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If X is the set of prime single-digit numbers and Y is a set containin

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If X is the set of prime single-digit numbers and Y is a set containin  [#permalink]

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New post 28 Oct 2016, 01:00
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

84% (01:06) correct 16% (01:33) wrong based on 32 sessions

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Joined: 06 Jun 2016
Posts: 250
Location: India
Concentration: Operations, Strategy
Schools: ISB '18 (D)
GMAT 1: 600 Q49 V23
GMAT 2: 680 Q49 V34
GPA: 3.9
Re: If X is the set of prime single-digit numbers and Y is a set containin  [#permalink]

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New post 28 Oct 2016, 01:08
Bunuel wrote:
If X is the set of prime single-digit numbers and Y is a set containing each of the numbers in set X raised to the power of 2, how much greater is the median of set Y than the median of set X?

A. 2
B. 4
C. 9
D. 13
E. 17


IMO D
set X={2,3,5,7} set of prime single digit numbers
set Y={4,9.25.49} each of the numbers in set X raised to the power of 2
Median set X= (3+5)/2= 4
Median set Y= (9+25)/2= 17
Required set Y - set X= 13
Hence D
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Re: If X is the set of prime single-digit numbers and Y is a set containin  [#permalink]

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New post 27 Nov 2019, 12:13
Bunuel wrote:
If X is the set of prime single-digit numbers and Y is a set containing each of the numbers in set X raised to the power of 2, how much greater is the median of set Y than the median of set X?

A. 2
B. 4
C. 9
D. 13
E. 17


We see that X = {2, 3, 5, 7} and Y = {4, 9, 25 49}. Therefore, the median of set X is (3 + 5)/2 = 4, and that of set Y is (9 + 25)/2 = 17. So the median of set Y is 17 - 4 = 13 greater than the median of set X.

Answer: D
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Re: If X is the set of prime single-digit numbers and Y is a set containin   [#permalink] 27 Nov 2019, 12:13
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