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# If n is the average (arithmetic mean) of the three numbers 6, 9, and k

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Math Expert
Joined: 02 Sep 2009
Posts: 58464
If n is the average (arithmetic mean) of the three numbers 6, 9, and k  [#permalink]

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25 Feb 2019, 00:00
00:00

Difficulty:

5% (low)

Question Stats:

94% (00:35) correct 6% (01:02) wrong based on 36 sessions

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If n is the average (arithmetic mean) of the three numbers 6, 9, and k, what is the value of k in terms of n?

(A) $$3n - 15$$

(B) $$n - 5$$

(C) $$n - 15$$

(D) $$\frac{n - 15}{3}$$

(E) $$\frac{n + 15}{3}$$

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Re: If n is the average (arithmetic mean) of the three numbers 6, 9, and k  [#permalink]

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25 Feb 2019, 00:58
Bunuel wrote:
If n is the average (arithmetic mean) of the three numbers 6, 9, and k, what is the value of k in terms of n?

(A) $$3n - 15$$

(B) $$n - 5$$

(C) $$n - 15$$

(D) $$\frac{n - 15}{3}$$

(E) $$\frac{n + 15}{3}$$

$$\frac{6 + 9 + k}{3}$$ = n

15 + k = 3n

k = 3n - 15

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Re: If n is the average (arithmetic mean) of the three numbers 6, 9, and k  [#permalink]

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25 Feb 2019, 01:08
Bunuel wrote:
If n is the average (arithmetic mean) of the three numbers 6, 9, and k, what is the value of k in terms of n?

(A) $$3n - 15$$

(B) $$n - 5$$

(C) $$n - 15$$

(D) $$\frac{n - 15}{3}$$

(E) $$\frac{n + 15}{3}$$

given
15+k=3n
k= 3n-15
IMO A
Re: If n is the average (arithmetic mean) of the three numbers 6, 9, and k   [#permalink] 25 Feb 2019, 01:08
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