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pushpitkc
2y = 14+3x

y = \(\frac{{14+3x}}{2}\)

If x=2, y=10(a point in the first quadrant)
If x=-6,y=-2(a point in the third quadrant)
If x=-2,y-4(a point in the second quadrant)

But we are not able to come up with a point in the fourth quadrant, where the value of y is negatiave and x, positive (Option C)

How do we presume different values of x to get points on the quadrants?
How did you pick x=2,-6,-2?
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