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Updated on: 09 Jul 2016, 10:14
Originally posted by MathRevolution on 09 May 2016, 20:51.
Last edited by Kurtosis on 09 Jul 2016, 10:14, edited 1 time in total.
Last edited by Kurtosis on 09 Jul 2016, 10:14, edited 1 time in total.
Changed the OA
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
61% (01:34) correct
39%
(01:46)
wrong
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In x-y coordinates, A(0,3) and B (3,0) are given. Does A and B form the diameter of the circle?
1) A and B are on the circle.
2) The radius is√3
* A solution will be posted in two days.
1) A and B are on the circle.
2) The radius is√3
* A solution will be posted in two days.
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11 May 2016, 20:06
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The variables of circles in x-y coordinates are 3 (center and radii). In order to match the number of numbers to the number of equations, we need 3 equations. Since the condition 1) and the condition 2) each has 1 equation, there is high chance that E is the correct answer. Using both the condition 1) and the condition 2), since AB=2√3=diameter, the answer is always yes, and the condition is sufficient. Therefore, the correct answer is C.
- Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
- Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
31 May 2016, 22:26
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MathRev,
I'm not sure I follow your solution, please correct my reasoning:
If you assume an isosceles triangle, with height=length=3 then by x-x-x(radical(2)) convention then AB = 3(radical(2)). If AB was the diameter then radius = 3(radical(2)) / 2 which does not equal radical(3)
(1) obviously NS
(2) sufficient because of explanation above
I'm not sure I follow your solution, please correct my reasoning:
If you assume an isosceles triangle, with height=length=3 then by x-x-x(radical(2)) convention then AB = 3(radical(2)). If AB was the diameter then radius = 3(radical(2)) / 2 which does not equal radical(3)
(1) obviously NS
(2) sufficient because of explanation above
