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mikemcgarry
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In the figure above, segments AC and BC are each parallel 13 Aug 2014, 15:55
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65% (hard)

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53% (01:47) correct 47% (02:12) wrong based on 115 sessions

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mahendru1992
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In the figure above, segments AC and BC are each parallel to one of the rectangular coordinate axes. Is the length of AC greater than the length of BC?

(1) m = 1 and k = 3
(2) The slope of segment AB is 4/5
Show more
Dear mahendru1992,
I'm happy to help with this. :-)

Statement #1: well, with this, we know the x-coordinate of the first point is 1. Because it's drawn in Quadrant III, I'm going to assume you actually meant -1, but it doesn't really matter. The y-coordinate of the second point is 3. Well, that leaves the y-coordinate of the first point and the x-coordinate of the second point up for grabs. We could have:
Attachment:
two possibilities for ABC.JPG
two possibilities for ABC.JPG [ 21.83 KiB | Viewed 4818 times ]
With this information, the inequality could go either way. This statement, alone and by itself, is insufficient.

Statement #2: slope is a powerful piece of information!! See:
https://magoosh.com/gmat/2012/gmat-math ... x-y-plane/
This means
4/5 = rise/run = AC/BC
BC*(4/5) = AC
Since all these numbers are positive, we know that BC must be bigger.
This statement, alone and by itself, is sufficient.

Answer = (B)

Does all this make sense?
Mike :-)

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apsForGmat
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In the figure above, segments AC and BC are each parallel 17 Aug 2014, 12:42
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mikemcgarry
mahendru1992
Attachment:
Untitled.png
In the figure above, segments AC and BC are each parallel to one of the rectangular coordinate axes. Is the length of AC greater than the length of BC?

(1) m = 1 and k = 3
(2) The slope of segment AB is 4/5
Dear mahendru1992,
I'm happy to help with this. :-)

Statement #1: well, with this, we know the x-coordinate of the first point is 1. Because it's drawn in Quadrant III, I'm going to assume you actually meant -1, but it doesn't really matter. The y-coordinate of the second point is 3. Well, that leaves the y-coordinate of the first point and the x-coordinate of the second point up for grabs. We could have:
Attachment:
two possibilities for ABC.JPG
With this information, the inequality could go either way. This statement, alone and by itself, is insufficient.

Statement #2: slope is a powerful piece of information!! See:
https://magoosh.com/gmat/2012/gmat-math- ... x-y-plane/
This means
4/5 = rise/run = AC/BC
BC*(4/5) = AC
Since all these numbers are positive, we know that BC must be bigger.
This statement, alone and by itself, is sufficient.

Answer = (B)

Does all this make sense?
Mike :-)
Show more

Hello.. you have switched B & C in your diagram. Will it affect the solution?
Also, as per MGMAT Geometry book, slope = rise/run = (y2-y1)/(x2-x1)
How does that relate to AC & BC. Please explain.
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In the figure above, segments AC and BC are each parallel 17 Aug 2014, 13:25
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apsForGmat
Hello.. you have switched B & C in your diagram. Will it affect the solution?
Also, as per MGMAT Geometry book, slope = rise/run = (y2-y1)/(x2-x1)
How does that relate to AC & BC. Please explain.
Show more
Yes, I did make that mistake in the diagram, but you will notice that all my equations and conclusions are based on the original diagram.

Do you understand the statement "slope = rise/run"? Do you understand what "rise" and "run" mean? The rise is the vertical distance between the two points, the distance from one y-height to the other. In the original diagram, the rise = AC. The run is horizontal separation between the two points, the horizontal distance between the x-line of one point and the x-line of the other. In the original diagram, run = BC. Thus, rise/run = AC/BC.

I suggest you read the blog article on slope I gave in the previous post.

Does this make sense?
Mike :-)
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In the figure above, segments AC and BC are each parallel 17 Aug 2014, 15:07
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mikemcgarry
mahendru1992
Attachment:
Untitled.png
In the figure above, segments AC and BC are each parallel to one of the rectangular coordinate axes. Is the length of AC greater than the length of BC?

(1) m = 1 and k = 3
(2) The slope of segment AB is 4/5
Dear mahendru1992,
I'm happy to help with this. :-)

Statement #1: well, with this, we know the x-coordinate of the first point is 1. Because it's drawn in Quadrant III, I'm going to assume you actually meant -1, but it doesn't really matter. The y-coordinate of the second point is 3. Well, that leaves the y-coordinate of the first point and the x-coordinate of the second point up for grabs. We could have:
Attachment:
two possibilities for ABC.JPG
With this information, the inequality could go either way. This statement, alone and by itself, is insufficient.

Statement #2: slope is a powerful piece of information!! See:
https://magoosh.com/gmat/2012/gmat-math- ... x-y-plane/
This means
4/5 = rise/run = AC/BC
BC*(4/5) = AC
Since all these numbers are positive, we know that BC must be bigger.
This statement, alone and by itself, is sufficient.

Answer = (B)

Does all this make sense?
Mike :-)
Show more

I though the answer must be C before I read your exp :( . Thanks a lot
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In the figure above, segments AC and BC are each parallel 17 Jan 2020, 21:45
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mahendru1992
Attachment:
Untitled.png
In the figure above, segments AC and BC are each parallel to one of the rectangular coordinate axes. Is the length of AC greater than the length of BC?

(1) m = 1 and k = 3
(2) The slope of segment AB is 4/5
Show more
AC is the distance in y direction and BC is the distance in x direction

(1) value of one of the coordinate is given of A and B, which is not sufficient to calculate distance in x direction and y direction
Insufficient

(2) Slope = (y2 - y1)/(x2- x1) = distance in y-direction / x-direction = 4/5
Distance is y-direction is less than distance in x-direction

B is correct

Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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