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In the diagram above, O is the center of the circle and ACDE is a squa

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In the diagram above, O is the center of the circle and ACDE is a squa  [#permalink]

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New post 15 Oct 2019, 23:41
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

77% (01:19) correct 23% (02:03) wrong based on 26 sessions

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GMAT 1: 580 Q41 V28
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Re: In the diagram above, O is the center of the circle and ACDE is a squa  [#permalink]

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New post 15 Oct 2019, 23:54
In the diagram above, O is the center of the circle and ACDE is a square. What is the area of the square?


(1) the circle has a radius of 2

(2) angle ACB = 90°


Answer : The Correct answer should be (A) -> Option (1) is sufficient


- AB is the diameter, so Angle ACB must be 90degree

- OA=OB=2, Thus, Dia AOB =4, BC =3, Angle ACB =90Degree, So we can find the value of AC

- All sides are equal for Square. Hence Area can be evaluated from a^2 ( a - length of each side)
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Re: In the diagram above, O is the center of the circle and ACDE is a squa  [#permalink]

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New post 16 Oct 2019, 01:20
Bunuel wrote:
Image
In the diagram above, O is the center of the circle and ACDE is a square. What is the area of the square?


(1) the circle has a radius of 2

(2) angle ACB = 90°

Attachment:
GMAT_DS_Magoosh_161.png


Angle in a semi-circle is 90 deg
--> Triangle ACB is right angled
--> \(AB^2 = AC^2 + BC^2\)
--> \(AC^2 = AB^2 - 9\)
--> \(AC = \sqrt{AB^2 - 9}\)

(1) the circle has a radius of 2
--> \(AB = 4\)
--> \(AC = \sqrt{4^2 - 9} = \sqrt{7}\)
--> Area of square = \(AC^2 = 7\) --> Sufficient

(2) angle ACB = 90°
This is the property of triangle insid a semi-circle
--> Nothing can be said about the value of side AC --> Insufficient

IMO Option A
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Re: In the diagram above, O is the center of the circle and ACDE is a squa   [#permalink] 16 Oct 2019, 01:20
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In the diagram above, O is the center of the circle and ACDE is a squa

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