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EgmatQuantExpert
In a series of four cricket matches, the average number of runs scored by Jack and Jill is same. The number of runs scored by Jill in the four matches are 45, 72, 18 and 25 respectively. If Jack’s median score is 30 and his least score, in the series, is thrice his highest score of the series, then what is the highest score of Jack in the series?

    A. 25
    B. 30
    C. 60
    D. 75
    E. Cannot be determined

Avg of Jill is \(\frac{45 + 72 + 18 + 25}{4} = 40\)

Runs scored by Jack in Ascending Order be \(a + b + c + d\)

\(\frac{b + c}{2} = 30\)

Or, \(b + c = 60\)

Further \(a = 3d\)

So We have \(a + d + ( b + c ) = 160\)

Or, \(3d + d + 60 = 160\)

Or, \(4d = 100\)

Or, \(d = 25\)

Thus, Highest score must be 25*3 = 75 , Answer must be (D)
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Solution


Given:
    • Average runs scored by both Jack and Jill, in the series, is same
    • Runs scored by Jill in four matches = {45, 72, 18, 25}
    • Jack’s median score = 30
    • Jack’s highest score in the series = 3 * his least score in the series

To find:
    • The highest score of Jack in the series

Approach and Working:
    • Average runs scores by Jill = Sum of his scores in all matches/number of matches = \(\frac{(45 + 72 + 18 + 25)}{4}= \frac{160}{4} = 40\)
    • Average runs scored by Jack = \(\frac{Sum of his scores in all matches}{4}\)
    • Given, both averages are same
      o Which implies, \(\frac{sum of all Jack’s scores}{4} = 40\)
      o Thus, sum of Jack’s scores = 40 * 4 = 160

    • Let a, b, c, d be the scores of Jack in increasing order
    • Given, median score = 30
      o Implies, \(\frac{(b + c)}{2} =30\)
      o Thus, b + c = 60

    • And, we are also given that d = 3a
    • Sum of all scores of Jack =a + b + c + d = a + 60 + 3a = 160
      o Thus, \(a = \frac{100}{4} = 25\)

    • Therefore, the highest score of Jack in the series = 3 * 25 = 75

Hence, the correct answer is option D.

Answer: D

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Q should be changed to "his highest score, in the series, is thrice his lowest score of the series" ?
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EgmatQuantExpert

Solution


Given:
    • Average runs scored by both Jack and Jill, in the series, is same
    • Runs scored by Jill in four matches = {45, 72, 18, 25}
    • Jack’s median score = 30
    • Jack’s least score in the series = 3 * his highest score in the series

To find:
    • The highest score of Jack in the series

Approach and Working:
    • Average runs scores by Jill = Sum of his scores in all matches/number of matches = \(\frac{(45 + 72 + 18 + 25)}{4}= \frac{160}{4} = 40\)
    • Average runs scored by Jack = \(\frac{Sum of his scores in all matches}{4}\)
    • Given, both averages are same
      o Which implies, \(\frac{sum of all Jack’s scores}{4} = 40\)
      o Thus, sum of Jack’s scores = 40 * 4 = 160

    • Let a, b, c, d be the scores of Jack in increasing order
    • Given, median score = 30
      o Implies, \(\frac{(b + c)}{2} =30\)
      o Thus, b + c = 60

    • And, we are also given that d = 3a
    • Sum of all scores of Jack =a + b + c + d = a + 60 + 3a = 160
      o Thus, \(a = \frac{100}{4} = 25\)

    • Therefore, the highest score of Jack in the series = 3 * 25 = 75

Hence, the correct answer is option D.

Answer: D


Shouldn't the Question be "Highest Score is thrice the least Score"?? Moreover you have repeated this statement in your solution also. Am i not getting it right?
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pankajpatwari
Shouldn't the Question be "Highest Score is thrice the least Score"?? Moreover you have repeated this statement in your solution also. Am i not getting it right?

Yes, you are write. At first, I was confused as well. EgmatQuantExpert can you correct it, please, thanks.
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Hey mtambiev, pankajpatwari and pandeyashwin,

Thanks for pointing it out. We've made the necessary changes. :)
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EgmatQuantExpert
In a series of four cricket matches, the average number of runs scored by Jack and Jill is same. The number of runs scored by Jill in the four matches are 45, 72, 18 and 25 respectively. If Jack’s median score is 30 and his highest score, in the series, is thrice his least score of the series, then what is the highest score of Jack in the series?

    A. 25
    B. 30
    C. 60
    D. 75
    E. Cannot be determined


Since Jill’s total score of the 4 matches is 45 + 72 + 18 + 25 = 160, Jack’s total score of the 4 matches is also 160. Furthermore, since Jack’s median score is 30, the sum of his middle two scores is 60. Therefore, the sum of his lowest and highest scores is 100. We can create the equation where x is his lowest score:

x + 3x = 100

4x = 100

x = 25

Therefore, his highest score is 3(25) = 75.

Answer: D
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