Last visit was: 21 Apr 2026, 15:23 It is currently 21 Apr 2026, 15:23
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
pike
User avatar
Current Student
Joined: 08 Jan 2009
Last visit: 27 Dec 2020
Posts: 245
Own Kudos:
505
 [132]
Given Kudos: 7
GMAT 1: 770 Q50 V46
GMAT 1: 770 Q50 V46
Posts: 245
Kudos: 505
 [132]
15
Kudos
Add Kudos
117
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,438
Own Kudos:
79,375
 [48]
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,438
Kudos: 79,375
 [48]
21
Kudos
Add Kudos
27
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 21 Apr 2026
Posts: 109,728
Own Kudos:
Given Kudos: 105,800
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,728
Kudos: 810,465
 [14]
5
Kudos
Add Kudos
9
Bookmarks
Bookmark this Post
General Discussion
User avatar
ChiranjeevSingh
Joined: 22 Oct 2012
Last visit: 21 Apr 2026
Posts: 427
Own Kudos:
3,206
 [6]
Given Kudos: 161
Status:Private GMAT Tutor
Location: India
Concentration: Economics, Finance
Schools: IIMA  (A)
GMAT Focus 1: 735 Q90 V85 DI85
GMAT Focus 2: 735 Q90 V85 DI85
GMAT Focus 3: 735 Q88 V87 DI84
GMAT 1: 780 Q51 V47
GRE 1: Q170 V168
Expert
Expert reply
Schools: IIMA  (A)
GMAT Focus 3: 735 Q88 V87 DI84
GMAT 1: 780 Q51 V47
GRE 1: Q170 V168
Posts: 427
Kudos: 3,206
 [6]
3
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
librian383
if -4<x<7 and -6 < y< 3, which of the following specifies the all possible values of xy?
1.-42<xy<21
2.-42<xy<28
3.-28<xy<18
4.-24<xy<21
5.-24<xy<24

I think the answer should be -42<xy<24, which is not one of the options.

To find the range of xy, we need to find the minimum this number can be. Since from the ranges given for both x and y cover both positive and negative numbers, the range of xy would also range from negative number to positive number.

To find the minimum, we have to find the maximum negative number possible => one of the x and y is positive and the other is negative and the magnitude of the product is maximum. This can be achieved when x~7 (x cannot be equal to 7 but can be as close as possible) and y~-6. This combination gives xy~-42

To find the maximum, we have to find a positive number =>either both x and y are negative OR both x and y are positive => we compare the products (-4*-6) and (7*3) =>maximum of these is 24.
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
IF -4 < X < 7 and -6 < y < 3, which of the following specifies all the possible values of xy?

A. -42 < XY <21
B. -42 < XY < 24
C. -28 < XY < 18
D. -24 < XY < 21
E. -24 < XY < 24

OA
So I got this wrong on the exam because I was pressed for time and was multiplying the 2 extreme positive and negative numbers and not finding my answer. Also I since it say x and y were LESS than, I looked at XY with the idea that x was -3 to 6 inclusive and Y was -5 to 2 inclusive.

Anyway, when I reviewed, I drew out the number line on each and could clearly see the right answer. My question is "is there a faster way to do this than diagramming it all out or is that generally the best/fastest approach?
avatar
PareshGmat
Joined: 27 Dec 2012
Last visit: 10 Jul 2016
Posts: 1,531
Own Kudos:
8,270
 [3]
Given Kudos: 193
Status:The Best Or Nothing
Location: India
Concentration: General Management, Technology
WE:Information Technology (Computer Software)
Posts: 1,531
Kudos: 8,270
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
angelfire213
IF -4 < X < 7 and -6 < y < 3, which of the following specifies all the possible values of xy?

