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If each of the following fractions were written as a decimal, which would have the fewest number of digits to the right of the decimal point?
A. 1/8
B. 1/5
C. 1/3
D. 2/3
E. 3/4
A. 1/8
B. 1/5
C. 1/3
D. 2/3
E. 3/4
18 Mar 2017, 21:06
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Fewest number of digits to the right of decimal means those choices having non terminating decimals will be eliminated.
So that eliminates C and D,as they have 3 in denominator.
Now we are left with A,B and E which have either 2 or 5 (factors of 10 to qualify for terminating decimals) to be terminating in nature.
If we look closely 5 can divide anything ending in 0.
So shortest decimal will be for B as it has 5 in denominator.
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So that eliminates C and D,as they have 3 in denominator.
Now we are left with A,B and E which have either 2 or 5 (factors of 10 to qualify for terminating decimals) to be terminating in nature.
If we look closely 5 can divide anything ending in 0.
So shortest decimal will be for B as it has 5 in denominator.
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18 Mar 2017, 21:22
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SajjadAhmad
If each of the following fractions were written as a decimal, which would have the fewest number of digits to the right of the decimal point?
A. 1/8
B. 1/5
C. 1/3
D. 2/3
E. 3/4
A. 1/8
B. 1/5
C. 1/3
D. 2/3
E. 3/4
\(A. \frac{1}{8}\) \(= 0.125\)
\(B. \frac{1}{5}\) \(= 0.20\)
\(C. \frac{1}{3}\) \(= 0.3333.....\)
\(D. \frac{2}{3}\) \(= 0.6666...\)
\(E. \frac{3}{4}\) \(= 0.75\)
Answer must be (B) \(0.25\)
