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If the sum of five consecutive integers is t, then, in terms of t, wha

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If the sum of five consecutive integers is t, then, in terms of t, wha  [#permalink]

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New post 03 Jul 2018, 00:50
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If the sum of five consecutive integers is t, then, in terms of t, what is the greatest of these integers?

A. \(\frac{(t -20)}{5}\)

B. \(\frac{(t - 10)}{5}\)

C. \((\frac{t}{5})\)

D. \(\frac{(t + 10)}{5}\)

E. \(\frac{(t + 20)}{5}\)

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Re: If the sum of five consecutive integers is t, then, in terms of t, wha  [#permalink]

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New post 03 Jul 2018, 01:09
Bunuel wrote:
If the sum of five consecutive integers is t, then, in terms of t, what is the greatest of these integers?

A. \(\frac{(t -20)}{5}\)

B. \(\frac{(t - 10)}{5}\)

C. \((\frac{t}{5})\)

D. \(\frac{(t + 10)}{5}\)

E. \(\frac{(t + 20)}{5}\)



Note: all the option has 5 as their denominator.

Given ,

t is the sum of 5 consecutive integers.

Among the answer choice , option E has the greatest numerator but the same denominator.

So option E gives us the greatest value.

The best answer is E.
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Re: If the sum of five consecutive integers is t, then, in terms of t, wha  [#permalink]

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New post 03 Jul 2018, 01:39
Bunuel wrote:
If the sum of five consecutive integers is t, then, in terms of t, what is the greatest of these integers?

A. \(\frac{(t -20)}{5}\)

B. \(\frac{(t - 10)}{5}\)

C. \((\frac{t}{5})\)

D. \(\frac{(t + 10)}{5}\)

E. \(\frac{(t + 20)}{5}\)




sum of 1st five int =5*6/2=15=t
t5=(t+10)/5 satisfies

taking another set of consecutive int - just to confim
t1=10,t5=14
t in this case = 5/2(2*10+(4))
t=5/2*24=60
t5=(t+10)/5 =14
therefore D
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Re: If the sum of five consecutive integers is t, then, in terms of t, wha &nbs [#permalink] 03 Jul 2018, 01:39
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If the sum of five consecutive integers is t, then, in terms of t, wha

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