A. -42 < XY <21
B. -42 < XY < 24
C. -28 < XY < 18
D. -24 < XY < 21
E. -24 < XY < 24

OA
So I got this wrong on the exam because I was pressed for time and was multiplying the 2 extreme positive and negative numbers and not finding my answer. Also I since it say x and y were LESS than, I looked at XY with the idea that x was -3 to 6 inclusive and Y was -5 to 2 inclusive.

Anyway, when I reviewed, I drew out the number line on each and could clearly see the right answer. My question is "is there a faster way to do this than diagramming it all out or is that generally the best/fastest approach?


Multiply all the possible combinations in such cases:

-4 * 7 = -28

-4 * -6 = 24 >>> Highest

-4 * 3 = -12

7 * -6 = -42 >>> Lowest

7 * 3 = 21

Answer = B
avatar
PareshGmat
Joined: 27 Dec 2012
Last visit: 10 Jul 2016
Posts: 1,531
Own Kudos:
8,270
 [4]
Given Kudos: 193
Status:The Best Or Nothing
Location: India
Concentration: General Management, Technology
WE:Information Technology (Computer Software)
Posts: 1,531
Kudos: 8,270
 [4]
4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Conventional method:

Draw the number line as below:

Attachment:
pro.png
pro.png [ 3.42 KiB | Viewed 51148 times ]
User avatar
pqhai
User avatar
Retired Moderator
Joined: 16 Jun 2012
Last visit: 26 Nov 2015
Posts: 864
Own Kudos:
8,939
 [1]
Given Kudos: 123
Location: United States
Posts: 864
Kudos: 8,939
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
alexa
Please help!!

If -4<x<7 and -6<y<3, which of the following specifies all the possible values of xy?

a. -42<xy<21
b. -42<xy<24
c. -28<xy<18
d. -24<xy<21
e. -24<xy<24

Hi

This is min/max question. To find the range of xy, you need to find MAX xy and MIN xy

The easiest way is to test and see what max and min are.
Max = -4*-6 = 24
Min = -6*7 = -42

Range: -42 < xy < 24

Hope it helps.
User avatar
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,319
Own Kudos:
3,889
 [4]
Given Kudos: 816
Concentration: Finance, Strategy
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
GMAT 1: 750 Q49 V44
Posts: 2,319
Kudos: 3,889
 [4]
4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
HarveyKlaus
Can anybody help me workout this problem?

If -4 < x <7 and -6 < y < 3, which of the following specifies all the possible values of xy?

A. -42 < xy < 21
B. -42 <xy < 24
C. -28 < xy < 18
D. -24 < xy < 21
E. -24 <xy < 24


Thank you.

This is a question that tests your observation of the following facts:

- x - = +
- x + = -
+ x - = -
+ x + = +

Thus, you need to now multiply the extreme values of x (-4,7) with extreme values of y (-6, 3) to get :

-4 x -6 = 24
-4 x 3= -12
7 x - 6= -42
7 x 3 = 21

Thus you see the minimum value = -42 and the maximum value = 24 . All other combinations of xy will give you values within these 2 values.

Hence the range of xy: -42 < xy < 24

B is the correct answer.

Hope this helps.
User avatar
rhine29388
Joined: 24 Nov 2015
Last visit: 21 Oct 2019
Posts: 386
Own Kudos:
Given Kudos: 231
Location: United States (LA)
Products:
Posts: 386
Kudos: 146
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Minimum value of xy is the product in absolute terms of x and y that give a min value = 7 * (-6) = - 42
Maximum value of xy is the product in absolute terms of x and y that give a max value = (-4) * (-6) = 24
thus the range in which all possible values of xy can lie is -42< xy <24
correct option - B
User avatar
gocoder
Joined: 19 Oct 2014
Last visit: 03 Nov 2019
Posts: 27
Own Kudos:
Given Kudos: 41
Location: India
Concentration: Finance, Entrepreneurship
GMAT 1: 600 Q48 V25
GMAT 2: 670 Q49 V31
GPA: 3.26
WE:Operations (Manufacturing)
Kudos
Add Kudos
Bookmarks
Bookmark this Post
If -4 < x < 7 and -6 < y < 3, which of the following specifies all the possible values of xy?

