GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 14 Oct 2019, 20:58 GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  If the given addition is correct, what is the sum of T, U and V?

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

Hide Tags

Retired Moderator V
Joined: 27 Oct 2017
Posts: 1256
Location: India
Concentration: International Business, General Management
GPA: 3.64
WE: Business Development (Energy and Utilities)
If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

12 00:00

Difficulty:   95% (hard)

Question Stats: 15% (02:39) correct 85% (02:58) wrong based on 111 sessions

HideShow timer Statistics

PS + QS + RS = TUV

If the given addition is correct, what is the sum of T, U and V? (P, Q, R, S, T, U and V are distinct digits.)

(1) P, Q and R are consecutive odd integers.

(2) T = 2

Attachment: Gmatbusters Quiz -2.jpeg [ 45.31 KiB | Viewed 1416 times ]

_________________
Retired Moderator V
Joined: 27 Oct 2017
Posts: 1256
Location: India
Concentration: International Business, General Management
GPA: 3.64
WE: Business Development (Energy and Utilities)
Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

Official Solution:

Statement 1:
This statement yields three possibilities for P, Q, and R, in some order: {1, 3, 5}, {3, 5, 7}, {5, 7, 9}; it makes no difference which of P, Q, and R is which digit, because they are all added together.
• If P, Q, and R are 1, 3, and 5 (in whatever order), then the digit T must be 1. This means the digits aren't distinct, so it is impossible.
• If P, Q, and R are 3, 5, and 7 (in whatever order), then T= I. That means S is one of the leftover digits O, 2, 4 6, 8, 9. If these values are plugged into S one at a time, the only one that yields all distinct digits is S -4 (34 + 54+74=162).
• If P, Q, and R are 5, 7, and 9 (in whatever order), then T = 2. That means S is one of the leftover digits O, 1, 3, 4, 6, 8. If these values are plugged into S one at a time, the only one that yields all distinct digits is S = 8 (58 + 78 + 98 = 234).
• Therefore, there are only two possible values of TUV: 162 and 234. In both cases, the sum of T, U, and V is 9,
so (I) is sufficient.

Statement 2:
If T = 2, then trial and error will yield a number of working sets of digits yielding different values for TUV. Examples: 58 + 68 + 78 = 204 (T+ U + V = 6); 41 + 71 + 91 203 ( T+ U + V = 5); 49+69 +89 207 (T+ U + V = 9); and several others.
Therefore, (2) is insufficient.

gmatbusters wrote:

Weekly Quant Quiz Question -10

If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.

Attachment:
Gmatbusters Quiz -2.jpeg

a) P, Q and R are consecutive odd integers.
b) T = 2

ONLY THE TEXT SOLUTIONS ARE ALLOWED

_________________
General Discussion
Manager  B
Joined: 08 Feb 2018
Posts: 85
GMAT 1: 670 Q50 V31 Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

Consider A, P Q R are consecutive odd integers. For any sets 1,3,5; 5,7,9; 3,5,7 depending on S values, sum of T, U, V varies.

A is not sufficient.

Consider B, if T = 2, P, Q ,R could be any distinct digits and S can vary giving different values for sum of T,U,V. Hence, B is insufficient.

Combine A,B, if T = 2 then P, Q, R must be 5,7,9 in any order and S must be 8 to satisfy the distinct digits condition giving a unique sum of T,U,V to be 2 + 3 +4 = 5

_________________
Kudos to Kudos And yeah, definitely aim for a level of accuracy where managing time will not be a burden anymore.
Senior Manager  P
Joined: 05 Jul 2018
Posts: 406
Location: India
Concentration: General Management, Technology
GMAT 1: 600 Q47 V26 GRE 1: Q162 V149 GPA: 3.6
WE: Information Technology (Consulting)
Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

As per 1) we know the numbers in 10s digit are odd consecutive integers...But this enough is not suffieicient...it can be either 3,5,7 or 5,7,1
As per 2) T=2 . Now this alone does not give any surity. As there can be multiple combinations leading to this

Using Both We know that P,q,R can only be 5,7,1 as any other combination wont give T=2. But still S can take any value and there can be multiple answers.

