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Re: In the figure above, what is the length of PQ times the length of RS? [#permalink]
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sandeepmanocha wrote:
Bunuel wrote:

In the figure above, what is the length of PQ times the length of RS?

(1) The length of PQ is 5.
(2) The length of QR times the length of PR is equal to 12.

Attachment:
PR-B3-07.JPG


From Diagram it is clear that it is a Right Angled Triangle - so
1) PQ = 5, so it will become 3,4,5 Triangle, does not matter which one is 3 or 4, because what I need is Area
Area = 1/2 * 3 * 4 = 6
Now Area Using PQ as Base = 1/2*PQ*RS = 6 = > PQ.RS = 12 (Sufficient)

2) It says QR.PR = 12, which could be 3*4 or 2*6, All we know one of them is acting as the Height. So
QR.PR = 2*Area (Sufficient)

We need PQ.RS = 2 * Area, because RS is Perpendicular to PQ
so PQ*RS = QR*RS

Answer: D


Hi sandeepmanocha
Just because length of hypotenuse is 5 , the other 2 sides need not be 3 and 4 . The sides need not be a Pythagorean triple .
For example,
If PR and QR are \(\sqrt{(10)}\)and \(\sqrt{(15)}\) , then
10 + 15 = 5^2 = 25
Area = (1/2)*[ \(\sqrt{(10)}\) * \(\sqrt{(15)}\) ]
= (1/2) *\(\sqrt{(150)}\)
= (1/2) * 5 * \(\sqrt{(6)}\)
= 6.12 , which is not equal to 6
So statement 1 will not be sufficient.

Hope it helps !! :)
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Re: In the figure above, what is the length of PQ times the length of RS? [#permalink]
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Skywalker18 wrote:
sandeepmanocha wrote:
Bunuel wrote:

In the figure above, what is the length of PQ times the length of RS?

(1) The length of PQ is 5.
(2) The length of QR times the length of PR is equal to 12.

Attachment:
PR-B3-07.JPG


From Diagram it is clear that it is a Right Angled Triangle - so
1) PQ = 5, so it will become 3,4,5 Triangle, does not matter which one is 3 or 4, because what I need is Area
Area = 1/2 * 3 * 4 = 6
Now Area Using PQ as Base = 1/2*PQ*RS = 6 = > PQ.RS = 12 (Sufficient)

2) It says QR.PR = 12, which could be 3*4 or 2*6, All we know one of them is acting as the Height. So
QR.PR = 2*Area (Sufficient)

We need PQ.RS = 2 * Area, because RS is Perpendicular to PQ
so PQ*RS = QR*RS

Answer: D


Hi sandeepmanocha
Just because length of hypotenuse is 5 , the other 2 sides need not be 3 and 4 . The sides need not be a Pythagorean triple .
For example,
If PR and QR are \(\sqrt{(10)}\)and \(\sqrt{(15)}\) , then
10 + 15 = 5^2 = 25
Area = (1/2)*[ \(\sqrt{(10)}\) * \(\sqrt{(15)}\) ]
= (1/2) *\(\sqrt{(150)}\)
= (1/2) * 5 * \(\sqrt{(6)}\)
= 6.12 , which is not equal to 6
So statement 1 will not be sufficient.

Hope it helps !! :)



It surely does. I think I imagined that they are all Integers :(
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Re: In the figure above, what is the length of PQ times the length of RS? [#permalink]
Cant we use RS=PQ/2 ?
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Re: In the figure above, what is the length of PQ times the length of RS? [#permalink]
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mahe wrote:
Cant we use RS=PQ/2 ?


No. In a right triangle the height to the hypotenuse is half the hypotenuse only if the triangle is isosceles.

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Hope it helps.
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Re: In the figure above, what is the length of PQ times the length of RS? [#permalink]
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Bunuel wrote:

In the figure above, what is the length of PQ times the length of RS?

(1) The length of PQ is 5.
(2) The length of QR times the length of PR is equal to 12.

Attachment:
PR-B3-07.JPG


From the figure, Triangle PQR is similar to Triangle RSP. So, we have
\(\frac{QR}{RS} = \frac{PQ}{PR} = \frac{PR}{SP}\)

Statement I:
\(PQ = 5\). We need one more side length to find RS. So, Insufficient.

Statement II:

\(QR * PR = 12\)... From the above Similar Property we have, \(QR * PR = PQ * RS = 12\)

So, sufficient.
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Re: In the figure above, what is the length of PQ times the length of RS? [#permalink]
Bunuel wrote:

In the figure above, what is the length of PQ times the length of RS?

(1) The length of PQ is 5.
(2) The length of QR times the length of PR is equal to 12.

Attachment:
PR-B3-07.JPG



When can we safely say that the given line RS is a median to the hypotenuse?
I thought that RS is a median to the hypotenuse and thus is half of PQ.

Please help.
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Re: In the figure above, what is the length of PQ times the length of RS? [#permalink]
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