Initially consider all posssible values of xy, we can decide the ranges later
xy=24, -12, -42, 21
now pick the extremes
-42<xy<21
User avatar
FieryLeo
Joined: 28 Jul 2011
Last visit: 02 Apr 2025
Posts: 20
Own Kudos:
52
 [1]
Given Kudos: 5
Location: United Kingdom
WE:Corporate Finance (Energy)
Posts: 20
Kudos: 52
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
-4<x<7 : -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7 : with boundary values
-6<y<3 : - 6, -5, -4, -3, -2, -1, 0, 1, 2, 3 : with boundary values

what is the minimum and maximum product valud of XY we can get here
Start multiplying the boundary values :
-4*-6 = 24
7*3 = 21
-7 * -6 = -42
-4 * 3 = -12

out of these values take the minimum and maximum values ; -42< xy < 24
User avatar
eddy8700
Joined: 25 Jan 2016
Last visit: 02 Oct 2020
Posts: 86
Own Kudos:
Given Kudos: 12
Status:active
Location: India
Concentration: Finance, Entrepreneurship
GPA: 4
WE:Web Development (Computer Software)
Posts: 86
Kudos: 75
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Minimum value of xy is -6*7=-42
Maximum value of xy is -6*-4=24
answer is B
User avatar
JeffTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 04 Mar 2011
Last visit: 05 Jan 2024
Posts: 2,974
Own Kudos:
8,708
 [4]
Given Kudos: 1,646
Status:Head GMAT Instructor
Affiliations: Target Test Prep
Expert
Expert reply
Posts: 2,974
Kudos: 8,708
 [4]
4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
pike
If -4 < x < 7 and -6 < y < 3, which of the following specifies all the possible values of xy?

A. -42 < xy < 21
B. -42 < xy < 24
C. -28 < xy < 18
D. -24 < xy < 21
E. -24 < xy < 24

To determine the largest possible value of xy, we either multiply together the two smallest negative values or the two largest positive values. Since (-4)(-6) = 24 and (7)(3) = 21, and 24 > 21, we see that the largest possible product of x and y is less than 24.

To determine the smallest value of xy, we multiply the largest positive number by the smallest negative number. Thus, the product of x and y must be greater than (7)(-6) = -42. Thus:

-42 < xy < 24

Answer: B
User avatar
pra1785
Joined: 20 Jan 2016
Last visit: 10 Mar 2019
Posts: 145
Own Kudos:
130
 [3]
Given Kudos: 64
Posts: 145
Kudos: 130
 [3]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
possible values of x = -3, -2, -1, 0 ,1, 2, 3, 4, 5, 6
Possible values of y = -5 ,-4 ,-3 ,-2, -1, 0, 1, 2

values of xy ranges between -30 to 15

With this logic, I chose option A.

My question here is, why are we assuming xy could be 24 (-6).(-4) because it doesn't say inclusive? Why are we considering -6 and -4 as possible values of y and x respectively?
User avatar
generis
User avatar
Senior SC Moderator
Joined: 22 May 2016
Last visit: 18 Jun 2022
Posts: 5,258
Own Kudos:
Given Kudos: 9,464
Expert
Expert reply
Posts: 5,258
Kudos: 37,724
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Fedemaravilla
If -4 < x < 7 and -6 < y < 3, which of the following specifies all the possible values of xy?

A. -42 < xy < 21
B. -42 < xy < 24
C. -28 < xy < 18
D. -24 < xy < 21
E. -24 < xy < 24

The fastest and most accurate method is often just to list the possibilities for xy.

Multiply each value of x's range (low end, high end), by each value of y's range (low and high).

-4 < x < 7
-6 < y < 3

(x)(y)?

