sandeepmanocha wrote:
Bunuel wrote:
In the figure above, what is the length of PQ times the length of RS?
(1) The length of PQ is 5.
(2) The length of QR times the length of PR is equal to 12.
From Diagram it is clear that it is a Right Angled Triangle - so
1) PQ = 5, so it will become 3,4,5 Triangle, does not matter which one is 3 or 4, because what I need is Area
Area = 1/2 * 3 * 4 = 6
Now Area Using PQ as Base = 1/2*PQ*RS = 6 = > PQ.RS = 12 (Sufficient)
2) It says QR.PR = 12, which could be 3*4 or 2*6, All we know one of them is acting as the Height. So
QR.PR = 2*Area (Sufficient)
We need PQ.RS = 2 * Area, because RS is Perpendicular to PQ
so PQ*RS = QR*RS
Answer: D
Hi
sandeepmanochaJust because length of hypotenuse is 5 , the other 2 sides need not be 3 and 4 . The sides need not be a Pythagorean triple .
For example,
If PR and QR are \(\sqrt{(10)}\)and \(\sqrt{(15)}\) , then
10 + 15 = 5^2 = 25
Area = (1/2)*[ \(\sqrt{(10)}\) * \(\sqrt{(15)}\) ]
= (1/2) *\(\sqrt{(150)}\)
= (1/2) * 5 * \(\sqrt{(6)}\)
= 6.12 , which is not equal to 6
So statement 1 will not be sufficient.
Hope it helps !!
_________________
When everything seems to be going against you, remember that the airplane takes off against the wind, not with it. - Henry Ford
The Moment You Think About Giving Up, Think Of The Reason Why You Held On So Long