Hence neither of the statements alone or together are sufficient. Hence the answer is E
_________________
Appreciate any KUDOS given ! MY MBA RESOURCES:

4000 Official Verbal Question | 3700 Official quant questions

Intern  B
Joined: 09 Oct 2017
Posts: 13
Location: India
Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

1) insufficient
if s=1 then v=3
letting p, q and r = 5,7 and 9 respectively then t=2 and u=1
sum of t, u and v= 6
but if we assume s= 2
v=8 and now the sum is 11
2) we do not have to prove this one as when we consider 1st equation, the value of T is 2 in both the cases
therefore insufficient
E
Manager  G
Joined: 23 Aug 2016
Posts: 101
Location: India
Concentration: Finance, Strategy
GMAT 1: 660 Q49 V31 GPA: 2.84
WE: Other (Energy and Utilities)
Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

PS
QS
RS
____
TUV

If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.

a) P, Q and R are consecutive odd integers.
P,Q,R=1,3,5 OR 3,5,7 OR 5,7,9
NOT SUFFICIENT

b) T = 2

THEREFORE THE ANSWER BETWEEN 200 AND 298
P,Q,R COULD BE 6,7,8 OR 7,8,9 NOT SUFFICIENT
BOTH TOGETHE NOT SUFFICIENT
_________________
Thanks and Regards,

Honneeey.

In former years,Used to run for "Likes", nowadays, craving for "Kudos". :D
Senior PS Moderator D
Status: It always seems impossible until it's done.
Joined: 16 Sep 2016
Posts: 737
GMAT 1: 740 Q50 V40 GMAT 2: 770 Q51 V42 Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

First of all lets note that P,Q,R,S,T,U,V are all distinct digits.

St 1) P Q R are consecutive odd integers - this does not give us any information about TUV as PQR could be 1,3,5 or 3,5,7 or 5,7,9. Hence St 1. by itself is not sufficient

St 2) T = 2. Not sufficient by itself as many possibilities

We are left with tow options either C or E.

Option (C) is correct as a couple of trial and errors shows 234 is TUV and the whole set-up is 58+78+98 = 234

Kind Regards,
_________________
Regards,

“Do. Or do not. There is no try.” - Yoda (The Empire Strikes Back)

Originally posted by Gladiator59 on 29 Sep 2018, 11:01.
Last edited by Gladiator59 on 29 Sep 2018, 11:05, edited 1 time in total.
Intern  B
Joined: 05 Sep 2016
Posts: 24
Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

E - both not sufficient
a. It can be any consecutive numbers (not sufficient)
b. T = 2 - not sufficient as the previous three numbers -P Q R-can either be (5,7,9 or 7,9,11)

combined S can be 1 or 2 and V = 3 or 6
and P Q R-can either be (5,7,9 or 7,9,11). Still not sufficient
_________________
[i]"Take up one idea. Make that one idea your life"
RC Moderator V
Joined: 24 Aug 2016
Posts: 790
GMAT 1: 540 Q49 V16 GMAT 2: 680 Q49 V33 Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

IMO C

1) NS = possible valid combinations for P,Q.R are (1,3,5) & (5,7,9)
2) Clearly NS
1+2) (5,7,) is valid.......Ans C
_________________
Please let me know if I am going in wrong direction.
Thanks in appreciation.
Intern  B
Joined: 18 Oct 2017
Posts: 21
Location: India
Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

A. PQR are consecutive odd integers . Here. S is not given and PQR can be any combination - 1,3,5 or 3,5,7, each set yielding different results. Hence, not sufficient.

B not sufficient as information about other digits not given

Both,

As T =2, PQR will be 5,7,9 (any order)

However S is not given which will impact the value of U and V. Thus both together are not sufficient.

