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Updated on: 22 Jul 2019, 06:24
Originally posted by Bunuel on 02 Apr 2019, 23:34.
Last edited by Sajjad1994 on 22 Jul 2019, 06:24, edited 1 time in total.
Last edited by Sajjad1994 on 22 Jul 2019, 06:24, edited 1 time in total.
Added Source.
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
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Question Stats:
78% (02:18) correct
22%
(02:16)
wrong
based on 152
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In the figure, ABCD is a square and BCP is an equilateral triangle. What is the measure of x ?
(A) 7.5
(B) 15
(C) 30
(D) 45
(E) 60
Source: Nova GMAT
Difficulty Level: 600
Difficulty Level: 600
Attachment:
#GREpracticequestion In the figure, ABCD is a square.jpg [ 31.21 KiB | Viewed 8456 times ]
04 Apr 2019, 18:33
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Bunuel
In the figure, ABCD is a square and BCP is an equilateral triangle. What is the measure of x ?
(A) 7.5
(B) 15
(C) 30
(D) 45
(E) 60
Attachment:
#GREpracticequestion In the figure, ABCD is a square.jpg
Since PC = DC, we see that triangle PCD is an isosceles triangle. We see that angle PCD = 60 + 90 = 150 degrees. Using triangle PCD, we have:
2y + 150 = 180
2y = 30
y = 15
So angle DPC = 15 degrees, and we can see that angle BPA = 15 degrees. Since angle BPC = 60 degrees, then angle APD, or x, is 60 - 2(15) = 30 degrees.
Answer: C
03 Apr 2019, 07:03
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Bunuel
In the figure, ABCD is a square and BCP is an equilateral triangle. What is the measure of x ?
(A) 7.5
(B) 15
(C) 30
(D) 45
(E) 60
Attachment:
#GREpracticequestion In the figure, ABCD is a square.jpg
solve
∆ADP
90-y+90-y+x=180
or say x= 2y
plugin given options
starting x= 30
so y=15
so
75+75+30 = 180
sufficient
IMO C
