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04 Aug 2010, 11:03
Kudos
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
70% (02:09) correct
30%
(02:27)
wrong
based on 366
sessions
History
Date
Time
Result
Not Attempted Yet
If the sum of the first four numbers in a list of six consecutive even numbers is 908, what is the sum of the last four numbers in the list?
A. 912
B. 914
C. 916
D. 920
E. 924
A. 912
B. 914
C. 916
D. 920
E. 924
I tried it, but got screwed up:
let 2x be one of the numbers;
list: 2x-4, 2x-2, 2x, 2x+2, 2x+4, 2x+6
sum of the first four: (2x-4) + (2x-2) + (2x) + 2x+2)
--> 4x-4=908
x=228
sum of last four: 2x + (2x+2) + (2x+4) + (2x+6)
= 8x+12
=8(228) + 12
=1836...... non of the answers
Please what is the correct approach?
let 2x be one of the numbers;
list: 2x-4, 2x-2, 2x, 2x+2, 2x+4, 2x+6
sum of the first four: (2x-4) + (2x-2) + (2x) + 2x+2)
--> 4x-4=908
x=228
sum of last four: 2x + (2x+2) + (2x+4) + (2x+6)
= 8x+12
=8(228) + 12
=1836...... non of the answers
Please what is the correct approach?
04 Aug 2010, 11:31
Kudos
Bookmarks
gmatbull
If the sum of the first four numbers in a list of six consecutive even numbers is 908,
what is the sum of the last four numbers in the list?
A. 912
B. 914
C. 916
D. 920
E. 924
I tried it, but got screwed up:
let 2x be one of the numbers;
list: 2x-4, 2x-2, 2x, 2x+2, 2x+4, 2x+6
sum of the first four: (2x-4) + (2x-2) + (2x) + 2x+2)
--> 4x-4=908
x=228
sum of last four: 2x + (2x+2) + (2x+4) + (2x+6)
= 8x+12
=8(228) + 12
=1836...... non of the answers
Please what is the correct approach?
Let the six consecutive even numbers be \(x\), \(x+2\), \(x+4\), \(x+6\), \(x+8\), \(x+10\).what is the sum of the last four numbers in the list?
A. 912
B. 914
C. 916
D. 920
E. 924
I tried it, but got screwed up:
let 2x be one of the numbers;
list: 2x-4, 2x-2, 2x, 2x+2, 2x+4, 2x+6
sum of the first four: (2x-4) + (2x-2) + (2x) + 2x+2)
--> 4x-4=908
x=228
sum of last four: 2x + (2x+2) + (2x+4) + (2x+6)
= 8x+12
=8(228) + 12
=1836...... non of the answers
Please what is the correct approach?
Given: \(x+(x+2)+(x+4)+(x+6)=4x+12=908\). Question: \((x+4)+(x+6)+(x+8)+(x+10)=4x+28=?\)
\((x+4)+(x+6)+(x+8)+(x+10)=4x+28=(4x+12)+16=908+16=924\).
Answer: E.
The way you are doing is also valid. You've just made an error in calculations, plus no need even number to be \(2x\) it can be just even \(x\).
But anyway your approach:
Sum of the first four: \((2x-4)+(2x-2)+(2x)+(2x+2)=8x-4=908\);
Sum of the last four: \(2x+(2x+2)+(2x+4)+(2x+6)=8x+12=(8x-4)+16=908+16=924\).
Hope it's clear.
General Discussion
04 Aug 2010, 12:11
Kudos
Bookmarks
oh, thanks Bunuel for the corrections.
Hope you aren't tired of receiving kudos; you know, people like you have made
kudos a trite, and one simply wonders what else to give.
Methinks, there should be a different category of kudos for genius such as Bunuel.
If I may ask, please what was you GMAT score like?
Hope you aren't tired of receiving kudos; you know, people like you have made
kudos a trite, and one simply wonders what else to give.
Methinks, there should be a different category of kudos for genius such as Bunuel.
If I may ask, please what was you GMAT score like?