Thus, answer is E

Posted from my mobile device
Intern  B
Joined: 05 Sep 2016
Posts: 24
Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

gmatbusters wrote:

Official Solution:

Statement 1:
This statement yields three possibilities for P, Q, and R, in some order: {1, 3, 5}, {3, 5, 7}, {5, 7, 9}; it makes no difference which of P, Q, and R is which digit, because they are all added together.
• If P, Q, and R are 1, 3, and 5 (in whatever order), then the digit T must be 1. This means the digits aren't distinct, so it is impossible.
• If P, Q, and R are 3, 5, and 7 (in whatever order), then T= I. That means S is one of the leftover digits O, 2, 4 6, 8, 9. If these values are plugged into S one at a time, the only one that yields all distinct digits is S -4 (34 + 54+74=162).
• If P, Q, and R are 5, 7, and 9 (in whatever order), then T = 2. That means S is one of the leftover digits O, 1, 3, 4, 6, 8. If these values are plugged into S one at a time, the only one that yields all distinct digits is S = 8 (58 + 78 + 98 = 234).
• Therefore, there are only two possible values of TUV: 162 and 234. In both cases, the sum of T, U, and V is 9,
so (I) is sufficient.

Statement 2:
If T = 2, then trial and error will yield a number of working sets of digits yielding different values for TUV. Examples: 58 + 68 + 78 = 204 (T+ U + V = 6); 41 + 71 + 91 203 ( T+ U + V = 5); 49+69 +89 207 (T+ U + V = 9); and several others.
Therefore, (2) is insufficient.

gmatbusters wrote:

Weekly Quant Quiz Question -10

If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.

Attachment:
Gmatbusters Quiz -2.jpeg

a) P, Q and R are consecutive odd integers.
b) T = 2

ONLY THE TEXT SOLUTIONS ARE ALLOWED

P Q R (3,5,7) s = (2) TUV = 156
Why 32 + 52 + 72 = 156 is not unique?
_________________
[i]"Take up one idea. Make that one idea your life"
Retired Moderator V
Joined: 27 Oct 2017
Posts: 1256
Location: India
Concentration: International Business, General Management
GPA: 3.64
WE: Business Development (Energy and Utilities)
Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

Hi
We need to find sum of T, U and V
As per your solution, sum of T, U,V = 1+5+6 =12
Where as official solutions gives the sum = 5 , 6...
Since we are getting more than one value of sum, the sum of T, U and V cannot be find uniquely.
Statement 2 is INSUFFICIENT.

Hope it is clear now.

saban wrote:
gmatbusters wrote:

Official Solution:

Statement 1:
This statement yields three possibilities for P, Q, and R, in some order: {1, 3, 5}, {3, 5, 7}, {5, 7, 9}; it makes no difference which of P, Q, and R is which digit, because they are all added together.
• If P, Q, and R are 1, 3, and 5 (in whatever order), then the digit T must be 1. This means the digits aren't distinct, so it is impossible.
• If P, Q, and R are 3, 5, and 7 (in whatever order), then T= I. That means S is one of the leftover digits O, 2, 4 6, 8, 9. If these values are plugged into S one at a time, the only one that yields all distinct digits is S -4 (34 + 54+74=162).
• If P, Q, and R are 5, 7, and 9 (in whatever order), then T = 2. That means S is one of the leftover digits O, 1, 3, 4, 6, 8. If these values are plugged into S one at a time, the only one that yields all distinct digits is S = 8 (58 + 78 + 98 = 234).
• Therefore, there are only two possible values of TUV: 162 and 234. In both cases, the sum of T, U, and V is 9,
so (I) is sufficient.

Statement 2:
If T = 2, then trial and error will yield a number of working sets of digits yielding different values for TUV. Examples: 58 + 68 + 78 = 204 (T+ U + V = 6); 41 + 71 + 91 203 ( T+ U + V = 5); 49+69 +89 207 (T+ U + V = 9); and several others.
Therefore, (2) is insufficient.

gmatbusters wrote:

Weekly Quant Quiz Question -10

If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.

