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07 Feb 2022, 08:15
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B
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If \(x \neq 0\), let \(♠ x\) be defined by the equation \(♠x = x-\frac{1}{x}\). Then \(♠(-3) =\)
A. -10/3
B. -8/3
C. 0
D. 8/3
E. 10/3
A. -10/3
B. -8/3
C. 0
D. 8/3
E. 10/3
07 Feb 2022, 08:28
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Bunuel
If \(x \neq 0\), let \(♠ x\) be defined by the equation \(♠x = x-\frac{1}{x}\). Then \(♠(-3) =\)
A. -10/3
B. -8/3
C. 0
D. 8/3
E. 10/3
A. -10/3
B. -8/3
C. 0
D. 8/3
E. 10/3
Replace all the x's with \(-3\). Then \(♠(-3) = (-3) - \frac{1}{(-3)} = -3 + \frac{1}{3} = -\frac{9}{3} + \frac{1}{3} = -\frac{8}{3}\)
Answer: B
07 Feb 2022, 09:52
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Explanation:
\(♠ x\) be defined by the equation \(♠x = x-\frac{1}{x}\).
\(♠(-3) =\) \( -3 -\frac{1}{(-3)}\)
= -3 + (1/3)
= (-9+1) / 3
= -8/3
IMO-B
\(♠ x\) be defined by the equation \(♠x = x-\frac{1}{x}\).
\(♠(-3) =\) \( -3 -\frac{1}{(-3)}\)
= -3 + (1/3)
= (-9+1) / 3
= -8/3
IMO-B
