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25 Apr 2017, 03:14
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D
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If the expression x^2 – xy/5 + 25 can be expressed by (x – 5)^2, what is the value of y?
(A) 0
(B) 5
(C) 25
(D) 50
(E) 5/x
(A) 0
(B) 5
(C) 25
(D) 50
(E) 5/x
25 Apr 2017, 03:50
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xy/5 = 10x
y = 10 x 5 = 50
Sent from my HM NOTE 1LTE using Tapatalk
y = 10 x 5 = 50
Sent from my HM NOTE 1LTE using Tapatalk
28 Apr 2017, 15:16
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Bunuel
If the expression x^2 – xy/5 + 25 can be expressed by (x – 5)^2, what is the value of y?
(A) 0
(B) 5
(C) 25
(D) 50
(E) 5/x
(A) 0
(B) 5
(C) 25
(D) 50
(E) 5/x
We can FOIL the second expression (x – 5)^2 and equate the two expressions:
x^2 – xy/5 + 25 = x^2 -10x + 25
-xy/5 = -10x
-xy = -50x
y = 50
Answer: D
