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Curly05
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AkamaiBrah
Brainless
12

how about 13. Since the square are in a row, there is no reason why the blue ones can't be in all of the odd positions.


Nah.. My reasoning is simple.

Since we must have one of each kind including ONE BLUE, we are left with 21 squares. And since we need to alternate colors, we can have another 11 BLUE maximum. Altogether we have 12 BLUES. This is true for any color ..

Am I missing some thing ?

:roll:
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Curly05
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Can an algebra formula be done listing out the possible squares? Remember, Brainless, we have about two minutes to get solution.

VT
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13 is correct.
Start with a blue. place a blue in every alternate position.
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Curly05
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How long it take you?
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also vote for 13

B_B_B_B_ .... _B

among all Bs there are enough free places to put G, Y, and R.

So, the maximum number of blue squares is the number of odds in 25.
13 odd+12 even

Thus, 13.
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Curly05
In 25 squares, each painted one of the solid colors red, green, yellow, or blue, are lined up side by side in a single row so that no two adjacent squares are the same color and there is at least one square of each color, what is the maximum possible number of blue squares?


Note the words in bold, in your question. Now once that is known, all one has to know is that there should be one more color apart from Blue to make sure that the color Blue does not come in adjacent boxes.

Finish!!!!!!!!!!!!!

You have the solution 13 :lol:
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If you count all the numbers
1.3.5.7,9, 11,13, 15, 17, 19, 21, 23, 25- there are 13.

But 3 out of every five squares is blue and there are 25 squares.

3 x
-- = ----
5 25

Why is this wrong?

There are x-squares
x -1 - stand for?
2x-1=26
x=13
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Why isn't my ratio working?
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Curly05
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Cmon, Akami, show me why ratio isn't working? :-D
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Victor,
The ratio is not working because:
In the first 5 sq., you have 3 blue sq
In the next 5 sq., you have 2 blue sq.
In the next 5 sq., you have 3 blue sq
In the next 5 sq., you have 2 blue sq.
In the next 5 sq., you have 3 blue sq

So, altogether u have 3+2+3+2+3= 13

Because the # of blue sq. is varying, your ratio is not working
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prakuda2000
Victor,
The ratio is not working because:
In the first 5 sq., you have 3 blue sq
In the next 5 sq., you have 2 blue sq.
In the next 5 sq., you have 3 blue sq
In the next 5 sq., you have 2 blue sq.
In the next 5 sq., you have 3 blue sq

So, altogether u have 3+2+3+2+3= 13

Because the # of blue sq. is varying, your ratio is not working


Victor,

You would have seen that yourself if you had made a little effort and drawn a picture....



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