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31 Dec 2020, 01:15
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E
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40% (01:02) correct
60%
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If m is a positive integer, is m odd?
(1) m= 2k + 1
(2) m is a multiple of 3
Are You Up For the Challenge: 700 Level Questions
(1) m= 2k + 1
(2) m is a multiple of 3
Are You Up For the Challenge: 700 Level Questions
Updated on: 31 Dec 2020, 06:28
Originally posted by sudeshpatodiya on 31 Dec 2020, 03:18.
Last edited by sudeshpatodiya on 31 Dec 2020, 06:28, edited 1 time in total.
Last edited by sudeshpatodiya on 31 Dec 2020, 06:28, edited 1 time in total.
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Quote:
If m is a positive integer, is m odd?
(1) m= 2k + 1
(2) m is a multiple of 3
(1) m= 2k + 1
(2) m is a multiple of 3
Given, m is positive integer
1) m=2k+1
we are not told about the value of K.
If K=1/2, then m = 1+1 =2 (Even)
If K=1, then m= 2+1 = 3 (Odd)
Insufficient
2) m = 3n = 3, 6, 9,12, etc.
It could be even or odd.
Insufficient
1 & 2 combined:
m=3N and of the form 2K+1,
So, out of 3, 6, 9, 12, etc. the only acceptable values are of the form 2K+1 i.e 3, 9, 15 etc.(Odd), when K is an integer
but, when K is a fraction these values can also be written with m being an even number eg. m=2(\(\frac{5}{2}\))+1 = 6 (Even)
Both are InSufficient.
(E)
Bryan180599
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31 Dec 2020, 03:37
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sudeshpatodiya
Quote:
If m is a positive integer, is m odd?
(1) m= 2k + 1
(2) m is a multiple of 3
(1) m= 2k + 1
(2) m is a multiple of 3
Given, m is positive integer
1) m=2k+1
we are not told about the value of K.
If K=1/2, then m = 1+1 =2 (Even)
If K=1, then m= 2+1 = 3 (Odd)
Insufficient
2) m = 3n = 3, 6, 9,12, etc.
It could be even or odd.
Insufficient
1 & 2 combined:
m=3N and of the form 2K+1,
So, out of 3, 6, 9, 12, etc. the only acceptable values are of the form 2K+1 i.e 3, 9, 15 etc.
Hence, m is Odd
Both are Sufficient.
(C)
But when we take 1&2 combined, 6 can be made from 2k+1 if k = 5/2. I don't see any restriction on k, so I guess even both cannot answer the question and I would say answer E. What do you think?