(-4)(-6) = 24
(-4)(3) = -12
(7)(-6) = -42
(7)(3) = 21

The smallest is -42
The greatest is 24

-42 < xy < 24

Answer B

Whatever the case, to maximize xy (to find the greatest number, the upper end of the inequality for xy):
-- find one end value of x which, when multiplied by one end value of y, is the greatest number. Do not assume that rightmost values for x and y will produce the greatest product. That is trap Answer A here. 24 > 21

In this case, for example: the greatest product of (x*y) consists of multiplying x's and y's SMALLEST numbers (i.e., the numbers -4 and -6, which mark the low end of their respective ranges).

To minimize, to find the smallest number xy can be:
-- use one of the end numbers from x's range which, when multiplied by an end number from y's range, yields the smallest number
-- in this case, the smallest number is -42, where -42 is the "most negative" number, the one farthest to the left of zero in the number line.
User avatar
GMATBusters
User avatar
GMAT Tutor
Joined: 27 Oct 2017
Last visit: 21 Apr 2026
Posts: 1,921
Own Kudos:
Given Kudos: 241
WE:General Management (Education)
Expert
Expert reply
Posts: 1,921
Kudos: 6,854
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Always check for the 4 boundary conditions.
See the procedure in the Sketch.
Attachments

WhatsApp Image 2018-03-15 at 22.04.54.jpeg
WhatsApp Image 2018-03-15 at 22.04.54.jpeg [ 86.98 KiB | Viewed 39305 times ]

User avatar
BrentGMATPrepNow
User avatar
Major Poster
Joined: 12 Sep 2015
Last visit: 31 Oct 2025
Posts: 6,733
Own Kudos:
36,441
 [2]
Given Kudos: 799
Location: Canada
Expert
Expert reply
Posts: 6,733
Kudos: 36,441
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
pike
If -4 < x < 7 and -6 < y < 3, which of the following specifies all the possible values of xy?

A. -42 < xy < 21
B. -42 < xy < 24
C. -28 < xy < 18
D. -24 < xy < 21
E. -24 < xy < 24

Let's examine the EXTREME VALUES Of x and y and see what happens.

If we want to MINIMIZE the value of xy, we need to examine what happens when 1 EXTREME value is positive and 1 EXTREME value is negative.
case a: x = -4 and y = 3, in which case xy = -12
case b: x = 7 and y = -6, in which case xy = -42
Great, so xy is MINIMIZED when x = 7 and y = -6
Of course, we're told that x < 7 and y > -6, but that's fine. Basically, this means that xy > -42

At this point, we know that the correct answer must be either A or B.

Next, if we want to MAXIMIZE the value of xy, we need to examine what happens when both EXTREME values are positive or both are negative.
case c: x = -4 and y = -6, in which case xy = 24
case d: x = 7 and y = 3, in which case xy = 21
Great, so xy is MAXIMIZED when x = -4 and y = -6
Of course, we're told that x > -4 and y > -6, but that's fine. Basically, this means that xy < 24

So, as you can see, -42 < xy < 24

Answer: B

Cheers,
Brent
User avatar
MHIKER
Joined: 14 Jul 2010
Last visit: 24 May 2021
Posts: 939
Own Kudos:
Given Kudos: 690
Status:No dream is too large, no dreamer is too small
Concentration: Accounting
Posts: 939
Kudos: 5,810
Kudos
Add Kudos
Bookmarks
Bookmark this Post
pike
If -4 < x < 7 and -6 < y < 3, which of the following specifies all the possible values of xy?

A. -42 < xy < 21
B. -42 < xy < 24
C. -28 < xy < 18
D. -24 < xy < 21
E. -24 < xy < 24


The multiplications of xy and will be
24,21,-42,-12
So, the range will be of all values
-42 < xy < 24

The Answer is B.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,956
Own Kudos:
Posts: 38,956
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109728 posts
Tuck School Moderator
853 posts