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17 Sep 2017, 03:48
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B
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If a + 3b + 4c = 9 and a + 4b + 6c = 15, then what is the value of a + 2b + 2c?
A. 0
B. 3
C. 6
D. 9
E. 24
A. 0
B. 3
C. 6
D. 9
E. 24
17 Sep 2017, 06:30
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Given data:
a + 3b + 4c = 9
a + 4b + 6c = 15
Since a + 3b + 4c = 9, 2(a + 3b + 4c) = 18 => 2a + 6b + 8c = 18 ->(1)
It has been given that a + 4b + 6c = 15 ->(2)
(1) - (2) => a + 2b + 2c = 3(Option B)
a + 3b + 4c = 9
a + 4b + 6c = 15
Since a + 3b + 4c = 9, 2(a + 3b + 4c) = 18 => 2a + 6b + 8c = 18 ->(1)
It has been given that a + 4b + 6c = 15 ->(2)
(1) - (2) => a + 2b + 2c = 3(Option B)
17 Sep 2017, 07:02
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Bunuel
If a + 3b + 4c = 9 and a + 4b + 6c = 15, then what is the value of a + 2b + 2c?
A. 0
B. 3
C. 6
D. 9
E. 24
A. 0
B. 3
C. 6
D. 9
E. 24
a+3b+4c=9 --(1)
a+4b+6c=15 --(2)
(2)-(1) ==>a+b+2c=6--(3)
(1)-(3) ==> a+2b+2c =3
Ans:B
