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If x and k are both integers, x > k, and x−k = 625, what is x? (1) k
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20 May 2017, 08:25
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If x and k are both integers, x > k, and \(x^{−k} = 625\), what is x? (1) k is a prime number (2) x + k > 20
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Re: If x and k are both integers, x > k, and x−k = 625, what is x? (1) k
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20 May 2017, 08:33
hazelnut wrote: If x and k are both integers, x > k, and \(x^{−k} = 625\), what is x?
(1) k is a prime number (2) x + k > 20 Interesting problem! The first thing I noticed is that the question itself really limits the possibilities. There can't be that many integers where \(x^{−k} = 625\), right? Also, I know 625 as a 'special number'  you should memorize the perfect squares up to about 25^2, so that you notice things like this quickly on test day. 625 = 25^2, so I immediately know one of the possibilities. x could be 25, and k could be 2. (Note the 'double negative' there). However, you should never be able to solve a DS question without either statement. That's something that never happens on DS. So, there must be at least one possibility. The GMAT likes to trick you into forgetting about the simplest exponent of all: 1. x could be 625, and k could be 1. Also, notice that 25 can be factored down more. 25^2 = 5^4. So, finally, x could be 5, and k could be 4. List the three possibilities on your paper: x = 25, k = 2 x = 625, k = 1 x = 5, k = 4 Then, start working with the statements. Your question to ask yourself: do the statements let me 'narrow it down' to just one of these possibilities? (1) does exactly that. 2 is the only prime value for k in our list. So, if we know that k is prime, then the first possibility is the only one that works. (1) is sufficient. (2) is insufficient, because the first two possibilities could both work. (They're really hoping that you don't think of x = 625, k=1. If you didn't think of that, you'd think this was sufficient as well.)
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Re: If x and k are both integers, x > k, and x−k = 625, what is x? (1) k
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22 Aug 2017, 02:20
ccooley wrote: hazelnut wrote: If x and k are both integers, x > k, and \(x^{−k} = 625\), what is x?
(1) k is a prime number (2) x + k > 20 Interesting problem! The first thing I noticed is that the question itself really limits the possibilities. There can't be that many integers where \(x^{−k} = 625\), right? Also, I know 625 as a 'special number'  you should memorize the perfect squares up to about 25^2, so that you notice things like this quickly on test day. 625 = 25^2, so I immediately know one of the possibilities. x could be 25, and k could be 2. (Note the 'double negative' there). However, you should never be able to solve a DS question without either statement. That's something that never happens on DS. So, there must be at least one possibility. The GMAT likes to trick you into forgetting about the simplest exponent of all: 1. x could be 625, and k could be 1. Also, notice that 25 can be factored down more. 25^2 = 5^4. So, finally, x could be 5, and k could be 4. List the three possibilities on your paper: x = 25, k = 2 x = 625, k = 1 x = 5, k = 4 Then, start working with the statements. Your question to ask yourself: do the statements let me 'narrow it down' to just one of these possibilities? (1) does exactly that. 2 is the only prime value for k in our list. So, if we know that k is prime, then the first possibility is the only one that works. (1) is sufficient. (2) is insufficient, because the first two possibilities could both work. (They're really hoping that you don't think of x = 625, k=1. If you didn't think of that, you'd think this was sufficient as well.) x can be a negative number.. so it can be equal to 5 no? which means that there are two options for the first statement.



