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09 Dec 2019, 00:35
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A
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Difficulty:
55%
(hard)
Question Stats:
57% (01:51) correct
43%
(01:51)
wrong
based on 103
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If m is a positive integer, is \(m! + (m + 1)\) divisible by 11?
(1) \(10 < m < 21\)
(2) m is odd
Are You Up For the Challenge: 700 Level Questions
(1) \(10 < m < 21\)
(2) m is odd
Are You Up For the Challenge: 700 Level Questions
Archit3110
Major Poster
Updated on: 09 Dec 2019, 08:03
Originally posted by Archit3110 on 09 Dec 2019, 03:00.
Last edited by Archit3110 on 09 Dec 2019, 08:03, edited 1 time in total.
Last edited by Archit3110 on 09 Dec 2019, 08:03, edited 1 time in total.
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#1
10<m<21
m=11
\(m! + (m + 1)\)
m*(m-1)!+m+1
m*((m-1)!+1)+1
wont be divisible by 11 ; hence sufficient
#2
m is odd ;
m = 1 ; no
m= 3 ; no
m=9 ; yes
insufficient
IMO A
10<m<21
m=11
\(m! + (m + 1)\)
m*(m-1)!+m+1
m*((m-1)!+1)+1
wont be divisible by 11 ; hence sufficient
#2
m is odd ;
m = 1 ; no
m= 3 ; no
m=9 ; yes
insufficient
IMO A
Bunuel
09 Dec 2019, 07:33
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For statement 1
Suppose M= 11
11!+(11+1) ;
11*10!+11+1
11(10!+1)+1
then how it could be divisible by 11.
Expression will not be divisible by 11 for given range of M.
Sufficient.
Suppose M= 11
11!+(11+1) ;
11*10!+11+1
11(10!+1)+1
then how it could be divisible by 11.
Expression will not be divisible by 11 for given range of M.
Sufficient.
Archit3110
