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Sub 505 Level|   Arithmetic|      
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pritis
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If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)? 08 Jun 2011, 09:35
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

5% (low)

Question Stats:

98% (00:28) correct 2% (00:48) wrong based on 151 sessions

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Date
Time
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If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)?

A -14
B -4
C 0
D 4
E 14
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C
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If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)? 08 Jun 2011, 09:46
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pritis
If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)?
Choices
A -14
B -4
C 0
D 4
E 14

Even power of negative=+ve
Odd power of negative=-ve

\(a^2=(-1)^2=1\)
\(a^3=(-1)^3=-1\)
\(a^4=(-1)^4=1\)
\(a^5=(-1)^5=-1\)

Ans: "C"

pritis:
Please use ^ to denote power.
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If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)? 03 Dec 2015, 06:45
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on solving

-(1-1+1-1)
0
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If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)? 03 Dec 2015, 07:22
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if a = -1, then putting values in equation
= -[ (-1)^2 + (-1)^3 + (-1^4) + (-1^5) ]
= -[ 1 - 1 + 1 - 1 ]
= 0
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If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)? 03 Dec 2015, 07:23
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if a = -1, then putting values in equation
= -[ (-1)^2 + (-1)^3 + (-1^4) + (-1^5) ]
= -[ 1 - 1 + 1 - 1 ]
= 0

Answer = C = 0
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If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)? 03 Dec 2015, 12:24
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If a = -1, what is the value of –(a^2 +a^3 + a^4 + a^5)?

A. -14
B. -4
C. 0
D. 4
E. 14

\(- Number^{even}\) = \(+ Number\)

\(- Number^{odd}\) = \(- Number\)

Further there is one more property of the number 1

\(1^{odd/even}\) = \(1\)

From the given numbers we have -

\(a^2+ a^4\) = 1 + 1 =>2

\(a^3 + a^5\) = (-1) + (-1) =>-2

Hence,\(a^2 + a^3 + a^4 + a^5\) = -2 + 2 =>0

Hence answer is (C) 0
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If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)? 21 Jun 2017, 22:53
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pritis
If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)?

A. -14
B. -4
C. 0
D. 4
E. 14

\(–(a^2 + a^3 + a^4 + a^5)\)

\(–((-1)^2 + (-1)^3 + (-1)^4 + (-1)^5)\)

\(–(1-1 +1 -1) = -(0) = 0 .\) Answer C...
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If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)? 21 Jun 2017, 23:16
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\(a = -1\)
\(a^2 = 1\)
\(a^3 = -1\)
\(a^4 = 1\)
\(a^5 = -1\)

\(-(a^2 + a^3 + a^4 + a^5) = -(1 - 1 + 1 - 1) = 0.\)
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If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)? 21 Jun 2017, 23:30
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If the number(x) is negative, x^even = positive and x^odd = negative

The expression(which contains 2 even powers and 2 odd powers of x), cancel each other out.
Since the number is 1, they have the same magnitude.
The sum will be 0(Option C)
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If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)? 24 Jun 2017, 14:24
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\(a = -1\)

\(a^2 + a^3 + a^4 + a^5\)

\((-1)^2 + (-1)^3 + (-1)^4 + (-1)^5\)

\(1 - 1 + 1 - 1\)

\(0\)

Hence, Answer is C
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If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)? 05 Feb 2025, 20:32
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a = -1
a^even = 1
a^odd = -1
–(a^2 + a^3 + a^4 + a^5)
= - (1-1+1-1)
= - 0
= 0
pritis
If a = -1, what is the value of –(a^2 + a^3 + a^4 + a^5)?

A -14
B -4
C 0
D 4
E 14
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