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Re: If x and k are both integers, x > k, and x−k = 625, what is x? (1) k
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22 Aug 2017, 02:23
tinayni552 wrote: ccooley wrote: hazelnut wrote: If x and k are both integers, x > k, and \(x^{−k} = 625\), what is x?
(1) k is a prime number (2) x + k > 20 Interesting problem! The first thing I noticed is that the question itself really limits the possibilities. There can't be that many integers where \(x^{−k} = 625\), right? Also, I know 625 as a 'special number'  you should memorize the perfect squares up to about 25^2, so that you notice things like this quickly on test day. 625 = 25^2, so I immediately know one of the possibilities. x could be 25, and k could be 2. (Note the 'double negative' there). However, you should never be able to solve a DS question without either statement. That's something that never happens on DS. So, there must be at least one possibility. The GMAT likes to trick you into forgetting about the simplest exponent of all: 1. x could be 625, and k could be 1. Also, notice that 25 can be factored down more. 25^2 = 5^4. So, finally, x could be 5, and k could be 4. List the three possibilities on your paper: x = 25, k = 2 x = 625, k = 1 x = 5, k = 4 Then, start working with the statements. Your question to ask yourself: do the statements let me 'narrow it down' to just one of these possibilities? (1) does exactly that. 2 is the only prime value for k in our list. So, if we know that k is prime, then the first possibility is the only one that works. (1) is sufficient. (2) is insufficient, because the first two possibilities could both work. (They're really hoping that you don't think of x = 625, k=1. If you didn't think of that, you'd think this was sufficient as well.) x can be a negative number.. so it can be equal to 5 no? which means that there are two options for the first statement. Notice that we are given that x > k, so x cannot be 5 if k = 2.
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Re: If x and k are both integers, x > k, and x−k = 625, what is x? (1) k
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22 Aug 2017, 02:35
tinayni552 wrote: ccooley wrote: hazelnut wrote: If x and k are both integers, x > k, and \(x^{−k} = 625\), what is x?
(1) k is a prime number (2) x + k > 20 Interesting problem! The first thing I noticed is that the question itself really limits the possibilities. There can't be that many integers where \(x^{−k} = 625\), right? Also, I know 625 as a 'special number'  you should memorize the perfect squares up to about 25^2, so that you notice things like this quickly on test day. 625 = 25^2, so I immediately know one of the possibilities. x could be 25, and k could be 2. (Note the 'double negative' there). However, you should never be able to solve a DS question without either statement. That's something that never happens on DS. So, there must be at least one possibility. The GMAT likes to trick you into forgetting about the simplest exponent of all: 1. x could be 625, and k could be 1. Also, notice that 25 can be factored down more. 25^2 = 5^4. So, finally, x could be 5, and k could be 4. List the three possibilities on your paper: x = 25, k = 2 x = 625, k = 1 x = 5, k = 4 Then, start working with the statements. Your question to ask yourself: do the statements let me 'narrow it down' to just one of these possibilities? (1) does exactly that. 2 is the only prime value for k in our list. So, if we know that k is prime, then the first possibility is the only one that works. (1) is sufficient. (2) is insufficient, because the first two possibilities could both work. (They're really hoping that you don't think of x = 625, k=1. If you didn't think of that, you'd think this was sufficient as well.) x can be a negative number.. so it can be equal to 5 no? which means that there are two options for the first statement. Thanks! I should be more careful when reading the stem



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If x and k are both integers, x > k, and x−k = 625, what is x? (1) k
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22 Aug 2017, 05:02
Bunuel wrote: If x and k are both integers, x > k, and \(x^{−k} = 625\), what is x?
(1) k is a prime number (2) x + k > 20 Hi Bunuel here how i saw statement (1) k is a prime number But k can be 2 or 2. So when k = 2 and when k = 2 the equation \(x^{−k} = 625\) should give different results ! What am I missing here ? Regards Sandy da Silva
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Re: If x and k are both integers, x > k, and x−k = 625, what is x? (1) k
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22 Aug 2017, 06:05
sandysilva wrote: Bunuel wrote: If x and k are both integers, x > k, and \(x^{−k} = 625\), what is x?
(1) k is a prime number (2) x + k > 20 Hi Bunuel here how i saw statement (1) k is a prime number But k can be 2 or 2. So when k = 2 and when k = 2 the equation \(x^{−k} = 625\) should give different results ! What am I missing here ? Regards Sandy da Silva Not sure I understand what you mean. We have the following possible cases for \(x^{−k} = 625\): x = 25, k = 2 x = 625, k = 1 x = 5, k = 4 (1) says: k is a prime number, thus k = 2 and x = 25.
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New to the Math Forum? Please read this: Ultimate GMAT Quantitative Megathread  All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
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Re: If x and k are both integers, x > k, and x−k = 625, what is x? (1) k
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19 Dec 2017, 14:21
Hi All, In certain DS questions, the prompt significantly limits the possible answers (before you even consider the information in the two Facts). By determining those limited options right from the start, you'll find that the rest of the work needed to answer the question can be done rather quickly. Here, we're told that X and K are both INTEGERS, that X > K and that X^{K} = 625. We're asked for the value of X. To start, there are not that many ways to raise an INTEGER to an INTEGER power and get 625; considering that X must be GREATER than K, it's even more limited  there are only 3 ways to do it: X = 625, K = 1 X = 25, K = 2 X = 5, K = 4 1) K is a prime number Given the above three options, there's only one option that 'fits' Fact 1: X = 25, K = 2 Fact 1 is SUFFICIENT 2) X + K > 20 With Fact 2, there are two options (X = 25, K= 2 and X = 625, K = 1) Fact 2 is INSUFFICIENT Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: If x and k are both integers, x > k, and x−k = 625, what is x? (1) k
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20 Dec 2017, 04:38
case 1: x^k=25^2 case 2: x^k=5^4 case 3: x^k=625^1 (1) x is a prime, so only case 1 applies ===> x=25 (2) case 1 & 3 apply: 252=23 6251=624
Answer A.




Re: If x and k are both integers, x > k, and x−k = 625, what is x? (1) k &nbs
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20 Dec 2017, 04:38






