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In the figure above, what is the length of PQ times the length of RS?

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In the figure above, what is the length of PQ times the length of RS?  [#permalink]

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New post 20 Nov 2015, 00:53
1
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A
B
C
D
E

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Question Stats:

53% (01:42) correct 47% (02:01) wrong based on 139 sessions

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Re: In the figure above, what is the length of PQ times the length of RS?  [#permalink]

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New post 20 Nov 2015, 01:12
2
We need to find
PQ*RS =
1. PQ=5
We have no information about RS .
Not sufficient.

2.
QR*PR = 12
Area of triangle PQR = (1/2)* QR * PR
Also , Area of triangle PQR = (1/2)* PQ*RS
=> QR * PR = PQ*RS
Sufficient

Answer B
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Re: In the figure above, what is the length of PQ times the length of RS?  [#permalink]

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New post 20 Nov 2015, 09:31
Bunuel wrote:
Image
In the figure above, what is the length of PQ times the length of RS?

(1) The length of PQ is 5.
(2) The length of QR times the length of PR is equal to 12.

Attachment:
PR-B3-07.JPG


From Diagram it is clear that it is a Right Angled Triangle - so
1) PQ = 5, so it will become 3,4,5 Triangle, does not matter which one is 3 or 4, because what I need is Area
Area = 1/2 * 3 * 4 = 6
Now Area Using PQ as Base = 1/2*PQ*RS = 6 = > PQ.RS = 12 (Sufficient)

2) It says QR.PR = 12, which could be 3*4 or 2*6, All we know one of them is acting as the Height. So
QR.PR = 2*Area (Sufficient)

We need PQ.RS = 2 * Area, because RS is Perpendicular to PQ
so PQ*RS = QR*RS

Answer: D
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Re: In the figure above, what is the length of PQ times the length of RS?  [#permalink]

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New post 20 Nov 2015, 11:45
1
sandeepmanocha wrote:
Bunuel wrote:
Image
In the figure above, what is the length of PQ times the length of RS?

(1) The length of PQ is 5.
(2) The length of QR times the length of PR is equal to 12.

Attachment:
PR-B3-07.JPG


From Diagram it is clear that it is a Right Angled Triangle - so
1) PQ = 5, so it will become 3,4,5 Triangle, does not matter which one is 3 or 4, because what I need is Area
Area = 1/2 * 3 * 4 = 6
Now Area Using PQ as Base = 1/2*PQ*RS = 6 = > PQ.RS = 12 (Sufficient)

2) It says QR.PR = 12, which could be 3*4 or 2*6, All we know one of them is acting as the Height. So
QR.PR = 2*Area (Sufficient)

We need PQ.RS = 2 * Area, because RS is Perpendicular to PQ
so PQ*RS = QR*RS

Answer: D


Hi sandeepmanocha
Just because length of hypotenuse is 5 , the other 2 sides need not be 3 and 4 . The sides need not be a Pythagorean triple .
For example,
If PR and QR are \(\sqrt{(10)}\)and \(\sqrt{(15)}\) , then
10 + 15 = 5^2 = 25
Area = (1/2)*[ \(\sqrt{(10)}\) * \(\sqrt{(15)}\) ]
= (1/2) *\(\sqrt{(150)}\)
= (1/2) * 5 * \(\sqrt{(6)}\)
= 6.12 , which is not equal to 6
So statement 1 will not be sufficient.

Hope it helps !! :)
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Re: In the figure above, what is the length of PQ times the length of RS?  [#permalink]

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New post 21 Nov 2015, 12:46
Skywalker18 wrote:
sandeepmanocha wrote:
Bunuel wrote:
Image
In the figure above, what is the length of PQ times the length of RS?

(1) The length of PQ is 5.
(2) The length of QR times the length of PR is equal to 12.

Attachment:
PR-B3-07.JPG


From Diagram it is clear that it is a Right Angled Triangle - so
1) PQ = 5, so it will become 3,4,5 Triangle, does not matter which one is 3 or 4, because what I need is Area
Area = 1/2 * 3 * 4 = 6
Now Area Using PQ as Base = 1/2*PQ*RS = 6 = > PQ.RS = 12 (Sufficient)

2) It says QR.PR = 12, which could be 3*4 or 2*6, All we know one of them is acting as the Height. So
QR.PR = 2*Area (Sufficient)

We need PQ.RS = 2 * Area, because RS is Perpendicular to PQ
so PQ*RS = QR*RS

Answer: D


Hi sandeepmanocha
Just because length of hypotenuse is 5 , the other 2 sides need not be 3 and 4 . The sides need not be a Pythagorean triple .
For example,
If PR and QR are \(\sqrt{(10)}\)and \(\sqrt{(15)}\) , then
10 + 15 = 5^2 = 25
Area = (1/2)*[ \(\sqrt{(10)}\) * \(\sqrt{(15)}\) ]
= (1/2) *\(\sqrt{(150)}\)
= (1/2) * 5 * \(\sqrt{(6)}\)
= 6.12 , which is not equal to 6
So statement 1 will not be sufficient.

Hope it helps !! :)



It surely does. I think I imagined that they are all Integers :(
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Re: In the figure above, what is the length of PQ times the length of RS?  [#permalink]

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New post 29 Jan 2018, 19:52
Cant we use RS=PQ/2 ?
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Re: In the figure above, what is the length of PQ times the length of RS?  [#permalink]

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New post 29 Jan 2018, 20:55
mahe wrote:
Cant we use RS=PQ/2 ?


No. In a right triangle the height to the hypotenuse is half the hypotenuse only if the triangle is isosceles.

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Hope it helps.
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Re: In the figure above, what is the length of PQ times the length of RS?  [#permalink]

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New post 01 Feb 2018, 01:13
1
Bunuel wrote:
Image
In the figure above, what is the length of PQ times the length of RS?

(1) The length of PQ is 5.
(2) The length of QR times the length of PR is equal to 12.

Attachment:
PR-B3-07.JPG


From the figure, Triangle PQR is similar to Triangle RSP. So, we have
\(\frac{QR}{RS} = \frac{PQ}{PR} = \frac{PR}{SP}\)

Statement I:
\(PQ = 5\). We need one more side length to find RS. So, Insufficient.

Statement II:

\(QR * PR = 12\)... From the above Similar Property we have, \(QR * PR = PQ * RS = 12\)

So, sufficient.
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Re: In the figure above, what is the length of PQ times the length of RS?  [#permalink]

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Re: In the figure above, what is the length of PQ times the length of RS?   [#permalink] 02 May 2019, 09:40
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