Attachment:
Gmatbusters Quiz -2.jpeg

a) P, Q and R are consecutive odd integers.
b) T = 2

ONLY THE TEXT SOLUTIONS ARE ALLOWED

P Q R (3,5,7) s = (2) TUV = 156
Why 32 + 52 + 72 = 156 is not unique?

_________________
Intern  B
Joined: 29 Aug 2017
Posts: 25
Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

saban wrote:
gmatbusters wrote:

Official Solution:

Statement 1:
This statement yields three possibilities for P, Q, and R, in some order: {1, 3, 5}, {3, 5, 7}, {5, 7, 9}; it makes no difference which of P, Q, and R is which digit, because they are all added together.
• If P, Q, and R are 1, 3, and 5 (in whatever order), then the digit T must be 1. This means the digits aren't distinct, so it is impossible.
• If P, Q, and R are 3, 5, and 7 (in whatever order), then T= I. That means S is one of the leftover digits O, 2, 4 6, 8, 9. If these values are plugged into S one at a time, the only one that yields all distinct digits is S -4 (34 + 54+74=162).
• If P, Q, and R are 5, 7, and 9 (in whatever order), then T = 2. That means S is one of the leftover digits O, 1, 3, 4, 6, 8. If these values are plugged into S one at a time, the only one that yields all distinct digits is S = 8 (58 + 78 + 98 = 234).
• Therefore, there are only two possible values of TUV: 162 and 234. In both cases, the sum of T, U, and V is 9,
so (I) is sufficient.

Statement 2:
If T = 2, then trial and error will yield a number of working sets of digits yielding different values for TUV. Examples: 58 + 68 + 78 = 204 (T+ U + V = 6); 41 + 71 + 91 203 ( T+ U + V = 5); 49+69 +89 207 (T+ U + V = 9); and several others.
Therefore, (2) is insufficient.

gmatbusters wrote:

Weekly Quant Quiz Question -10

If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.

Attachment:
Gmatbusters Quiz -2.jpeg

a) P, Q and R are consecutive odd integers.
b) T = 2

ONLY THE TEXT SOLUTIONS ARE ALLOWED

P Q R (3,5,7) s = (2) TUV = 156
Why 32 + 52 + 72 = 156 is not unique?

gmatbusters

This is a possibility as per statement 1 only.

TUV can be (3,5,7)

S can be 2

Then it will yield 156

Retired Moderator V
Joined: 27 Oct 2017
Posts: 1256
Location: India
Concentration: International Business, General Management
GPA: 3.64
WE: Business Development (Energy and Utilities)
If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

1
Recheck your assumption, All P, Q, R, S, T, U, V are distinct.

As per your assumption:

" TUV P, Q, R can be (3,5,7)

S can be 2

Then it will yield 156,

HERE: U and Q both are 5, but these should be distinct
[/color]

hence assumption is invalid.

"

PearlRay wrote:

Official Solution:

Statement 1:
This statement yields three possibilities for P, Q, and R, in some order: {1, 3, 5}, {3, 5, 7}, {5, 7, 9}; it makes no difference which of P, Q, and R is which digit, because they are all added together.
• If P, Q, and R are 1, 3, and 5 (in whatever order), then the digit T must be 1. This means the digits aren't distinct, so it is impossible.
• If P, Q, and R are 3, 5, and 7 (in whatever order), then T= I. That means S is one of the leftover digits O, 2, 4 6, 8, 9. If these values are plugged into S one at a time, the only one that yields all distinct digits is S -4 (34 + 54+74=162).
• If P, Q, and R are 5, 7, and 9 (in whatever order), then T = 2. That means S is one of the leftover digits O, 1, 3, 4, 6, 8. If these values are plugged into S one at a time, the only one that yields all distinct digits is S = 8 (58 + 78 + 98 = 234).
• Therefore, there are only two possible values of TUV: 162 and 234. In both cases, the sum of T, U, and V is 9,
so (I) is sufficient.

