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If, in a baseball game, a single picher can decide to throw either a 100mph fastball or 60mph knuckle ball on any pitch, how much less time, in seconds, does the batter have from when the ball is released as a fastball than when the ball is released as a knuckle ball? (Assume where the batter's point of contact is exactly 60ft away from the pitcher's release point. 5280ft = 1 mile.)
A. \(\frac{6}{22}s\)
B. \(\frac{7}{22}s\)
C. \(\frac{8}{22}s\)
D. \(\frac{9}{22}s\)
E. \(\frac{15}{22}s\)
A. \(\frac{6}{22}s\)
B. \(\frac{7}{22}s\)
C. \(\frac{8}{22}s\)
D. \(\frac{9}{22}s\)
E. \(\frac{15}{22}s\)
10 Aug 2015, 07:36
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mejia401
If, in a baseball game, a single picher can decide to throw either a 100mph (miles per hour) fastball or 60mph knuckle ball on any pitch, how much less time, in seconds, does the batter have from when the ball is released as a fastball than when the ball is released as a knuckle ball? (Assume where the batter's point of contact is exactly 60ft away from the pitcher's release point.)
A. \(\frac{6}{22}s\)
B. \(\frac{7}{22}s\)
C. \(\frac{8}{22}s\)
D. \(\frac{9}{22}s\)
E. \(\frac{15}{22}s\)
A. \(\frac{6}{22}s\)
B. \(\frac{7}{22}s\)
C. \(\frac{8}{22}s\)
D. \(\frac{9}{22}s\)
E. \(\frac{15}{22}s\)
One conversion to know is = 1 mile = 5280ft
Time taken for fastball = (60 / (100 * 5280)) * 60 * 60 = 9/22
Time taken for knuckle ball = (60 / (60 * 5280)) * 60 * 60 = 15/22
Qn is the difference btw the time taken by the two balls => 15/22 - 9/22 = 6/22
Option A
11 Aug 2015, 00:14
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mejia401
If, in a baseball game, a single picher can decide to throw either a 100mph (miles per hour) fastball or 60mph knuckle ball on any pitch, how much less time, in seconds, does the batter have from when the ball is released as a fastball than when the ball is released as a knuckle ball? (Assume where the batter's point of contact is exactly 60ft away from the pitcher's release point.)
A. \(\frac{6}{22}s\)
B. \(\frac{7}{22}s\)
C. \(\frac{8}{22}s\)
D. \(\frac{9}{22}s\)
E. \(\frac{15}{22}s\)
A. \(\frac{6}{22}s\)
B. \(\frac{7}{22}s\)
C. \(\frac{8}{22}s\)
D. \(\frac{9}{22}s\)
E. \(\frac{15}{22}s\)
Note that for the question to be GMAT relevant, the conversion units need to be given in the question.
Time = Distance/Speed
Difference in Time = Distance/Speed1 - Distance/Speed2
Difference in Time in seconds = (60/5280) * (1/60 - 1/100) * 60*60 = 60*40*60*60/5280*60*100 = 3/11 secs
Answer (A)
