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QuantMadeEasy
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IanStewart
kapil1
If m is an integer, is \(2^m\) greater than \(5^m\)?​

(1) m + 1 > 0​

(2) m - 1 < 0​

I'm not sure why, but when I quote your post, the "OA" is not also being quoted, but the OA provided above at the moment is "C", which is not correct. What is the source of the question?

If Statement 1 is true, then m > -1. Since m is an integer, the smallest value of m would then be 0, in which case 2^m is not greater than 5^m, since they'd both equal 1. If m is a positive integer, clearly 2^m is not greater than 5^m, since the product of m "2"'s will be smaller than the product of m "5"'s. So no matter the value of m, we can be sure that 2^m is not greater than 5^m, and we can be sure the answer to the original question is "no". Statement 1 is sufficient.

Statement 2 is not sufficient. It tells us m < 1, but when m = 0, the answer to the question is "no", and when m is negative, the answer to the question is "yes". So the answer is A.

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Edited the OA. Thank you.
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