In one 30 day month, Joeś computer store sold computers at their regul

In one 30 day month, Joeś computer store sold computers at their regular price for the first 15 days of the month but then sold them at a 50 percent discount off the regular price for the last 15 days of the month. If Joeś revenue for the month was $18000, how much revenue was earned from selling computers at the discounted price?


(1) The revenue earned from the sale of computers at regular price was 100 percent greater than the revenue earned from the sale of computers at the discounted price

(2) The number of computers sold at the regular price was equal to the number of computers sold at a discounted price.

As i don't know the approach, I'll make an educated guess.

To find the revenue earned from selling computers at discounted price, we need the no. of computers sold at regular price.
Total revenue = revenue at regular price + revenue at discounted, 50%, price
Revenue = no. of computers sold * price/unit

As we don't know no. of computers sold nor price/computer sold at discounted price from both statements and the desired answer is unique. So, both conditions together also not sufficient.

Imo. E

let computer sold at regular price = a and discounted price = b
price of regular price = x and discounted = .5x
given revenue
ax+.5xb = 18,000

finde .5xb

#1

The revenue earned from the sale of computers at regular price was 100 percent greater than the revenue earned from the sale of computers at the discounted price

ax=2*.5xb
ax=xb
so
1.5xb = 18,000
xb = 12,000
.5xb = 6,000
sufficient
#2
The number of computers sold at the regular price was equal to the number of computers sold at a discounted price.
i.e a=b
so
ax+.5xb = 18,000
1.5xb = 18,000
xb = 12,000
.5xb = 6,000
sufficient
IMO D


In one 30 day month, Joeś computer store sold computers at their regular price for the first 15 days of the month but then sold them at a 50 percent discount off the regular price for the last 15 days of the month. If Joeś revenue for the month was $18000, how much revenue was earned from selling computers at the discounted price?


(1) The revenue earned from the sale of computers at regular price was 100 percent greater than the revenue earned from the sale of computers at the discounted price

(2) The number of computers sold at the regular price was equal to the number of computers sold at a discounted price.

pa+(0.5p)b=18k

(1) The revenue earned from the sale of computers at regular price was 100 percent greater than the revenue earned from the sale of computers at the discounted price sufic

pa/(0.5p)b=2, pa=2(0.5p)b, pa=pb, a=b;
pa+(0.5p)b=18k, pa+0.5pa=18k, pa=18k/1.5; 0.5pb=0.5pa=0.5(18k/1.5).

(2) The number of computers sold at the regular price was equal to the number of computers sold at a discounted price. sufic

a=b, pa+(0.5p)b=18k, pa+0.5pa=18k, pa=18k/1.5; 0.5pb=0.5pa=0.5(18k/1.5).

Ans (D)

In one 30 day month, Joeś computer store sold computers at their regular price for the first 15 days of the month but then sold them at a 50 percent discount off the regular price for the last 15 days of the month. If Joeś revenue for the month was $18000, how much revenue was earned from selling computers at the discounted price?
Let revenue at regular price =r1
Price =p
Quantity = q1

Let revenue at discounted price = r2
Price =0.5p
Quantity = q2
Asked: r2 ?

Days | | revenue |
15 | p•q | r1 |
15 | 0.5p•q | r2 |
Total | | 18000 |
.: r1+r2 =18000

(1) The revenue earned from the sale of computers at regular price was 100 percent greater than the revenue earned from the sale of computers at the discounted price
Says r1 =2(r2)
.: 2(r2)+ r2 = 18000 —> r2 = 6000
(Sufficient)

(2) The number of computers sold at the regular price was equal to the number of computers sold at a discounted price.
Says q1 =q2
Let quantity sold = 2 units
p•2 = r1 , 0.5p•2 = r2
2p = r1 , p= r2
.: 3p =18000 —-> p= 6000
r2 = 6000 (Sufficient)

Hit that D

Posted from my mobile device

H1= Revenue for first 15 days
H2= Revenue for second 15 days (unit price at 50% discount)
18000 = H1 + H2.

Q. H2?

1) H1=2*H2 --> 18000= 2*H2 + H2
H2=6000
SUFFICIENT

2) If the number of computers sold at the regular price is equal to the number of computers sold at a discounted (or half) price, then the revenue earned from selling computer at full price (H1) is clearly twice the revenue earned from selling computer at half price (H2).
H1=2*H2 --> 18000= 2*H2 + H2
H2=6000
SUFFICIENT

FINAL ANSWER IS (D)

Posted from my mobile device

Let Regular price for a computer be y, and the discounted price for a computer be x. Then from the question, x=0.5y => y=2x ------(1)
Let revenue earned from regular sales be Rr and revenue earned from discounted sales be Rd.
Then Rr+Rd=18,000 --------(2)
We are to determine the revenue earned from the discounted sales.

