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If n is the average (arithmetic mean) of the three numbers 6, 9, and k

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If n is the average (arithmetic mean) of the three numbers 6, 9, and k  [#permalink]

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New post 25 Feb 2019, 00:00
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

94% (00:35) correct 6% (01:02) wrong based on 36 sessions

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Concentration: Accounting, Finance
GPA: 3.68
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Re: If n is the average (arithmetic mean) of the three numbers 6, 9, and k  [#permalink]

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New post 25 Feb 2019, 00:58
Bunuel wrote:
If n is the average (arithmetic mean) of the three numbers 6, 9, and k, what is the value of k in terms of n?

(A) \(3n - 15\)

(B) \(n - 5\)

(C) \(n - 15\)

(D) \(\frac{n - 15}{3}\)

(E) \(\frac{n + 15}{3}\)



\(\frac{6 + 9 + k}{3}\) = n

15 + k = 3n

k = 3n - 15

A is the correct answer.
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Re: If n is the average (arithmetic mean) of the three numbers 6, 9, and k  [#permalink]

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New post 25 Feb 2019, 01:08
Bunuel wrote:
If n is the average (arithmetic mean) of the three numbers 6, 9, and k, what is the value of k in terms of n?

(A) \(3n - 15\)

(B) \(n - 5\)

(C) \(n - 15\)

(D) \(\frac{n - 15}{3}\)

(E) \(\frac{n + 15}{3}\)


given
15+k=3n
k= 3n-15
IMO A
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Re: If n is the average (arithmetic mean) of the three numbers 6, 9, and k   [#permalink] 25 Feb 2019, 01:08
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If n is the average (arithmetic mean) of the three numbers 6, 9, and k

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