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In a class election, 190 votes were cast of three candidates. Jake rec

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In a class election, 190 votes were cast of three candidates. Jake rec  [#permalink]

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New post 07 Aug 2019, 03:39
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

86% (01:52) correct 14% (01:51) wrong based on 29 sessions

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Posts: 191
Re: In a class election, 190 votes were cast of three candidates. Jake rec  [#permalink]

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New post 07 Aug 2019, 04:02
Simon:X
Jack:2X + 6
Adam:3X - 8
3x -8+2x +6 +x=190
6x=192
X= 32
==》 Jack's votes are 2(32)+6=70
Option C

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Re: In a class election, 190 votes were cast of three candidates. Jake rec  [#permalink]

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New post 07 Aug 2019, 04:08
total =190
J+a+S=190
j+A=190-s.....................(1)

J=2S+6............(2)
A=3S-8...............(3)

adding (2) and (3)
j+a=5S-2
equate with (1)
5s-2=190-s
s=32
j=70
c
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Re: In a class election, 190 votes were cast of three candidates. Jake rec  [#permalink]

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New post 12 Aug 2019, 11:53
Bunuel wrote:
In a class election, 190 votes were cast of three candidates. Jake received 6 more votes than twice as many as Simon received, while Adam received 8 votes less than three times as many as Simon. How many votes did Jake receive?

(A) 32
(B) 88
(C) 70
(D) 80
(E) 90


We can create the equations:

J + S + A = 190

and

J = 6 + 2S

and

A = 3S - 8

Substituting, we have:

6 + 2S + S + 3S - 8 = 190

6S = 192

S = 32

Thus, Jake received J = 6 + 2S = 6 + 64 = 70 votes.

Answer: C
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Re: In a class election, 190 votes were cast of three candidates. Jake rec   [#permalink] 12 Aug 2019, 11:53
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