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In the figure, x + y =

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In the figure, x + y = [#permalink]

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In the figure, x + y =

(A) 60
(B) 135
(C) 165
(D) 195
(E) 220

[Reveal] Spoiler:
Attachment:
2017-09-20_1021_001.png
2017-09-20_1021_001.png [ 7.71 KiB | Viewed 484 times ]
[Reveal] Spoiler: OA

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Re: In the figure, x + y = [#permalink]

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New post 20 Sep 2017, 23:41
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The four lines form a quadrilateral
The two angles that lie of the same straight line as the angles given(135 and 60)
are \(180 - 135 = 45\) and \(180 - 60 = 120\) respectively.
The other two angles in the quadrilateral are 180 - x and 180 - y

The sum of the angles in a quadrilateral is 360 degree.

180 - x + 180 - y + 120 + 45 = 360
x+y = 165 degree(Option C)
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Re: In the figure, x + y = [#permalink]

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New post 21 Sep 2017, 09:33
In the given quadrilateral, sum of interior angles =180(n-2)=180x2=360
Sum of interior angles are (180-x)+(180-y)+(180-135)+(180-60)
=(180-x)+(180-y)+45+120=360
x+y=165
Answer C
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Re: In the figure, x + y = [#permalink]

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New post 25 Sep 2017, 15:35
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Bunuel wrote:
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In the figure, x + y =

(A) 60
(B) 135
(C) 165
(D) 195
(E) 220


Since the exterior angles of any polygon must sum to 360 degrees, we have:

x + y + 60 + 135 = 360

x + y = 165

Answer: C
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Re: In the figure, x + y =   [#permalink] 25 Sep 2017, 15:35
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