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Updated on: 24 Mar 2014, 00:45
Originally posted by Raghunathnallu on 23 Mar 2014, 13:06.
Last edited by Bunuel on 24 Mar 2014, 00:45, edited 1 time in total.
Last edited by Bunuel on 24 Mar 2014, 00:45, edited 1 time in total.
Edited the question.
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If the price of a certain bond on May 1st was 2/3 the price of the bond on June 1st and the price of the bond on July 1st was 25% greater than the price of the bond on May 1st. then the price of the bond on June 1st st was what percent of the average (arithmetic mean) price of the bond on May 1st and July 1st?
A. 50%
B. 75%
C. 120%
D. 133 1/3%
E. 150%
A. 50%
B. 75%
C. 120%
D. 133 1/3%
E. 150%
23 Mar 2014, 19:49
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Let price in June = x
Price in May\(= \frac{2x}{3}\)
Price in July \(= \frac{2x}{3} * \frac{125}{100}\)
Avg price of May & July \(= \frac{\frac{2x}{3} + \frac{2x}{3} * \frac{125}{100}}{2}\)
\(= \frac{75x}{100}\)
x is greater than \(\frac{75x}{100}by \frac{25x}{100}\)
In terms of percentage, it will be
\(\frac{100 * x}{\frac{75x}{100}}\)
Answer = 133.33% = D
Price in May\(= \frac{2x}{3}\)
Price in July \(= \frac{2x}{3} * \frac{125}{100}\)
Avg price of May & July \(= \frac{\frac{2x}{3} + \frac{2x}{3} * \frac{125}{100}}{2}\)
\(= \frac{75x}{100}\)
x is greater than \(\frac{75x}{100}by \frac{25x}{100}\)
In terms of percentage, it will be
\(\frac{100 * x}{\frac{75x}{100}}\)
Answer = 133.33% = D
23 Mar 2014, 20:17
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PareshGmat
Let price in June = x
Price in May\(= \frac{2x}{3}\)
Price in July \(= \frac{2x}{3} * \frac{125}{100}\)
Avg price of May & July \(= \frac{\frac{2x}{3} + \frac{2x}{3} * \frac{125}{100}}{2}\)
\(= \frac{75x}{100}\)
x is greater than \(\frac{75x}{100}by \frac{25x}{100}\)
In terms of percentage, it will be
\(\frac{100 * x}{\frac{75x}{100}}\)
Answer = 133.33% = D
Price in May\(= \frac{2x}{3}\)
Price in July \(= \frac{2x}{3} * \frac{125}{100}\)
Avg price of May & July \(= \frac{\frac{2x}{3} + \frac{2x}{3} * \frac{125}{100}}{2}\)
\(= \frac{75x}{100}\)
x is greater than \(\frac{75x}{100}by \frac{25x}{100}\)
In terms of percentage, it will be
\(\frac{100 * x}{\frac{75x}{100}}\)
Answer = 133.33% = D
I have one question - In the month of July I have considered the following
July = [2][/3]X[*][25[/100] =[1[/6]X
Average = 15/18X
now to find out the X value = X/[15[/18]x = 120% My answer is C. please let me know how you got 125/100 in July and the next steps little more explicit. Thank you so much for your help.
