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13 Aug 2014, 15:55
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
53% (01:47) correct
47%
(02:12)
wrong
based on 115
sessions
History
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mahendru1992
Dear mahendru1992,
I'm happy to help with this.
Statement #1: well, with this, we know the x-coordinate of the first point is 1. Because it's drawn in Quadrant III, I'm going to assume you actually meant -1, but it doesn't really matter. The y-coordinate of the second point is 3. Well, that leaves the y-coordinate of the first point and the x-coordinate of the second point up for grabs. We could have:
Attachment:
two possibilities for ABC.JPG [ 21.83 KiB | Viewed 4918 times ]
Statement #2: slope is a powerful piece of information!! See:
https://magoosh.com/gmat/2012/gmat-math ... x-y-plane/
This means
4/5 = rise/run = AC/BC
BC*(4/5) = AC
Since all these numbers are positive, we know that BC must be bigger.
This statement, alone and by itself, is sufficient.
Answer = (B)
Does all this make sense?
Mike
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
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17 Aug 2014, 12:42
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mikemcgarry
Hello.. you have switched B & C in your diagram. Will it affect the solution?
Also, as per MGMAT Geometry book, slope = rise/run = (y2-y1)/(x2-x1)
How does that relate to AC & BC. Please explain.
17 Aug 2014, 13:25
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apsForGmat
Yes, I did make that mistake in the diagram, but you will notice that all my equations and conclusions are based on the original diagram.
Do you understand the statement "slope = rise/run"? Do you understand what "rise" and "run" mean? The rise is the vertical distance between the two points, the distance from one y-height to the other. In the original diagram, the rise = AC. The run is horizontal separation between the two points, the horizontal distance between the x-line of one point and the x-line of the other. In the original diagram, run = BC. Thus, rise/run = AC/BC.
I suggest you read the blog article on slope I gave in the previous post.
Does this make sense?
Mike
. Thanks a lot 
