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Curly05
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RK73
1. (5c3+5c4+1)/32. Evensflow, be careful!!!


Agree, be careful
AT LEAST 3 out of 5, not exactly 3 out of 5
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So with calculations (since we will need to do this on the actual test - the more practice now the better!!)

1) 5C3/32 + 5C4/32 + 1/32 = 16/32 = 1/2

Makes sense because the possible numbers of heads are: 0,1,2,3,4 or 5.
Considering the cases 3,4, and 5, we have half of those cases so the prob is 1/2.

2) (2C1 * 3C2 * 2C1)/7C4 = 2*3*2/35 = 12/35

Hope that would be one of the answer choices on the test!
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RK73
1. (5c3+5c4+1)/32. Evensflow, be careful!!!


My bad....

I failed to notice the word "at least".

It does happen when one solves problem at 4:30 in the morning :wink:
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evensflow
RK73
1. (5c3+5c4+1)/32. Evensflow, be careful!!!

My bad....

I failed to notice the word "at least".

It does happen when one solves problem at 4:30 in the morning :wink:



I thought I was a maniac....
Are you planning to sign up for the GMAT at 4 AM?
I heard you can get $20 off if you take your test before 6 AM. :lol:
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Hey really.... I heard it was a concession of $100 (exactly half the fees). Could you confirm that for me from GMAC. ;)



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