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17 Jul 2017, 23:28
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Difficulty:
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56% (02:49) correct
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based on 91
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In the diagram below, P = g + c − e and Q = a + f . What is the value of (P + Q)?
(1) BC = CD = DB = DE
(2) AB = 1/2*AE
2017-07-18_1026.png [ 10.98 KiB | Viewed 2723 times ]
(1) BC = CD = DB = DE
(2) AB = 1/2*AE
Attachment:
2017-07-18_1026.png [ 10.98 KiB | Viewed 2723 times ]
17 Jul 2017, 23:49
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Given : P = g + c − e and Q = a + f .
We have been asked to find the value of (P + Q)
1. BC = CD = DB = DE
From the following information, Triangle BCD is equilateral.
Hence Angle BCD = c = g = 60 degree
Angle BDE = 180 - 60 = 120(Since angle in a straight line is 180)
In Triangle BDE, Angle DBE = e = 30 degree
Angle ABE = 180 - 60 - 30 = 90 degree
Therefore, Q = a+f = 90 degree(since sum of angles in a triangle is 90 degree)
Also P = 120 - 30 = 90 degree. We can arrive at an unique value of P + Q = 180 degree(Sufficient)
2. AB = 1/2*AE
Knowing the relationship between AB and AE is not enough to figure the value of angles P,Q.
Insufficient(Option A)
We have been asked to find the value of (P + Q)
1. BC = CD = DB = DE
From the following information, Triangle BCD is equilateral.
Hence Angle BCD = c = g = 60 degree
Angle BDE = 180 - 60 = 120(Since angle in a straight line is 180)
In Triangle BDE, Angle DBE = e = 30 degree
Angle ABE = 180 - 60 - 30 = 90 degree
Therefore, Q = a+f = 90 degree(since sum of angles in a triangle is 90 degree)
Also P = 120 - 30 = 90 degree. We can arrive at an unique value of P + Q = 180 degree(Sufficient)
2. AB = 1/2*AE
Knowing the relationship between AB and AE is not enough to figure the value of angles P,Q.
Insufficient(Option A)
18 Jul 2017, 07:14
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pushpitkc
Given : P = g + c − e and Q = a + f .
We have been asked to find the value of (P + Q)
1. BC = CD = DB = DE
From the following information, Triangle BCD is equilateral.
Hence Angle BCD = c = g = 60 degree
Angle BDE = 180 - 60 = 120(Since angle in a straight line is 180)
In Triangle BDE, Angle DBE = e = 30 degree
Angle ABE = 180 - 60 - 30 = 90 degree
Therefore, Q = a+f = 90 degree(since sum of angles in a triangle is 90 degree)
Also P = 120 - 30 = 90 degree. We can arrive at an unique value of P + Q = 180 degree(Sufficient)
2. AB = 1/2*AE
Knowing the relationship between AB and AE is not enough to figure the value of angles P,Q.
Insufficient(Option A)
We have been asked to find the value of (P + Q)
1. BC = CD = DB = DE
From the following information, Triangle BCD is equilateral.
Hence Angle BCD = c = g = 60 degree
Angle BDE = 180 - 60 = 120(Since angle in a straight line is 180)
In Triangle BDE, Angle DBE = e = 30 degree
Angle ABE = 180 - 60 - 30 = 90 degree
Therefore, Q = a+f = 90 degree(since sum of angles in a triangle is 90 degree)
Also P = 120 - 30 = 90 degree. We can arrive at an unique value of P + Q = 180 degree(Sufficient)
2. AB = 1/2*AE
Knowing the relationship between AB and AE is not enough to figure the value of angles P,Q.
Insufficient(Option A)
How you came to this conclusion.
In Triangle BDE, Angle DBE = e = 30 degree
I marked C as an answer
