not one of the options. To find the range of xy, we need to find the minimum this number can be. Since from the ranges given for both x and y cover both positive and negative numbers, the range of xy would also range from negative number to positive number. To find the minimum, we have to find the maximum negative number possible => one of the x and y is positive and the other is negative and the magnitude of the product is maximum. This can be achieved when x~7 (x cannot be equal to 7 but can be as close as possible) and y~6. This combination gives xy~42 To find the maximum, we have to find a positive number =>either both x and y are negative OR both x and y are positive => we compare the products (4*6) and (7*3) =>maximum of these is 24.
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Re: If 4 < x < 7 and 6 < y < 3, which of the following
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IF 4 < X < 7 and 6 < y < 3, which of the following specifies all the
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28 Oct 2014, 16:06
IF 4 < X < 7 and 6 < y < 3, which of the following specifies all the possible values of xy? A. 42 < XY <21 B. 42 < XY < 24 C. 28 < XY < 18 D. 24 < XY < 21 E. 24 < XY < 24 OA So I got this wrong on the exam because I was pressed for time and was multiplying the 2 extreme positive and negative numbers and not finding my answer. Also I since it say x and y were LESS than, I looked at XY with the idea that x was 3 to 6 inclusive and Y was 5 to 2 inclusive. Anyway, when I reviewed, I drew out the number line on each and could clearly see the right answer. My question is "is there a faster way to do this than diagramming it all out or is that generally the best/fastest approach?



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IF 4 < X < 7 and 6 < y < 3, which of the following specifies all the
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Updated on: 29 Oct 2014, 00:26
angelfire213 wrote: IF 4 < X < 7 and 6 < y < 3, which of the following specifies all the possible values of xy? A. 42 < XY <21 B. 42 < XY < 24 C. 28 < XY < 18 D. 24 < XY < 21 E. 24 < XY < 24 OA So I got this wrong on the exam because I was pressed for time and was multiplying the 2 extreme positive and negative numbers and not finding my answer. Also I since it say x and y were LESS than, I looked at XY with the idea that x was 3 to 6 inclusive and Y was 5 to 2 inclusive. Anyway, when I reviewed, I drew out the number line on each and could clearly see the right answer. My question is "is there a faster way to do this than diagramming it all out or is that generally the best/fastest approach? Multiply all the possible combinations in such cases: 4 * 7 = 28 4 * 6 = 24 >>> Highest 4 * 3 = 12 7 * 6 = 42 >>> Lowest 7 * 3 = 21 Answer = B
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Originally posted by PareshGmat on 29 Oct 2014, 00:23.
Last edited by PareshGmat on 29 Oct 2014, 00:26, edited 2 times in total.



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IF 4 < X < 7 and 6 < y < 3, which of the following specifies all the
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29 Oct 2014, 00:24
Conventional method: Draw the number line as below: Attachment:
pro.png [ 3.42 KiB  Viewed 14631 times ]
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If 4<x<7 and 6<y<3, which of the following ...
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08 Nov 2014, 01:01
alexa wrote: Please help!!
If 4<x<7 and 6<y<3, which of the following specifies all the possible values of xy?
a. 42<xy<21 b. 42<xy<24 c. 28<xy<18 d. 24<xy<21 e. 24<xy<24 Hi This is min/max question. To find the range of xy, you need to find MAX xy and MIN xy The easiest way is to test and see what max and min are. Max = 4*6 = 24 Min = 6*7 = 42 Range: 42 < xy < 24 Hope it helps.
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Re: If 4 < x <7 and 6 < y < 3,
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16 Dec 2015, 04:05
HarveyKlaus wrote: Can anybody help me workout this problem?
If 4 < x <7 and 6 < y < 3, which of the following specifies all the possible values of xy?
A. 42 < xy < 21 B. 42 <xy < 24 C. 28 < xy < 18 D. 24 < xy < 21 E. 24 <xy < 24
Thank you. This is a question that tests your observation of the following facts:  x  = +  x + =  + x  =  + x + = + Thus, you need to now multiply the extreme values of x (4,7) with extreme values of y (6, 3) to get : 4 x 6 = 24 4 x 3= 12 7 x  6= 42 7 x 3 = 21 Thus you see the minimum value = 42 and the maximum value = 24 . All other combinations of xy will give you values within these 2 values. Hence the range of xy: 42 < xy < 24 B is the correct answer. Hope this helps.



