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I went with B initially but after reading your query its clear that the right answer should be "BOTH B & E" as the question asks about which "could" be the value of x....Both are equally possible values of x and hence, this may be one of those questions which doesn't have the right answer choice....

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I agree. Though a bit odd for us but the GMAT convention is in fact what you have said...:)
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pohkid
If x > 0.9, which of the following could be the value of x?

A. √0.81
B. √0.9
C. (0.9)2
D. (0.9)(0.99)
E. 1 - √0.01

If you decide to choose B, please tell me why E doesn't work, since the \sqrt{0.01} can be negative and the entire answer choice becomes greater than 1. However, B can be negative, which is smaller than 0.9.

You are missing a critical point here:

\(\sqrt{x}\) implies the principal square root i.e. the positive square root of x only.

For example:
\(\sqrt{9} = 3\) only.
\(\sqrt{9}\) is not -3.

When the question wants the negative square root, it will be written as \(-\sqrt{9} = -3\).

It might be against what you might have learnt in school but by convention (and certainly as far as GMAT is concerned), \(\sqrt{x}\) implies the positive square root only.

On the same lines, \(\sqrt{x^2} = |x|\) (only the positive value of x)

Therefore, √0.9 is a positive value greater than 0.9
and √0.01 has only one value which is 0.1 so option (E) becomes 1-0.1 = 0.9. It is not greater than 0.9

Answer (B) only.

Thanks for your explanation. Would you say on the GMAT, we would always care about the positive root only and ignore the negative root?
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pohkid
If x > 0.9, which of the following could be the value of x?

A. √0.81
B. √0.9
C. (0.9)2
D. (0.9)(0.99)
E. 1 - √0.01

If you decide to choose B, please tell me why E doesn't work, since the \sqrt{0.01} can be negative and the entire answer choice becomes greater than 1. However, B can be negative, which is smaller than 0.9.

You are missing a critical point here:

\(\sqrt{x}\) implies the principal square root i.e. the positive square root of x only.

For example:
\(\sqrt{9} = 3\) only.
\(\sqrt{9}\) is not -3.

When the question wants the negative square root, it will be written as \(-\sqrt{9} = -3\).

It might be against what you might have learnt in school but by convention (and certainly as far as GMAT is concerned), \(\sqrt{x}\) implies the positive square root only.

On the same lines, \(\sqrt{x^2} = |x|\) (only the positive value of x)

Therefore, √0.9 is a positive value greater than 0.9
and √0.01 has only one value which is 0.1 so option (E) becomes 1-0.1 = 0.9. It is not greater than 0.9

Answer (B) only.

HI, Thanks for the explanation. I seem to be missing another critical point.
Why can't the answer be C? (0.9)2 = 1.8
1.8 > 0.9
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sm1510
VeritasPrepKarishma
pohkid
If x > 0.9, which of the following could be the value of x?

A. √0.81
B. √0.9
C. (0.9)2
D. (0.9)(0.99)
E. 1 - √0.01

If you decide to choose B, please tell me why E doesn't work, since the \sqrt{0.01} can be negative and the entire answer choice becomes greater than 1. However, B can be negative, which is smaller than 0.9.

You are missing a critical point here:

\(\sqrt{x}\) implies the principal square root i.e. the positive square root of x only.

For example:
\(\sqrt{9} = 3\) only.
\(\sqrt{9}\) is not -3.

When the question wants the negative square root, it will be written as \(-\sqrt{9} = -3\).

It might be against what you might have learnt in school but by convention (and certainly as far as GMAT is concerned), \(\sqrt{x}\) implies the positive square root only.

On the same lines, \(\sqrt{x^2} = |x|\) (only the positive value of x)

Therefore, √0.9 is a positive value greater than 0.9
and √0.01 has only one value which is 0.1 so option (E) becomes 1-0.1 = 0.9. It is not greater than 0.9

Answer (B) only.

HI, Thanks for the explanation. I seem to be missing another critical point.
Why can't the answer be C? (0.9)2 = 1.8
1.8 > 0.9

It's (0.9)^2 = 0.81 < 0.9 not (0.9)*2. Edited the stem.
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Bunuel
sm1510

HI, Thanks for the explanation. I seem to be missing another critical point.
Why can't the answer be C? (0.9)2 = 1.8
1.8 > 0.9

It's (0.9)^2 = 0.81 < 0.9 not (0.9)*2. Edited the stem.

Great! Makes much more sense now. We could also use the process of elimination and eliminate all other options that equal to 0.9 or are <0.9

That's if someone, like me, were confused about the root of 0.9

Thanks :)
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x > 0.9

10x > 9

If the value of x comes up 1 or greater than 1, then the above equation hold true

\(\sqrt{0.81} = 0.9\) > will not satisfy

\(\sqrt{0.90} = \sqrt{\frac{9}{10}} = \frac{3}{\sqrt{10}}\) > Answer would be greater than 1

Answer = B
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EMPOWERgmatRichC
Hi All,

This question is built around a great Number Property rule that you might see on Test Day (although its usage is relatively rare).

When dealing with positive fractions (0 < X < 1).....what happens when you SQUARE a positive fraction?

eg
(1/3)^2 = (1/3)(1/3) = 1/9

Squaring a positive fraction makes the result SMALLER.

Since "squaring" and "square-rooting" are 'opposite' functions, what happens when you SQUARE-ROOT a positive fraction?

√(1/9) = √(1)/√(9) = 1/3

Square-rooting a positive fraction makes the result BIGGER.

In this question, you'll notice that the answer choices revolve around the use of 0.9

I want to focus on Answers B and C

Without doing the math, what happens when you SQUARE 0.9.....? The result will get SMALLER.
Without doing the math, what happens when you SQAURE ROOT 0.9....? The result will get BIGGER.

Since the question is asking which of the following values could be X (meaning....could be greater than 0.9), we don't have to do any more work...

Final Answer:
GMAT assassins aren't born, they're made,
Rich

You sir, are a legend.... Thanks a bunch
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Does anyone know what source this question comes from? OG, Kaplan, Veritas?
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pohkid
If x > 0.9, which of the following could be the value of x?

A. √0.81
B. √0.9
C. (0.9)^2
D. (0.9)(0.99)
E. 1 - √0.01


We are given that x > 0.9 and need to determine a value for x.

We may recall that when we take the square root of a decimal that is between 0 and 1, the result is larger than the original number inside the root. Thus, since √0.9 > 0.9, we know that √0.9 could be x.

Answer: B
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