(1) The revenue earned from the sale of computers at regular price was 100 percent greater than the revenue earned from the sale of computers at the discounted price
Basically, statement 1 says that, Rr = 2Rd -----(3)
This is sufficient because we know 3Rd=18,000 hence Rd = $6,000.00.

(2) The number of computers sold at the regular price was equal to the number of computers sold at a discounted price
Statement 2 is saying that if 100 computers were sold over the period, then 50 were sold at regular prices and 50 were sold at discounted prices.
50y+50x=18,000 but from (1) y=2x
Hence 150x=18,000
x=120.
Knowing x=120, we can determine Rd=120*50 = $6,000.00
Statement 2 is also sufficient.

The answer is D.

In one 30 day month, Joeś computer store sold computers at their regular price for the first 15 days of the month but then sold them at a 50 percent discount off the regular price for the last 15 days of the month. If Joeś revenue for the month was $18000, how much revenue was earned from selling computers at the discounted price?

Let number of computers sold in first 15 days = x
number of computers sold in last 15 days = y
Selling price of computer sold in first 15 days = p
Now, \(xp + \frac{yp}{2} = 18000\)
\(\frac{yp}{2} = ?\)

(1) The revenue earned from the sale of computers at regular price was 100 percent greater than the revenue earned from the sale of computers at the discounted price
\(xp = \frac{yp}{2} + \frac{100}{100}*\frac{yp}{2}\)
So,
\(\frac{yp}{2} + \frac{100*yp}{100*2} + \frac{yp}{2} = 18000\)
\(\frac{yp}{2} = \frac{18000}{3} = 6000\)

SUFFICIENT.

(2) The number of computers sold at the regular price was equal to the number of computers sold at a discounted price.
x = y
So,
\(yp + \frac{yp}{2} = 18000\)
\(\frac{yp}{2} = \frac{18000}{3}\) = 6000

SUFFICIENT.

Answer D.

Let x be the regular price
--> a - the # of computers sold for the first 15 days.
--> b - the # of computers sold for the next 15 days.

\(ax+ b(\frac{x}{2})= 18000\)
--> \(b(\frac{x}{2})=\) ???

(Statement1): The revenue earned from the sale of computers at regular price was 100 percent greater than the revenue earned from the sale of computers at the discounted price
--> \(ax= b(\frac{x}{2})+ b(\frac{x}{2})\)
ax = bx --> a=b

\(ax+ b(\frac{x}{2})= 18000\) --> \(bx+b(\frac{x}{2})=b(\frac{3x}{2})= 18000\)--> \(b(\frac{x}{2})= 6000\)
Sufficient

(Statement2): The number of computers sold at the regular price was equal to the number of computers sold at a discounted price.
a=b --> \(ax+ b(\frac{x}{2})= 18000\)--> \(b(\frac{3x}{2})= 18000\) --> \(b(\frac{x}{2})= 6000\)
Sufficient

The answer is D.

In one 30 day month, Joeś computer store sold computers at their regular price for the first 15 days of the month but then sold them at a 50 percent discount off the regular price for the last 15 days of the month. If Joeś revenue for the month was $18000, how much revenue was earned from selling computers at the discounted price?


(1) The revenue earned from the sale of computers at regular price was 100 percent greater than the revenue earned from the sale of computers at the discounted price

(2) The number of computers sold at the regular price was equal to the number of computers sold at a discounted price

1) The ratio of revenues from regular priced computers and discounted computers are given (2 : 1). We can tell the revenue from the sale of computers at the discounted price, which is $6,000. sufficient.

2) Since the quantities are same, so the revenue from the regular priced computers are twice of the revenue from the sale of discounted priced computers. Same info as 1. So, sufficient.

D is the answer.

Let Regular price be x and discounted price be x/2
Units sold at regular price = N and at discounted price be M

Total revenue = x*N + (x/2)*M = 18000 ------(i)

To calculate : (x/2)*M??
(1) The revenue earned from the sale of computers at regular price was 100 percent greater than the revenue earned from the sale of computers at the discounted price
x*N = 200% of (x/2)*M = x*M -----(ii)
Substituting in (i), value of (x/2)*M can be calculated. Sufficient

(2) The number of computers sold at the regular price was equal to the number of computers sold at a discounted price.
N = M -----(iii)
From (i) and (iii), (x/2)*M can be calculated
Sufficient

D is correct

sells computers.. where does it say that these computers come at 1 price.. 1) is perfect because you dont care how much an item costs.. 2) is sooo weak.. there may be different prices and when at 100% people take only the cheap ones and when 50% people take the ones with the higher price..