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Originally posted by Curly05 on 09 Jul 2003, 09:18.
Last edited by Curly05 on 16 Jul 2003, 08:20, edited 1 time in total.
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In honor of Akami( Newport Beach, rich guy!)
What is the greatest amount of 4 * 4 squares that can be traced out along the existing line segments of the 8 by 8 checkerboard ?
You know what know what ETS is saying traced out means draw the lines along the 1 by 1 sq boards.
Math Master, great show, yep my author's English is pretty accurate actually, but I guess most math students would find such a problem unusual and thats what adds to the difficulty.
Then, x has 5 choices: 0,1,2,3,4. And, y has choices: 0,1,2,3,4
4. Therefore, by the Multiplication Principle {(x,y)| x,y=0,1,2,3,4} has 5*5=25 choices
Basically, these give you the starting out tracing points.
VT
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The simplest way to solve this is to draw a 4x4 square in the top-left-hand corner of the 8x8 square. NOw imaging sliding it over one square at a time to the right. ONce you get to the end, imagine sliding it one square at a time down. If you know how to count, you should be able to solve this problem.
The simplest way to solve this is to draw a 4x4 square in the top-left-hand corner of the 8x8 square. NOw imaging sliding it over one square at a time to the right. ONce you get to the end, imagine sliding it one square at a time down. If you know how to count, you should be able to solve this problem.
Not really. 8C4 is a big number and assumes that you can break up the 4x4 square into columns of 1. If you slide the 4x4 square across the top to the right, you can only move 4 times before hitting the other end.
Not really. 8C4 is a big number and assumes that you can break up the 4x4 square into columns of 1. If you slide the 4x4 square across the top to the right, you can only move 4 times before hitting the other end.
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Based on this method I get 36. Number of 4x4 sqares along the horizontal line is 6. Obviously, it will be agin 6 along the vertical line.
Not really. 8C4 is a big number and assumes that you can break up the 4x4 square into columns of 1. If you slide the 4x4 square across the top to the right, you can only move 4 times before hitting the other end.
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Akamai,
Why woudld we be able to move 4 times only? Wouldn't we be able to move 6 times? I thought while moving towards the right each time we would consider the second set of TWO small vertical squares part of our next 4x4 configuration. Please clarify. Thanks
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Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.