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If a = (b + c)/e, then c =

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If a = (b + c)/e, then c =  [#permalink]

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New post Updated on: 02 Nov 2018, 02:47
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A
B
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Difficulty:

  15% (low)

Question Stats:

93% (00:20) correct 7% (00:05) wrong based on 27 sessions

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If \(a = \frac{b+c}{e}\), then c =


(A) \((a - b)e\)

(B) \(ae − b\)

(C) \(\frac{ae}{b}\)

(D) \(\frac{b+a}{e}\)

(E) \(\frac{a}{e} − b\)

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Originally posted by pushpitkc on 02 Nov 2018, 02:43.
Last edited by Bunuel on 02 Nov 2018, 02:47, edited 1 time in total.
Renamed the topic and edited the question.
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Re: If a = (b + c)/e, then c =  [#permalink]

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New post 02 Nov 2018, 04:49
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pushpitkc wrote:
If \(a = \frac{b+c}{e}\), then c =


(A) \((a - b)e\)

(B) \(ae − b\)

(C) \(\frac{ae}{b}\)

(D) \(\frac{b+a}{e}\)

(E) \(\frac{a}{e} − b\)


GIVEN: \(a = \frac{b+c}{e}\)

Multiply both sides by e to get: \(ae = b + c\)

Subtract b from both sides to get: \(ae - b = c\)

Answer: B

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Brent
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Re: If a = (b + c)/e, then c =  [#permalink]

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New post 03 Nov 2018, 16:58
pushpitkc wrote:
If \(a = \frac{b+c}{e}\), then c =


(A) \((a - b)e\)

(B) \(ae − b\)

(C) \(\frac{ae}{b}\)

(D) \(\frac{b+a}{e}\)

(E) \(\frac{a}{e} − b\)


Simplifying, we have:

ae = b + c

ae - b = c

Answer: B
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Re: If a = (b + c)/e, then c = &nbs [#permalink] 03 Nov 2018, 16:58
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If a = (b + c)/e, then c =

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