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In a class election, 190 votes were cast of three candidates. Jake rec

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Joined: 02 Sep 2009
Posts: 64095
In a class election, 190 votes were cast of three candidates. Jake rec  [#permalink]

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07 Aug 2019, 02:39
00:00

Difficulty:

15% (low)

Question Stats:

83% (01:47) correct 17% (01:55) wrong based on 41 sessions

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(A) 32
(B) 88
(C) 70
(D) 80
(E) 90

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Joined: 28 Jun 2019
Posts: 470
Re: In a class election, 190 votes were cast of three candidates. Jake rec  [#permalink]

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07 Aug 2019, 03:02
Simon:X
Jack:2X + 6
3x -8+2x +6 +x=190
6x=192
X= 32
Option C

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GMAT 1: 650 Q49 V31
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Re: In a class election, 190 votes were cast of three candidates. Jake rec  [#permalink]

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07 Aug 2019, 03:08
total =190
J+a+S=190
j+A=190-s.....................(1)

J=2S+6............(2)
A=3S-8...............(3)

j+a=5S-2
equate with (1)
5s-2=190-s
s=32
j=70
c
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Re: In a class election, 190 votes were cast of three candidates. Jake rec  [#permalink]

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12 Aug 2019, 10:53
Bunuel wrote:

(A) 32
(B) 88
(C) 70
(D) 80
(E) 90

We can create the equations:

J + S + A = 190

and

J = 6 + 2S

and

A = 3S - 8

Substituting, we have:

6 + 2S + S + 3S - 8 = 190

6S = 192

S = 32

Thus, Jake received J = 6 + 2S = 6 + 64 = 70 votes.

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Re: In a class election, 190 votes were cast of three candidates. Jake rec  [#permalink]

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15 Oct 2019, 11:13
Bunuel wrote:

(A) 32
(B) 88
(C) 70
(D) 80
(E) 90

J=2S+6
A=3S-8

S+2S+6+3S-8=190
6S=192
S=32

J=(2*32)+6=70

Hence C
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Re: In a class election, 190 votes were cast of three candidates. Jake rec   [#permalink] 15 Oct 2019, 11:13