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Re: If 4 < x < 7 and 6 < y < 3, which of the following specifies all the
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02 May 2016, 02:49
Minimum value of xy is the product in absolute terms of x and y that give a min value = 7 * (6) =  42 Maximum value of xy is the product in absolute terms of x and y that give a max value = (4) * (6) = 24 thus the range in which all possible values of xy can lie is 42< xy <24 correct option  B



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Re: If 4 < x < 7 and 6 < y < 3, which of the following specifies all the
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17 Aug 2016, 06:43
If 4 < x < 7 and 6 < y < 3, which of the following specifies all the possible values of xy? Initially consider all posssible values of xy, we can decide the ranges later xy=24, 12, 42, 21 now pick the extremes 42<xy<21
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Re: If 4<x<7 and 6<y<3, which of the following specifies all the possib
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02 Mar 2017, 03:39
4<x<7 : 4, 3, 2, 1, 0, 1, 2, 3, 4, 5, 6, 7 : with boundary values 6<y<3 :  6, 5, 4, 3, 2, 1, 0, 1, 2, 3 : with boundary values
what is the minimum and maximum product valud of XY we can get here Start multiplying the boundary values : 4*6 = 24 7*3 = 21 7 * 6 = 42 4 * 3 = 12
out of these values take the minimum and maximum values ; 42< xy < 24



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Re: If 4 < x < 7 and 6 < y < 3, which of the following specifies all the
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12 Mar 2017, 23:29
Minimum value of xy is 6*7=42 Maximum value of xy is 6*4=24 answer is B



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Re: If 4 < x < 7 and 6 < y < 3, which of the following specifies all the
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15 Mar 2017, 15:48
pike wrote: If 4 < x < 7 and 6 < y < 3, which of the following specifies all the possible values of xy?
A. 42 < xy < 21 B. 42 < xy < 24 C. 28 < xy < 18 D. 24 < xy < 21 E. 24 < xy < 24 To determine the largest possible value of xy, we either multiply together the two smallest negative values or the two largest positive values. Since (4)(6) = 24 and (7)(3) = 21, and 24 > 21, we see that the largest possible product of x and y is less than 24. To determine the smallest value of xy, we multiply the largest positive number by the smallest negative number. Thus, the product of x and y must be greater than (7)(6) = 42. Thus: 42 < xy < 24 Answer: B
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Re: If 4 < x < 7 and 6 < y < 3, which of the following specifies all the
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21 Aug 2017, 02:10
possible values of x = 3, 2, 1, 0 ,1, 2, 3, 4, 5, 6 Possible values of y = 5 ,4 ,3 ,2, 1, 0, 1, 2
values of xy ranges between 30 to 15
With this logic, I chose option A.
My question here is, why are we assuming xy could be 24 (6).(4) because it doesn't say inclusive? Why are we considering 6 and 4 as possible values of y and x respectively?



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If 4 < x < 7 and 6 < y < 3, which of the following specifies all the
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06 Dec 2017, 15:52
Fedemaravilla wrote: If 4 < x < 7 and 6 < y < 3, which of the following specifies all the possible values of xy?
A. 42 < xy < 21 B. 42 < xy < 24 C. 28 < xy < 18 D. 24 < xy < 21 E. 24 < xy < 24 The fastest and most accurate method is often just to list the possibilities for xy. Multiply each value of x's range (low end, high end), by each value of y's range (low and high). 4 < x < 7 6 < y < 3 (x)(y)? (4)(6) = 24 (4)(3) = 12 (7)(6) = 42 (7)(3) = 21 The smallest is 42 The greatest is 24 42 < xy < 24 Answer B Whatever the case, to maximize xy (to find the greatest number, the upper end of the inequality for xy):  find one end value of x which, when multiplied by one end value of y, is the greatest number. Do not assume that rightmost values for x and y will produce the greatest product. That is trap Answer A here. 24 > 21 In this case, for example: the greatest product of (x*y) consists of multiplying x's and y's SMALLEST numbers (i.e., the numbers 4 and 6, which mark the low end of their respective ranges). To minimize, to find the smallest number xy can be:  use one of the end numbers from x's range which, when multiplied by an end number from y's range, yields the smallest number  in this case, the smallest number is 42, where 42 is the "most negative" number, the one farthest to the left of zero in the number line.
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Re: If 4 < x < 7 and 6 < y < 3, which of the following specifies all the
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Re: If 4 < x < 7 and 6 < y < 3, which of the following specifies all the
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19 Apr 2018, 12:23
pike wrote: If 4 < x < 7 and 6 < y < 3, which of the following specifies all the possible values of xy?
A. 42 < xy < 21 B. 42 < xy < 24 C. 28 < xy < 18 D. 24 < xy < 21 E. 24 < xy < 24 Let's examine the EXTREME VALUES Of x and y and see what happens. If we want to MINIMIZE the value of xy, we need to examine what happens when 1 EXTREME value is positive and 1 EXTREME value is negative. case a: x = 4 and y = 3, in which case xy = 12 case b: x = 7 and y = 6, in which case xy = 42Great, so xy is MINIMIZED when x = 7 and y = 6 Of course, we're told that x < 7 and y > 6, but that's fine. Basically, this means that xy > 42 At this point, we know that the correct answer must be either A or B. Next, if we want to MAXIMIZE the value of xy, we need to examine what happens when both EXTREME values are positive or both are negative. case c: x = 4 and y = 6, in which case xy = 24case d: x = 7 and y = 3, in which case xy = 21 Great, so xy is MAXIMIZED when x = 4 and y = 6 Of course, we're told that x > 4 and y > 6, but that's fine. Basically, this means that xy < 24 So, as you can see, 42 < xy < 24Answer: B Cheers, Brent
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