Statement 2:
If T = 2, then trial and error will yield a number of working sets of digits yielding different values for TUV. Examples: 58 + 68 + 78 = 204 (T+ U + V = 6); 41 + 71 + 91 203 ( T+ U + V = 5); 49+69 +89 207 (T+ U + V = 9); and several others.
Therefore, (2) is insufficient.

gmatbusters wrote:

Weekly Quant Quiz Question -10

If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.

Attachment:
Gmatbusters Quiz -2.jpeg

a) P, Q and R are consecutive odd integers.
b) T = 2

ONLY THE TEXT SOLUTIONS ARE ALLOWED

P Q R (3,5,7) s = (2) TUV = 156
Why 32 + 52 + 72 = 156 is not unique?[/quote]

gmatbusters

This is a possibility as per statement 1 only.

TUV can be (3,5,7)

S can be 2

Then it will yield 156

_________________
Intern  B
Joined: 28 Apr 2016
Posts: 16
Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

gmatbusters wrote:
Recheck your assumption, All P, Q, R, S, T, U, V are distinct.

As per your assumption:

" TUV P, Q, R can be (3,5,7)

S can be 2

Then it will yield 156,

HERE: U and Q both are 5, but these should be distinct
[/color]

hence assumption is invalid.

"

PearlRay wrote:

Official Solution:

Statement 1:
This statement yields three possibilities for P, Q, and R, in some order: {1, 3, 5}, {3, 5, 7}, {5, 7, 9}; it makes no difference which of P, Q, and R is which digit, because they are all added together.
• If P, Q, and R are 1, 3, and 5 (in whatever order), then the digit T must be 1. This means the digits aren't distinct, so it is impossible.
• If P, Q, and R are 3, 5, and 7 (in whatever order), then T= I. That means S is one of the leftover digits O, 2, 4 6, 8, 9. If these values are plugged into S one at a time, the only one that yields all distinct digits is S -4 (34 + 54+74=162).
• If P, Q, and R are 5, 7, and 9 (in whatever order), then T = 2. That means S is one of the leftover digits O, 1, 3, 4, 6, 8. If these values are plugged into S one at a time, the only one that yields all distinct digits is S = 8 (58 + 78 + 98 = 234).
• Therefore, there are only two possible values of TUV: 162 and 234. In both cases, the sum of T, U, and V is 9,
so (I) is sufficient.

Statement 2:
If T = 2, then trial and error will yield a number of working sets of digits yielding different values for TUV. Examples: 58 + 68 + 78 = 204 (T+ U + V = 6); 41 + 71 + 91 203 ( T+ U + V = 5); 49+69 +89 207 (T+ U + V = 9); and several others.
Therefore, (2) is insufficient.

gmatbusters wrote:

Weekly Quant Quiz Question -10

If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.

Attachment:
Gmatbusters Quiz -2.jpeg

a) P, Q and R are consecutive odd integers.
b) T = 2

ONLY THE TEXT SOLUTIONS ARE ALLOWED

P Q R (3,5,7) s = (2) TUV = 156
Why 32 + 52 + 72 = 156 is not unique?

gmatbusters

This is a possibility as per statement 1 only.

TUV can be (3,5,7)

S can be 2

Then it will yield 156

P,Q,R,S,T,U,V all are unique values.
P Q R (3,5,7) s = (2) TUV = 156
Here, Q=U=5 thus not a valid selection.
Manager  B
Joined: 08 Feb 2018
Posts: 85
GMAT 1: 670 Q50 V31 Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

Show Tags

On my second go, I somehow didn't take the PS, QS, RS as two digit numbers at all. Rather I considered them to be product of the digits. How can we rule out my possibility with nothing given in the question?
_________________
Kudos to Kudos And yeah, definitely aim for a level of accuracy where managing time will not be a burden anymore. Re: If the given addition is correct, what is the sum of T, U and V?   [#permalink] 12 Mar 2019, 09:24
Display posts from previous: Sort by

If the given addition is correct, what is the sum of T, U and V?

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne  