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(1) There were 35 more men than women at the conference
Let the number of women = \(x\)
--> The number of men = \(x + 35\)
So, \(x + (x + 35) = 65\)
--> \(2x = 30\)
--> \(x = 15\)
--> Ratio = \(\frac{(x + 35)}{x} = \frac{50}{15} = \frac{10}{3}\) --> Sufficient

(2) If the number of women attending the conference increased by 5 but the number of men remained the same, then the ratio of men to women would be 5/2.
--> Total now = 65 + 5 = 70
& ratio of men to women now = 5 to 2
--> Number of Men = \(\frac{5}{7}*70 = 50\) & Number of Women = \(20\)
Since, \(5\) women are added, Number of women = \(20 - 5 = 15\)
--> Ratio = \(\frac{Men}{Women} = \frac{50}{15} = \frac{10}{3}\) --> Sufficient

Option D
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Explanation:

Given Data: Men + Women = 65 .... Eqn 1
Find: M/W ratio.

Statement 1: M-W=35 .... Eqn 2
from Eqn 1 & 2:
M=50, W=15
Ratio = 50/15 = 10/3
Sufficient.

Statement 2: M/(W+5) = 5/2
M= 5x(W+5)/2 .... Puting this value in Eqn 1
5x(W+5)/2 + W = 65
W=15; M=50
Ratio: 50/15 = 10/3
Sufficient

IMO-D
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Given m+w = 65

To find : m/w

(1) There were 35 more men than women at the conference
m = 35 + w
Substitute in (i), m and w can be calculated.
Sufficient

(2) If the number of women attending the conference increased by 5 but the number of men remained the same, then the ratio of men to women would be 5/2.
m / (w+5) = 5/2
2m = 5w + 25
Using equation (i), values of m and w can be calculated.
Sufficient

D is correct
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