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If x ≠ –1 and y ≠ ±1, then what is the value of (xy)^2 − x^2/(x + 1)(y

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If x ≠ –1 and y ≠ ±1, then what is the value of (xy)^2 − x^2/(x + 1)(y [#permalink]

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New post 28 May 2017, 01:47
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  25% (medium)

Question Stats:

74% (00:59) correct 26% (01:31) wrong based on 53 sessions

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Re: If x ≠ –1 and y ≠ ±1, then what is the value of (xy)^2 − x^2/(x + 1)(y [#permalink]

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New post 28 May 2017, 06:00
The expression after simplication will become
\(\frac{(x^2)}{(x+1)}\)

1. Have a unique value of x will yield a unique value for the expression. Sufficient.
2. Knowing the value of y has no impact on the outcome of the expression.
We necessarily need to know the value of x. Hence, insufficient. (Option A)
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Re: If x ≠ –1 and y ≠ ±1, then what is the value of (xy)^2 − x^2/(x + 1)(y [#permalink]

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New post 19 Sep 2017, 08:30
How do you do the simplification?
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Re: If x ≠ –1 and y ≠ ±1, then what is the value of (xy)^2 − x^2/(x + 1)(y [#permalink]

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New post 19 Sep 2017, 08:53
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Suchilou wrote:
How do you do the simplification?


Hi Suchilou

the equation can be written as \(\frac{(x^2y^2-x^2)}{(x+1)(y^2-1)}\)

Tasking \(x^2\) as common, you get \(\frac{x^2(y^2-1)}{(x+1)(y^2-1)}\)

Solve this to get
\(\frac{x^2}{(x+1)}\)

Hence by knowing the value of \(x\), you can solve the question
Re: If x ≠ –1 and y ≠ ±1, then what is the value of (xy)^2 − x^2/(x + 1)(y   [#permalink] 19 Sep 2017, 08:53
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