rahularke
If Set Z has a median of 19, what is the range of Set Z?
(1) Z = {18, 28, 11, x, 15, y}
(2) The average (arithmetic mean) of Set Z is 20.
Range = {biggest element - smallest element}
(1) Z = {18, 28, 11, x, 15, y}
Median is given to us = 19
Median is the middle value
For set with even number of element median =sum of two middle element /2
In this case Z = {11,15,18,28, X, Y}
median is given as 19 but\(\frac{18+28}{2}\) is not 19, therefore X or Y should come after 18,
so either X or Y must be 20, but the remaining unknown can have any value from greater than 20 and thus range cannot be determined
{11,15,
18,20,28, 111] range = 111-11 =100
or
{11,15,
18,20,28,31] range = 31-11 =20
or
{11,15,
18,20,22,28] range = 28-11 =17
INSUFFICIENT
(2) The average (arithmetic mean) of Set Z is 20.
Meaning \(\frac{11+15+18+28+X+Y}{6}=20\)
72+X+Y=120
X+Y=48
We cannot find what is X and Y and thus cannot find the range
INSUFFICIENT
Merging both we know, that either X or Y is 20 therefore the remaining will be 48-20=28 and thus range will be 28-11=17
SUFFICIENT