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If z is a positive integer and r is the remainder when z^2 + 2z + 4 is

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Kudos [?]: 135541 [1], given: 12697

If z is a positive integer and r is the remainder when z^2 + 2z + 4 is [#permalink]

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31 Aug 2017, 22:14
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If z is a positive integer and r is the remainder when z^2 + 2z + 4 is divided by 8, what is the value of r?[/b]

(1) When (z−3)^2 is divided by 8, the remainder is 4.

(2) When 2z is divided by 8, the remainder is 2.
[Reveal] Spoiler: OA

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Kudos [?]: 135541 [1], given: 12697

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If z is a positive integer and r is the remainder when z^2 + 2z + 4 is [#permalink]

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31 Aug 2017, 22:48
Bunuel wrote:
If z is a positive integer and r is the remainder when z^2 + 2z + 4 is divided by 8, what is the value of r?

(1) When (z−3)^2 is divided by 8, the remainder is 4.

(2) When 2z is divided by 8, the remainder is 2.

A positive number $$x$$ has the remainder $$\{0, \pm 1, \pm 2, \pm 3, \pm 4\}$$ when divided by 8, hence $$x^2$$ has the remainder $$\{0, 1, 4, 9, 16\}$$ or $$\{0, 1, 4, 1, 0\}$$ or $$\{0, 1, 4\}$$ when divided by 8.

We have $$z^2+2z+4=(z+1)^2+3$$.

Since $$(z+1)^2$$ has the remainder $$\{0, 1, 4\}$$ when divided by 8,
$$(z+1)^2+3$$ has the remainder $$\{3, 4, 7\}$$ when divided by 8, or r could be $$\{3, 4, 7\}$$.

(1) If $$(z-3)^2$$ has the remainder 4 when divided by 8, then $$z-3$$ has the remainder $$\pm 2$$ or $$z$$ has the remainder 1 or 5.

If $$z$$ has the remainder 1, we have $$r=4$$.
If $$z$$ has the remainder 5, we have $$r=1$$.

Insufficient.

(2) If $$2z$$ has the remainder 2, or 10, then $$z$$ has the remainder 1 or 5.

If $$z$$ has the remainder 1, we have $$r=4$$.
If $$z$$ has the remainder 5, we have $$r=1$$.

Insufficient.

Combine (1) and (2).

We still have 2 cases: $$z$$ has the remainder 1 or 5. Insufficient. Answer D.
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Re: If z is a positive integer and r is the remainder when z^2 + 2z + 4 is [#permalink]

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01 Sep 2017, 02:12
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Bunuel wrote:
If z is a positive integer and r is the remainder when z^2 + 2z + 4 is divided by 8, what is the value of r?[/b]

(1) When (z−3)^2 is divided by 8, the remainder is 4.

(2) When 2z is divided by 8, the remainder is 2.

(1)

This is not sufficient as we don't know what remainder we would get if z is divided by 8

(2)

From this we get -
2z = 8k + 2 (k is a constant)
z = 4k + 1

z^2 = (4k + 1)^2 = 16(k^2) + 8k + 1 -> as 16 and 8 are both divisible by 8 -> z^2 will give a remainder of 1 when divided by 8
2z as given gives a remainder of 2 when divided by 8
And constant 4 gives a remainder of 4 when divided by 8

Hence -
remainder((z^2 + 2z + 4)/8) = remainder(z^2/8) + remainder(2z/8) + remainder(4/8)
=1+2+4
=7

Hence (2) alone is sufficient but (1) is not

Hence (B) is correct

Kudos [?]: 7 [1], given: 4

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Joined: 21 Aug 2017
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Kudos [?]: 4 [2], given: 4

Re: If z is a positive integer and r is the remainder when z^2 + 2z + 4 is [#permalink]

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03 Sep 2017, 06:09
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If z is a positive integer and r is the remainder when z^2 + 2z + 4 is divided by 8, what is the value of r?[/b]
(1) When (z−3)^2 is divided by 8, the remainder is 4.
(2) When 2z is divided by 8, the remainder is 2.
Solution -
(1) (z-3)^2 = 8k+4
z^2 - 6z + 9 = 8k + 4
z^2 -6z + 8z + 9 = 8k + 8z + 4 (Adding "8z" on both sides)
z^2 +2z + 4 = 8(k+z) - 1
Therefore, r = "-1" i.e 7. SUFFICIENT

(2) 2z = 8p + 2
z = 4p + 1
z^2 = (4p + 1)^2 = 16p^2 + 8p + 1
So, z^2 + 2z + 4 = (16p^2 + 8p + 1) + (8p + 2) + (4) = 16p^2 + 16p + 7 = 16p(p+1) + 7
Therefore, r = "7". SUFFICIENT

Ans - D

Kudos [?]: 4 [2], given: 4

Re: If z is a positive integer and r is the remainder when z^2 + 2z + 4 is   [#permalink] 03 Sep 2017, 06:09
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