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In the figure above, if the area of square region WXYZ is equal to the

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In the figure above, if the area of square region WXYZ is equal to the [#permalink]

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New post 20 Sep 2017, 01:58
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In the figure above, if the area of square region WXYZ is equal to the area of the triangular region RST, then RT =

(A) 2
(B) 24/9
(C) 4
(D) 48/9
(E) 8

Attachment:
2017-09-20_1020_002.png
2017-09-20_1020_002.png [ 7.81 KiB | Viewed 673 times ]

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Re: In the figure above, if the area of square region WXYZ is equal to the [#permalink]

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New post 20 Sep 2017, 05:04
Bunuel wrote:
Image
In the figure above, if the area of square region WXYZ is equal to the area of the triangular region RST, then RT =

(A) 2
(B) 24/9
(C) 4
(D) 48/9
(E) 8

Attachment:
2017-09-20_1020_002.png


Area of the square = Side^2 = 6^2 = 36
Area of triangle = 1/2 x RT x 9 = 36
Hence RT = 8
Answer E

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Re: In the figure above, if the area of square region WXYZ is equal to the [#permalink]

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New post 20 Sep 2017, 05:04
Bunuel wrote:
Image
In the figure above, if the area of square region WXYZ is equal to the area of the triangular region RST, then RT =

(A) 2
(B) 24/9
(C) 4
(D) 48/9
(E) 8

Attachment:
2017-09-20_1020_002.png


Area of triangle RST = Area of square WXYZ = 6^2 = 36
=> 1/2 * height * base = 36
=> height * base = 72
=> base = 72/height = 72/9 = 8

Answer E
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Re: In the figure above, if the area of square region WXYZ is equal to the [#permalink]

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New post 25 Sep 2017, 18:06
Bunuel wrote:
Image
In the figure above, if the area of square region WXYZ is equal to the area of the triangular region RST, then RT =

(A) 2
(B) 24/9
(C) 4
(D) 48/9
(E) 8

Attachment:
2017-09-20_1020_002.png


The area of a square is s^2, where s = a side of the square. The area of a triangle is (½)bh, where b and h are the base and height of the triangle, respectively. We can let RT = b and create the following equation:

6 x 6 = (1/2) x b x 9

72 = 9b

8 = b

Answer: E
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Re: In the figure above, if the area of square region WXYZ is equal to the   [#permalink] 25 Sep 2017, 18:06
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