Last visit was: 15 Dec 2024, 08:00 It is currently 15 Dec 2024, 08:00
Home
GMAT
Messages
Tests
Schools
Reviews
Social
Chat
My Profile
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
User avatar
mikemcgarry
User avatar
Magoosh GMAT Instructor
Joined: 28 Dec 2011
Last visit: 06 Aug 2018
Posts: 4,485
Own Kudos:
29,392
 []
Given Kudos: 130
Expert reply
Posts: 4,485
Kudos: 29,392
 []
In the figure above, segments AC and BC are each parallel 13 Aug 2014, 15:55
2
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

65% (hard)

Question Stats:

52% (01:51) correct 48% (02:12) wrong based on 112 sessions

History

Date
Time
Result
Not Attempted Yet
mahendru1992
Attachment:
The attachment Untitled.png is no longer available
In the figure above, segments AC and BC are each parallel to one of the rectangular coordinate axes. Is the length of AC greater than the length of BC?

(1) m = 1 and k = 3
(2) The slope of segment AB is 4/5
Dear mahendru1992,
I'm happy to help with this. :-)

Statement #1: well, with this, we know the x-coordinate of the first point is 1. Because it's drawn in Quadrant III, I'm going to assume you actually meant -1, but it doesn't really matter. The y-coordinate of the second point is 3. Well, that leaves the y-coordinate of the first point and the x-coordinate of the second point up for grabs. We could have:
Attachment:
two possibilities for ABC.JPG
two possibilities for ABC.JPG [ 21.83 KiB | Viewed 4326 times ]
With this information, the inequality could go either way. This statement, alone and by itself, is insufficient.

Statement #2: slope is a powerful piece of information!! See:
https://magoosh.com/gmat/2012/gmat-math- ... x-y-plane/
This means
4/5 = rise/run = AC/BC
BC*(4/5) = AC
Since all these numbers are positive, we know that BC must be bigger.
This statement, alone and by itself, is sufficient.

Answer = (B)

Does all this make sense?
Mike :-)
ShowHide Answer
Official Answer
B
User avatar
apsForGmat
User avatar
Joined: 21 Jul 2014
Last visit: 01 Aug 2015
Posts: 12
Own Kudos:
2
Given Kudos: 13
Posts: 12
Kudos: 2
In the figure above, segments AC and BC are each parallel 17 Aug 2014, 12:42
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mikemcgarry
mahendru1992
Attachment:
Untitled.png
In the figure above, segments AC and BC are each parallel to one of the rectangular coordinate axes. Is the length of AC greater than the length of BC?

(1) m = 1 and k = 3
(2) The slope of segment AB is 4/5
Dear mahendru1992,
I'm happy to help with this. :-)

Statement #1: well, with this, we know the x-coordinate of the first point is 1. Because it's drawn in Quadrant III, I'm going to assume you actually meant -1, but it doesn't really matter. The y-coordinate of the second point is 3. Well, that leaves the y-coordinate of the first point and the x-coordinate of the second point up for grabs. We could have:
Attachment:
two possibilities for ABC.JPG
With this information, the inequality could go either way. This statement, alone and by itself, is insufficient.

Statement #2: slope is a powerful piece of information!! See:
https://magoosh.com/gmat/2012/gmat-math- ... x-y-plane/
This means
4/5 = rise/run = AC/BC
BC*(4/5) = AC
Since all these numbers are positive, we know that BC must be bigger.
This statement, alone and by itself, is sufficient.

Answer = (B)

Does all this make sense?
Mike :-)

Hello.. you have switched B & C in your diagram. Will it affect the solution?
Also, as per MGMAT Geometry book, slope = rise/run = (y2-y1)/(x2-x1)
How does that relate to AC & BC. Please explain.
User avatar
mikemcgarry
User avatar
Magoosh GMAT Instructor
Joined: 28 Dec 2011
Last visit: 06 Aug 2018
Posts: 4,485
Own Kudos:
29,392
 []
Given Kudos: 130
Expert reply
Posts: 4,485
Kudos: 29,392
 []
In the figure above, segments AC and BC are each parallel 17 Aug 2014, 13:25
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
apsForGmat
Hello.. you have switched B & C in your diagram. Will it affect the solution?
Also, as per MGMAT Geometry book, slope = rise/run = (y2-y1)/(x2-x1)
How does that relate to AC & BC. Please explain.
Yes, I did make that mistake in the diagram, but you will notice that all my equations and conclusions are based on the original diagram.

Do you understand the statement "slope = rise/run"? Do you understand what "rise" and "run" mean? The rise is the vertical distance between the two points, the distance from one y-height to the other. In the original diagram, the rise = AC. The run is horizontal separation between the two points, the horizontal distance between the x-line of one point and the x-line of the other. In the original diagram, run = BC. Thus, rise/run = AC/BC.

I suggest you read the blog article on slope I gave in the previous post.

Does this make sense?
Mike :-)
User avatar
vad3tha
User avatar
Joined: 22 Feb 2009
Last visit: 15 Dec 2023
Posts: 108
Own Kudos:
551
Given Kudos: 148
Posts: 108
Kudos: 551
In the figure above, segments AC and BC are each parallel 17 Aug 2014, 15:07
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mikemcgarry
mahendru1992
Attachment:
Untitled.png
In the figure above, segments AC and BC are each parallel to one of the rectangular coordinate axes. Is the length of AC greater than the length of BC?

(1) m = 1 and k = 3
(2) The slope of segment AB is 4/5
Dear mahendru1992,
I'm happy to help with this. :-)

Statement #1: well, with this, we know the x-coordinate of the first point is 1. Because it's drawn in Quadrant III, I'm going to assume you actually meant -1, but it doesn't really matter. The y-coordinate of the second point is 3. Well, that leaves the y-coordinate of the first point and the x-coordinate of the second point up for grabs. We could have:
Attachment:
two possibilities for ABC.JPG
With this information, the inequality could go either way. This statement, alone and by itself, is insufficient.

Statement #2: slope is a powerful piece of information!! See:
https://magoosh.com/gmat/2012/gmat-math- ... x-y-plane/
This means
4/5 = rise/run = AC/BC
BC*(4/5) = AC
Since all these numbers are positive, we know that BC must be bigger.
This statement, alone and by itself, is sufficient.

Answer = (B)

Does all this make sense?
Mike :-)

I though the answer must be C before I read your exp :( . Thanks a lot
User avatar
QuantMadeEasy
User avatar
Joined: 28 Feb 2014
Last visit: 15 Dec 2024
Posts: 502
Own Kudos:
663
Given Kudos: 75
Location: India
Concentration: General Management, International Business
GPA: 3.97
WE:Engineering (Education)
Posts: 502
Kudos: 663
In the figure above, segments AC and BC are each parallel 17 Jan 2020, 21:45
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mahendru1992
Attachment:
Untitled.png
In the figure above, segments AC and BC are each parallel to one of the rectangular coordinate axes. Is the length of AC greater than the length of BC?

(1) m = 1 and k = 3
(2) The slope of segment AB is 4/5
AC is the distance in y direction and BC is the distance in x direction

(1) value of one of the coordinate is given of A and B, which is not sufficient to calculate distance in x direction and y direction
Insufficient

(2) Slope = (y2 - y1)/(x2- x1) = distance in y-direction / x-direction = 4/5
Distance is y-direction is less than distance in x-direction

B is correct
Moderator:
Bunuel
Math Expert
97883 posts