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# If a = (b + c)/e, then c =

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Joined: 26 Feb 2016
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If a = (b + c)/e, then c =  [#permalink]

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Updated on: 02 Nov 2018, 03:47
00:00

Difficulty:

5% (low)

Question Stats:

93% (00:23) correct 7% (00:17) wrong based on 47 sessions

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If $$a = \frac{b+c}{e}$$, then c =

(A) $$(a - b)e$$

(B) $$ae − b$$

(C) $$\frac{ae}{b}$$

(D) $$\frac{b+a}{e}$$

(E) $$\frac{a}{e} − b$$

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Originally posted by pushpitkc on 02 Nov 2018, 03:43.
Last edited by Bunuel on 02 Nov 2018, 03:47, edited 1 time in total.
Renamed the topic and edited the question.
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Joined: 12 Sep 2015
Posts: 4000
Re: If a = (b + c)/e, then c =  [#permalink]

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02 Nov 2018, 05:49
Top Contributor
pushpitkc wrote:
If $$a = \frac{b+c}{e}$$, then c =

(A) $$(a - b)e$$

(B) $$ae − b$$

(C) $$\frac{ae}{b}$$

(D) $$\frac{b+a}{e}$$

(E) $$\frac{a}{e} − b$$

GIVEN: $$a = \frac{b+c}{e}$$

Multiply both sides by e to get: $$ae = b + c$$

Subtract b from both sides to get: $$ae - b = c$$

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Brent
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Re: If a = (b + c)/e, then c =  [#permalink]

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03 Nov 2018, 17:58
pushpitkc wrote:
If $$a = \frac{b+c}{e}$$, then c =

(A) $$(a - b)e$$

(B) $$ae − b$$

(C) $$\frac{ae}{b}$$

(D) $$\frac{b+a}{e}$$

(E) $$\frac{a}{e} − b$$

Simplifying, we have:

ae = b + c

ae - b = c

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Re: If a = (b + c)/e, then c =   [#permalink] 03 Nov 2018, 17:58
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